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So, in the very first lecture (at the beginning), the professor has "find the tangent line to y = f(x) at P = (x0, y0). Can someone explain what this means exactly?
 one year ago
 one year ago
So, in the very first lecture (at the beginning), the professor has "find the tangent line to y = f(x) at P = (x0, y0). Can someone explain what this means exactly?
 one year ago
 one year ago

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NeemoBest ResponseYou've already chosen the best response.1
kk wait for about five minutes...I tried to draw it here ! but I couldn't
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
thanks neemo, so we're trying to solve for that point that coincided with the curve there?
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
i guess what i dont get is what does y = f(x) mean here
 one year ago

NeemoBest ResponseYou've already chosen the best response.1
exactly ! y=f(x) is an equation that "describes" the curve...
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
so theres the graph itself and the tangent line and we're trying to find a specific point on that tangent line?
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
also, does y = f(x) just mean that we can solve for y by applying some function to x?
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
cuz if i remember my basic algebra, i think we need the slope also, no? or is that assuming the function is providing those details?
 one year ago

NeemoBest ResponseYou've already chosen the best response.1
didn't get what you want to say ! x define y ...by y=f(x)....so sorry ; I didn't understand :( !
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
ok, sorry. think i overcomplicated it. the equation/notation makes sense to me, it just says find the y for the tangent line that hits the curve that has a point of x0, y0
 one year ago

NeemoBest ResponseYou've already chosen the best response.1
then; Y0=f(x0) or the point doesn't belong to the curve !
 one year ago

NeemoBest ResponseYou've already chosen the best response.1
kk now ! I understand ! yeaaah it's true...just notations...finding y=ax+b for the tangent line ! what I gave you ! It satisfies you !
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
So to summarize, it's asking to get the y for the tangent line that touches a curve with points (x0, y0)? Is that accurate?
 one year ago

JingleBellsBest ResponseYou've already chosen the best response.0
I hope I'm not butting in but you should try watching Highlights of Calculus with Prof Strang, I found it very useful for myself anyway: http://ocw.mit.edu/highschool/
 one year ago

levinotikBest ResponseYou've already chosen the best response.0
@JingleBells, if you are butting in (which i dont think you are) then I'm glad you did! I happened to already be in the middle of reading Strang's book so this is fantastic! Thanks a lot!
 one year ago

JingleBellsBest ResponseYou've already chosen the best response.0
I'm glad to be of help. I think Prof Strang is fantastic: he describes \[\Delta y/ \Delta x\]as 'short/short' and dy/dx as 'darn short/darn short'
 one year ago

LuvgunnBest ResponseYou've already chosen the best response.0
Hopefully it makes sense now that the proffesor was trying to tell us that derivatives or limits are the slope we need to find first for a given equation to solve or find the equation of a tangent line. Hope that makes sense?
 one year ago
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