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lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
what do you want to do with it?
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
solve for x
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
\[\sqrt 3 \tan (2x) = 0\] first step divide both sides by \(\sqrt{3}\) what do you get?
 2 years ago

y2o2 Group TitleBest ResponseYou've already chosen the best response.0
x = 0 or x = 180
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
so tan2x=1/sqrt(3)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
nope. \[\tan (2x) =\frac {0}{\sqrt3}\] now simplify this
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
haha..then you're right \[\tan(2x) =\frac{1}{\sqrt 3}\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
now second step. take the arctangent of both sides
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
ok so pi/6?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
remember that negative sign...and it's not yet over
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
how does the negative affect it?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
well it doesnt affect that much
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
how do you mean?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
dw:1342705038280:dw
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
oh ok so when you say take the arctangent, where do you go from there?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
so \[2x = \frac{\pi}{6}\] now you divide both sides by 2
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
ok so x= =pi/12
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
is this one of the answers?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
what do you mean?
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
well there are 4 values for x right?
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
because there was a 2 between the tan and the x, which compresses the tan graph
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
i cant remember that part...is it adding \(\pi\) or \(2\pi\)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
what do you mean 2 between tan and x..tan (2x)?
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
yeah, thats what i meant tan2x
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
i think its add pi
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
im not sure about this part so im gonna ask @amistre64 for some assistance. please come sir.
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
Thank you for your help so far!!
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
what does amistre64 say?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
i dont think he's coming yet...i tried tagging him to come here...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
let me call a different one..he might be afk
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
Thank you :)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
@apoorvk pls help
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.1
just add pi to the solution and it wont matter.
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
so 11pi/12?
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.1
yep i do think its another answer.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
thanks @vamgadu you saved me there heh
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
yes thank you! :)
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.1
its my pleasure @lgbasallote
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
however, in the back of my text book the answers are 5pi/12 11pi/12 17pi/12 and 23pi/12
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
and im wondering how my magic maths textbook got there
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
so we are going good with the 11pi/12 :D
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
and if pi is added again, we get 23pi/12 which is also good!
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
you're doing right. so is there a further problem?
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
well there are sposed to be 4 answers
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
then you add pi again
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
i have 2 :)
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.1
subtract a pi, if want int he interval, [2pi,2pi]
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
well i have 11pi/12 and 23pi/12
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.1
pi/12 and 13pi/12
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
so 11pi/12pi?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
pi/12  pi
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.3
11pi/12  pi is pi/12 (bringing you back to the orig thingy)
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
thats not one of the answers :?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
You started with 2x= pi/6 if we call 2x theta, we have 2 solutions: dw:1342706814544:dw and x is 5pi/12 and 11pi/12 now add pi to each value to get the other 2 solutions or , noting that 2x+pi divided by 2 is x+pi/2 , add multiplies of pi/2 to get all four solutions starting with pi/12 (which is 11pi/12 in the interval [0, 2pi] )
 2 years ago

amsterdam11 Group TitleBest ResponseYou've already chosen the best response.1
can this be done on a tan graph?
 2 years ago
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