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what do you want to do with it?

solve for x

\[\sqrt 3 \tan (2x) = 0\]
first step divide both sides by \(\sqrt{3}\) what do you get?

x = 0 or x = 180

so tan2x=-1/sqrt(3)

nope. \[\tan (2x) =\frac {0}{\sqrt3}\]
now simplify this

oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0

sorry!

haha..then you're right \[\tan(2x) =-\frac{1}{\sqrt 3}\]

now second step. take the arctangent of both sides

ok so pi/6?

remember that negative sign...and it's not yet over

how does the negative affect it?

well it doesnt affect that much

how do you mean?

|dw:1342705038280:dw|

oh ok so when you say take the arctangent, where do you go from there?

so \[2x = -\frac{\pi}{6}\]
now you divide both sides by 2

ok so x= =pi/12

-pi/12

yup

is this one of the answers?

what do you mean?

well there are 4 values for x right?

because there was a 2 between the tan and the x, which compresses the tan graph

i cant remember that part...is it adding \(\pi\) or \(2\pi\)

what do you mean 2 between tan and x..tan (2x)?

yeah, thats what i meant tan2x

i think its add pi

im not sure about this part so im gonna ask @amistre64 for some assistance. please come sir.

Thank you for your help so far!!

what does amistre64 say?

i dont think he's coming yet...i tried tagging him to come here...

let me call a different one..he might be afk

Thank you :)

@apoorvk pls help

just add pi to the solution and it wont matter.

so 11pi/12?

yep i do think its another answer.

thanks @vamgadu you saved me there heh

yes thank you! :)

its my pleasure @lgbasallote

however, in the back of my text book the answers are 5pi/12 11pi/12 17pi/12 and 23pi/12

and im wondering how my magic maths textbook got there

so we are going good with the 11pi/12 :D

and if pi is added again, we get 23pi/12 which is also good!

you're doing right. so is there a further problem?

well there are sposed to be 4 answers

then you add pi again

i have 2 :)

2?

subtract a pi, if want int he interval, [-2pi,2pi]

well i have 11pi/12 and 23pi/12

-pi/12 and -13pi/12

so 11pi/12-pi?

-pi/12 - pi

11pi/12 - pi is -pi/12 (bringing you back to the orig thingy)

thats not one of the answers :?

can this be done on a tan graph?