anonymous
  • anonymous
Could someone please help me with sqrt(3) tan2x=0
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

lgbasallote
  • lgbasallote
what do you want to do with it?
anonymous
  • anonymous
solve for x
lgbasallote
  • lgbasallote
\[\sqrt 3 \tan (2x) = 0\] first step divide both sides by \(\sqrt{3}\) what do you get?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

y2o2
  • y2o2
x = 0 or x = 180
anonymous
  • anonymous
so tan2x=-1/sqrt(3)
lgbasallote
  • lgbasallote
nope. \[\tan (2x) =\frac {0}{\sqrt3}\] now simplify this
anonymous
  • anonymous
oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0
anonymous
  • anonymous
sorry!
lgbasallote
  • lgbasallote
haha..then you're right \[\tan(2x) =-\frac{1}{\sqrt 3}\]
lgbasallote
  • lgbasallote
now second step. take the arctangent of both sides
anonymous
  • anonymous
ok so pi/6?
lgbasallote
  • lgbasallote
remember that negative sign...and it's not yet over
anonymous
  • anonymous
how does the negative affect it?
lgbasallote
  • lgbasallote
well it doesnt affect that much
anonymous
  • anonymous
how do you mean?
lgbasallote
  • lgbasallote
|dw:1342705038280:dw|
anonymous
  • anonymous
oh ok so when you say take the arctangent, where do you go from there?
lgbasallote
  • lgbasallote
so \[2x = -\frac{\pi}{6}\] now you divide both sides by 2
anonymous
  • anonymous
ok so x= =pi/12
anonymous
  • anonymous
-pi/12
lgbasallote
  • lgbasallote
yup
anonymous
  • anonymous
is this one of the answers?
lgbasallote
  • lgbasallote
what do you mean?
anonymous
  • anonymous
well there are 4 values for x right?
anonymous
  • anonymous
because there was a 2 between the tan and the x, which compresses the tan graph
lgbasallote
  • lgbasallote
i cant remember that part...is it adding \(\pi\) or \(2\pi\)
lgbasallote
  • lgbasallote
what do you mean 2 between tan and x..tan (2x)?
anonymous
  • anonymous
yeah, thats what i meant tan2x
anonymous
  • anonymous
i think its add pi
lgbasallote
  • lgbasallote
im not sure about this part so im gonna ask @amistre64 for some assistance. please come sir.
anonymous
  • anonymous
Thank you for your help so far!!
anonymous
  • anonymous
what does amistre64 say?
lgbasallote
  • lgbasallote
i dont think he's coming yet...i tried tagging him to come here...
lgbasallote
  • lgbasallote
let me call a different one..he might be afk
anonymous
  • anonymous
Thank you :)
lgbasallote
  • lgbasallote
@apoorvk pls help
anonymous
  • anonymous
just add pi to the solution and it wont matter.
anonymous
  • anonymous
so 11pi/12?
anonymous
  • anonymous
yep i do think its another answer.
lgbasallote
  • lgbasallote
thanks @vamgadu you saved me there heh
anonymous
  • anonymous
yes thank you! :)
anonymous
  • anonymous
its my pleasure @lgbasallote
anonymous
  • anonymous
however, in the back of my text book the answers are 5pi/12 11pi/12 17pi/12 and 23pi/12
anonymous
  • anonymous
and im wondering how my magic maths textbook got there
anonymous
  • anonymous
so we are going good with the 11pi/12 :D
anonymous
  • anonymous
and if pi is added again, we get 23pi/12 which is also good!
lgbasallote
  • lgbasallote
you're doing right. so is there a further problem?
anonymous
  • anonymous
well there are sposed to be 4 answers
lgbasallote
  • lgbasallote
then you add pi again
anonymous
  • anonymous
i have 2 :)
lgbasallote
  • lgbasallote
2?
anonymous
  • anonymous
subtract a pi, if want int he interval, [-2pi,2pi]
anonymous
  • anonymous
well i have 11pi/12 and 23pi/12
anonymous
  • anonymous
-pi/12 and -13pi/12
anonymous
  • anonymous
so 11pi/12-pi?
lgbasallote
  • lgbasallote
-pi/12 - pi
lgbasallote
  • lgbasallote
11pi/12 - pi is -pi/12 (bringing you back to the orig thingy)
anonymous
  • anonymous
thats not one of the answers :?
phi
  • phi
You started with 2x= -pi/6 if we call 2x theta, we have 2 solutions: |dw:1342706814544:dw| and x is 5pi/12 and 11pi/12 now add pi to each value to get the other 2 solutions or , noting that 2x+pi divided by 2 is x+pi/2 , add multiplies of pi/2 to get all four solutions starting with -pi/12 (which is 11pi/12 in the interval [0, 2pi] )
anonymous
  • anonymous
can this be done on a tan graph?

Looking for something else?

Not the answer you are looking for? Search for more explanations.