1. lgbasallote

what do you want to do with it?

2. amsterdam11

solve for x

3. lgbasallote

$\sqrt 3 \tan (2x) = 0$ first step divide both sides by $$\sqrt{3}$$ what do you get?

4. y2o2

x = 0 or x = 180

5. amsterdam11

so tan2x=-1/sqrt(3)

6. lgbasallote

nope. $\tan (2x) =\frac {0}{\sqrt3}$ now simplify this

7. amsterdam11

oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0

8. amsterdam11

sorry!

9. lgbasallote

haha..then you're right $\tan(2x) =-\frac{1}{\sqrt 3}$

10. lgbasallote

now second step. take the arctangent of both sides

11. amsterdam11

ok so pi/6?

12. lgbasallote

remember that negative sign...and it's not yet over

13. amsterdam11

how does the negative affect it?

14. lgbasallote

well it doesnt affect that much

15. amsterdam11

how do you mean?

16. lgbasallote

|dw:1342705038280:dw|

17. amsterdam11

oh ok so when you say take the arctangent, where do you go from there?

18. lgbasallote

so $2x = -\frac{\pi}{6}$ now you divide both sides by 2

19. amsterdam11

ok so x= =pi/12

20. amsterdam11

-pi/12

21. lgbasallote

yup

22. amsterdam11

is this one of the answers?

23. lgbasallote

what do you mean?

24. amsterdam11

well there are 4 values for x right?

25. amsterdam11

because there was a 2 between the tan and the x, which compresses the tan graph

26. lgbasallote

i cant remember that part...is it adding $$\pi$$ or $$2\pi$$

27. lgbasallote

what do you mean 2 between tan and x..tan (2x)?

28. amsterdam11

yeah, thats what i meant tan2x

29. amsterdam11

30. lgbasallote

31. amsterdam11

Thank you for your help so far!!

32. amsterdam11

what does amistre64 say?

33. lgbasallote

i dont think he's coming yet...i tried tagging him to come here...

34. lgbasallote

let me call a different one..he might be afk

35. amsterdam11

Thank you :)

36. lgbasallote

@apoorvk pls help

just add pi to the solution and it wont matter.

38. amsterdam11

so 11pi/12?

yep i do think its another answer.

40. lgbasallote

thanks @vamgadu you saved me there heh

41. amsterdam11

yes thank you! :)

its my pleasure @lgbasallote

43. amsterdam11

however, in the back of my text book the answers are 5pi/12 11pi/12 17pi/12 and 23pi/12

44. amsterdam11

and im wondering how my magic maths textbook got there

45. amsterdam11

so we are going good with the 11pi/12 :D

46. amsterdam11

and if pi is added again, we get 23pi/12 which is also good!

47. lgbasallote

you're doing right. so is there a further problem?

48. amsterdam11

well there are sposed to be 4 answers

49. lgbasallote

50. amsterdam11

i have 2 :)

51. lgbasallote

2?

subtract a pi, if want int he interval, [-2pi,2pi]

53. amsterdam11

well i have 11pi/12 and 23pi/12

-pi/12 and -13pi/12

55. amsterdam11

so 11pi/12-pi?

56. lgbasallote

-pi/12 - pi

57. lgbasallote

11pi/12 - pi is -pi/12 (bringing you back to the orig thingy)

58. amsterdam11

thats not one of the answers :?

59. phi

You started with 2x= -pi/6 if we call 2x theta, we have 2 solutions: |dw:1342706814544:dw| and x is 5pi/12 and 11pi/12 now add pi to each value to get the other 2 solutions or , noting that 2x+pi divided by 2 is x+pi/2 , add multiplies of pi/2 to get all four solutions starting with -pi/12 (which is 11pi/12 in the interval [0, 2pi] )

60. amsterdam11

can this be done on a tan graph?