Could someone please help me with sqrt(3) tan2x=0

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Could someone please help me with sqrt(3) tan2x=0

Mathematics
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what do you want to do with it?
solve for x
\[\sqrt 3 \tan (2x) = 0\] first step divide both sides by \(\sqrt{3}\) what do you get?

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Other answers:

x = 0 or x = 180
so tan2x=-1/sqrt(3)
nope. \[\tan (2x) =\frac {0}{\sqrt3}\] now simplify this
oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0
sorry!
haha..then you're right \[\tan(2x) =-\frac{1}{\sqrt 3}\]
now second step. take the arctangent of both sides
ok so pi/6?
remember that negative sign...and it's not yet over
how does the negative affect it?
well it doesnt affect that much
how do you mean?
|dw:1342705038280:dw|
oh ok so when you say take the arctangent, where do you go from there?
so \[2x = -\frac{\pi}{6}\] now you divide both sides by 2
ok so x= =pi/12
-pi/12
yup
is this one of the answers?
what do you mean?
well there are 4 values for x right?
because there was a 2 between the tan and the x, which compresses the tan graph
i cant remember that part...is it adding \(\pi\) or \(2\pi\)
what do you mean 2 between tan and x..tan (2x)?
yeah, thats what i meant tan2x
i think its add pi
im not sure about this part so im gonna ask @amistre64 for some assistance. please come sir.
Thank you for your help so far!!
what does amistre64 say?
i dont think he's coming yet...i tried tagging him to come here...
let me call a different one..he might be afk
Thank you :)
@apoorvk pls help
just add pi to the solution and it wont matter.
so 11pi/12?
yep i do think its another answer.
thanks @vamgadu you saved me there heh
yes thank you! :)
its my pleasure @lgbasallote
however, in the back of my text book the answers are 5pi/12 11pi/12 17pi/12 and 23pi/12
and im wondering how my magic maths textbook got there
so we are going good with the 11pi/12 :D
and if pi is added again, we get 23pi/12 which is also good!
you're doing right. so is there a further problem?
well there are sposed to be 4 answers
then you add pi again
i have 2 :)
2?
subtract a pi, if want int he interval, [-2pi,2pi]
well i have 11pi/12 and 23pi/12
-pi/12 and -13pi/12
so 11pi/12-pi?
-pi/12 - pi
11pi/12 - pi is -pi/12 (bringing you back to the orig thingy)
thats not one of the answers :?
  • phi
You started with 2x= -pi/6 if we call 2x theta, we have 2 solutions: |dw:1342706814544:dw| and x is 5pi/12 and 11pi/12 now add pi to each value to get the other 2 solutions or , noting that 2x+pi divided by 2 is x+pi/2 , add multiplies of pi/2 to get all four solutions starting with -pi/12 (which is 11pi/12 in the interval [0, 2pi] )
can this be done on a tan graph?

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