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Let me draw it. Jim has put a fence along the side AC of the triangular patch of land shown below.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1342705835156:dw| To solve this do I do tan(x) = 8 ÷ 15? and if not what should I do?
what are we trying to find here?
The length of the fence (AC)

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Other answers:

use pythogorous theorem no?
(AC)² = (AB)² + (BC)²
oh just 8^2 + 15^2 = 64 + 225 = 289 or √17
what happened there
sont you mean 64 + 225 = 289 or 17^2
dont*
Oh yeah sory I meant 17^2 Is that no bueno?
that's not the length of AC though
Do I use Tan?
\[AC = \sqrt{x^2 + y^2}\]
I don't know what x and y are, though? Unless 8 and 15 are x and y?
oops lol....
sorry that was the distance formula
haha no worries. I'm just glad you're helping :D
\[AC = \sqrt{AB^2 + BC^2}\]
Ah! Okay! So, 225+64 = √289? so the length of AC is 17?
yup
Thank you!

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