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rebeccaskell94
Group Title
Let me draw it.
Jim has put a fence along the side AC of the triangular patch of land shown below.
 2 years ago
 2 years ago
rebeccaskell94 Group Title
Let me draw it. Jim has put a fence along the side AC of the triangular patch of land shown below.
 2 years ago
 2 years ago

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rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
dw:1342705835156:dw To solve this do I do tan(x) = 8 ÷ 15? and if not what should I do?
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.0
what are we trying to find here?
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
The length of the fence (AC)
 2 years ago

vamgadu Group TitleBest ResponseYou've already chosen the best response.0
use pythogorous theorem no?
 2 years ago

y2o2 Group TitleBest ResponseYou've already chosen the best response.1
(AC)² = (AB)² + (BC)²
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
oh just 8^2 + 15^2 = 64 + 225 = 289 or √17
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
what happened there
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
sont you mean 64 + 225 = 289 or 17^2
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Oh yeah sory I meant 17^2 Is that no bueno?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
that's not the length of AC though
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Do I use Tan?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
\[AC = \sqrt{x^2 + y^2}\]
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
I don't know what x and y are, though? Unless 8 and 15 are x and y?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
oops lol....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
sorry that was the distance formula
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
haha no worries. I'm just glad you're helping :D
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
\[AC = \sqrt{AB^2 + BC^2}\]
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Ah! Okay! So, 225+64 = √289? so the length of AC is 17?
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 2 years ago
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