rebeccaskell94
Let me draw it.
Jim has put a fence along the side AC of the triangular patch of land shown below.



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rebeccaskell94
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dw:1342705835156:dw
To solve this do I do tan(x) = 8 ÷ 15? and if not what should I do?

vamgadu
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what are we trying to find here?

rebeccaskell94
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The length of the fence (AC)

vamgadu
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use pythogorous theorem no?

y2o2
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(AC)² = (AB)² + (BC)²

rebeccaskell94
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oh just 8^2 + 15^2 =
64 + 225 = 289 or √17

lgbasallote
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what happened there

lgbasallote
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sont you mean 64 + 225 = 289 or 17^2

lgbasallote
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dont*

rebeccaskell94
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Oh yeah sory I meant 17^2
Is that no bueno?

lgbasallote
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that's not the length of AC though

rebeccaskell94
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Do I use Tan?

lgbasallote
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\[AC = \sqrt{x^2 + y^2}\]

rebeccaskell94
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I don't know what x and y are, though? Unless 8 and 15 are x and y?

lgbasallote
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oops lol....

lgbasallote
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sorry that was the distance formula

rebeccaskell94
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haha no worries. I'm just glad you're helping :D

lgbasallote
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\[AC = \sqrt{AB^2 + BC^2}\]

rebeccaskell94
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Ah! Okay! So, 225+64 = √289? so the length of AC is 17?

lgbasallote
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yup

rebeccaskell94
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Thank you!