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Liltico
 2 years ago
Best ResponseYou've already chosen the best response.1i can't find the answer for x :(

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.1\(\large \tan \theta = \huge \frac{opposite}{adjacent} \)

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.1Algebra tricks... (writes)

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.1\[\tan 49^o = \frac{19}{x}\] \[x\tan 49^o = 19\] \[x = \frac{19}{\tan 49^o}\]

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.1You got a typo I see @Qibtiya , it's 49\(^o\) not 14\(^o\)

Qibtiya
 2 years ago
Best ResponseYou've already chosen the best response.0oh i thought that tan is 14 degree instide of 49 tan 49=1.150 tan 49=19/x or x=19/tan 49 put the value of tan 14 x=19/1.150 x=16.51
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