anonymous
  • anonymous
solve the following: 10^(2x-3) = 0.01
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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klimenkov
  • klimenkov
If \(a^x=b^x\), then \(a=b\). And use \(0.01=\frac1 {100}=\frac1{10^2}=10^{-2}\).
klimenkov
  • klimenkov
Oops. Really you need is that if \(a^x=a^y\) then \(x=y\).
anonymous
  • anonymous
Use what @klimenkov said above. \[10^{2x - 3} = 0.01\]\[10^{2x - 3} = \frac{1}{100}\]\[10^{2x - 3} = \frac{1}{10^{2}}\]\[10^{2x - 3} = 10^{-2}\]\[2x - 3 = -2\]Solve for x now.

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klimenkov
  • klimenkov
The very first statement is false. Forget it, because if \(2^2=(-2)^2\), but \(2\ne-2\).
anonymous
  • anonymous
What do you mean? I'm not quite following.
klimenkov
  • klimenkov
I said that mine statement was false.
anonymous
  • anonymous
Oh ok.
anonymous
  • anonymous
i'm sorry. which statement was false?
anonymous
  • anonymous
would the answer be x = 1/2
anonymous
  • anonymous
yup
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
I am so late...but you are correct :)

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