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johndeergurl

plz help explain: 3/x^3/1/x^2 ? I will up load a better picture.

  • one year ago
  • one year ago

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  1. johndeergurl
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    • one year ago
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  2. mandonut
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    dividing by 1/x^2 is the same as mutiply the numerator by x^2

    • one year ago
  3. mandonut
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    |dw:1342752270031:dw|

    • one year ago
  4. Romero
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    Wait that is wrong.

    • one year ago
  5. johndeergurl
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    I understand that part what I dnt get is do both of my x^2 and x^3 cross out?

    • one year ago
  6. Romero
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    \[\frac{3}{\frac{x^3}{\frac{1}{x^2}}}=\frac{3}{x^3}\frac{x^2}{1}=\frac{3x^2}{x^3}=\frac{3*x*x}{x*x*x}\]

    • one year ago
  7. Romero
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    You have two x's on the top and you have three in the bottom right?

    • one year ago
  8. johndeergurl
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    yes.

    • one year ago
  9. Romero
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    Two from the top cancel two from the bottom

    • one year ago
  10. Romero
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    so you are left with zero x's on the top and one x on the bottom

    • one year ago
  11. Romero
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    understand?

    • one year ago
  12. johndeergurl
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    so it would just be 3x

    • one year ago
  13. Romero
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    No I said there will be zero x on the top and one in the bottom of the fraction

    • one year ago
  14. johndeergurl
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    3/x

    • one year ago
  15. Romero
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    \[\frac{3*x*x}{x*x*x}=\frac{3}{x}\]

    • one year ago
  16. Romero
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    yes you are correct good job

    • one year ago
  17. johndeergurl
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    okay thank you. :) you were very helpful.

    • one year ago
  18. Romero
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    Sure thing

    • one year ago
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