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johndeergurl

  • 2 years ago

plz help explain: 3/x^3/1/x^2 ? I will up load a better picture.

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  1. johndeergurl
    • 2 years ago
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  2. mandonut
    • 2 years ago
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    dividing by 1/x^2 is the same as mutiply the numerator by x^2

  3. mandonut
    • 2 years ago
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    |dw:1342752270031:dw|

  4. Romero
    • 2 years ago
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    Wait that is wrong.

  5. johndeergurl
    • 2 years ago
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    I understand that part what I dnt get is do both of my x^2 and x^3 cross out?

  6. Romero
    • 2 years ago
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    \[\frac{3}{\frac{x^3}{\frac{1}{x^2}}}=\frac{3}{x^3}\frac{x^2}{1}=\frac{3x^2}{x^3}=\frac{3*x*x}{x*x*x}\]

  7. Romero
    • 2 years ago
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    You have two x's on the top and you have three in the bottom right?

  8. johndeergurl
    • 2 years ago
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    yes.

  9. Romero
    • 2 years ago
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    Two from the top cancel two from the bottom

  10. Romero
    • 2 years ago
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    so you are left with zero x's on the top and one x on the bottom

  11. Romero
    • 2 years ago
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    understand?

  12. johndeergurl
    • 2 years ago
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    so it would just be 3x

  13. Romero
    • 2 years ago
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    No I said there will be zero x on the top and one in the bottom of the fraction

  14. johndeergurl
    • 2 years ago
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    3/x

  15. Romero
    • 2 years ago
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    \[\frac{3*x*x}{x*x*x}=\frac{3}{x}\]

  16. Romero
    • 2 years ago
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    yes you are correct good job

  17. johndeergurl
    • 2 years ago
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    okay thank you. :) you were very helpful.

  18. Romero
    • 2 years ago
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    Sure thing

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