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solve: ( 1/(e^x) ) = 5

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This is tricky one you will have to use natural log.
1/e^(x) = 5 e^(x) = 1/5 ln(e^(x)) = ln(1/5) x = ln(1/5) = ln(1) - ln(5) = 0 - ln(5) = -ln(5)

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Other answers:

from there you simply natural log both sides.
\[e^{-x}=5\] does this look better? or maybe \[e^{x}= \frac{1}{5}\]
The natural log will cancel the e and bring down the x
You understand?
so the answer would be ln(1/5) ?
haha so many answers
Yes that is the answer. You can simplify it however you want. I would just leave it as that.
okay thank you. that makes sense!
notice that 1/5 = 5^(-1) and a property of logs is a*log(b) = log(b^a) so log(1/5) = log(5^(-1)) = -1*log(5) this is the great thing about logs, you can really "play around" with them. notice how i got to the same thing two compelety different ways.

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