## soccergal12 2 years ago solve: log(underscore:x)9 = 1/2

1. lgbasallote

_ <--underscore (shift + minus sign)

2. lgbasallote

anyway... $\log_x 9 = \frac 12$

3. lgbasallote

right?

4. soccergal12

yes igbasallote

5. soccergal12

that's the equation

6. lgbasallote

$\log_x 9 = \frac 12$ first step is to change it into exponential form $x^{1/2} = 9$ do you agree with this form

7. soccergal12

yes

8. lgbasallote

good. so we need x. you have x^1/2 what do you think you should do to make that x^1/2 into just x^1?

9. soccergal12

could you log both sides, and bring down the 1/2

10. lgbasallote

hmm not exactly

11. lgbasallote

here's a hint $\LARGE (a^3)^{1/3} = a^{3/3} = a^1 = a$ $\LARGE (a^2)^{1/2} = a^{2/2} = a^1 = a$ $\LARGE (a^{1/3})^3 = a^{3/3} = a^1 = a$

12. soccergal12

oh, do you square both sides?

13. lgbasallote

yup

14. soccergal12

so x = 81?

15. lgbasallote

yup

16. soccergal12

perfect thanks!

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