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solve: log(underscore:x)9 = 1/2

Mathematics
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_ <--underscore (shift + minus sign)
anyway... \[\log_x 9 = \frac 12\]
right?

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Other answers:

yes igbasallote
that's the equation
\[\log_x 9 = \frac 12\] first step is to change it into exponential form \[x^{1/2} = 9\] do you agree with this form
yes
good. so we need x. you have x^1/2 what do you think you should do to make that x^1/2 into just x^1?
could you log both sides, and bring down the 1/2
hmm not exactly
here's a hint \[\LARGE (a^3)^{1/3} = a^{3/3} = a^1 = a\] \[\LARGE (a^2)^{1/2} = a^{2/2} = a^1 = a\] \[\LARGE (a^{1/3})^3 = a^{3/3} = a^1 = a\]
oh, do you square both sides?
yup
so x = 81?
yup
perfect thanks!

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