A community for students.
Here's the question you clicked on:
 0 viewing
soccergal12
 3 years ago
solve: log(underscore:x)9 = 1/2
soccergal12
 3 years ago
solve: log(underscore:x)9 = 1/2

This Question is Closed

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1_ <underscore (shift + minus sign)

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1anyway... \[\log_x 9 = \frac 12\]

soccergal12
 3 years ago
Best ResponseYou've already chosen the best response.0that's the equation

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1\[\log_x 9 = \frac 12\] first step is to change it into exponential form \[x^{1/2} = 9\] do you agree with this form

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1good. so we need x. you have x^1/2 what do you think you should do to make that x^1/2 into just x^1?

soccergal12
 3 years ago
Best ResponseYou've already chosen the best response.0could you log both sides, and bring down the 1/2

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1here's a hint \[\LARGE (a^3)^{1/3} = a^{3/3} = a^1 = a\] \[\LARGE (a^2)^{1/2} = a^{2/2} = a^1 = a\] \[\LARGE (a^{1/3})^3 = a^{3/3} = a^1 = a\]

soccergal12
 3 years ago
Best ResponseYou've already chosen the best response.0oh, do you square both sides?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.