soccergal12
solve: log(underscore:x)9 = 1/2



This Question is Closed

lgbasallote
Best Response
You've already chosen the best response.
1
_ <underscore (shift + minus sign)

lgbasallote
Best Response
You've already chosen the best response.
1
anyway...
\[\log_x 9 = \frac 12\]

lgbasallote
Best Response
You've already chosen the best response.
1
right?

soccergal12
Best Response
You've already chosen the best response.
0
yes igbasallote

soccergal12
Best Response
You've already chosen the best response.
0
that's the equation

lgbasallote
Best Response
You've already chosen the best response.
1
\[\log_x 9 = \frac 12\]
first step is to change it into exponential form
\[x^{1/2} = 9\]
do you agree with this form

soccergal12
Best Response
You've already chosen the best response.
0
yes

lgbasallote
Best Response
You've already chosen the best response.
1
good. so we need x. you have x^1/2
what do you think you should do to make that x^1/2 into just x^1?

soccergal12
Best Response
You've already chosen the best response.
0
could you log both sides, and bring down the 1/2

lgbasallote
Best Response
You've already chosen the best response.
1
hmm not exactly

lgbasallote
Best Response
You've already chosen the best response.
1
here's a hint
\[\LARGE (a^3)^{1/3} = a^{3/3} = a^1 = a\]
\[\LARGE (a^2)^{1/2} = a^{2/2} = a^1 = a\]
\[\LARGE (a^{1/3})^3 = a^{3/3} = a^1 = a\]

soccergal12
Best Response
You've already chosen the best response.
0
oh, do you square both sides?

lgbasallote
Best Response
You've already chosen the best response.
1
yup

soccergal12
Best Response
You've already chosen the best response.
0
so x = 81?

lgbasallote
Best Response
You've already chosen the best response.
1
yup

soccergal12
Best Response
You've already chosen the best response.
0
perfect thanks!