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|dw:1342757653054:dw|

@lgbasallote please help!!

|dw:1342757791245:dw|
just presenting a drawing first so i can visualize it

I figured out that angle ADB = y.

how did you figure that out?

oh i see

Because triangle ABD is isosceles.

|dw:1342757924763:dw|

And how did you get DB = 3a and BC = a?

it says the ratio is 1:3

Ratio is 1:3 for the angle DAC.

That means t = 3a and y = a.

oh lol

y + y + t + 90 = 180
2y + t = 90
do you see this?

How did you get x = 90 degrees? I know it looks like that but i doesn't say so in the question.

Yes, I got that.

according to your triangle it's a right triangle

I might be slightly greater or lesser that 90 right?

|dw:1342758203033:dw|
y + y + m = 180
t + 90 + n = 180
m + n = 180

*It.

what do you mean?

do you have the *real* drawing??

this drawing is getting confusing :(

Yes, but it is in the form of a worksheet that I got in school(it is not in the electronic form).

I'll try drawing again then, just a minute.

|dw:1342758349890:dw|

|dw:1342758495805:dw|
For convenience.

|dw:1342758686754:dw|
a + a + x = 180
n + 3a + x = 180
a + a + m = 180
m + n = 180
do you see these?

Yes I do.

so you have 4 unknowns and 4 equations. we can use systems of linear equations

Yeah, but I only know how to solve system of equations with 2 variables.

i wrote one wrong...should be a + (a+3a) + x = 180

So 5a + x = 180

a + a + 3a + x = 180 -->1
n + 3a + x = 180 ---> 2
a + a + m = 180 --->3
m + n = 180 --> 4
yes

let's simplify everything first
5a +x = 180
n + 3a + x = 180
2a + m = 180
m + n = 180

OK. What next?

^that would be equation 5

Shouldn't it be 2a = n?
Because 0 - n would be -n and but you wrote n.

uhmm yeah you're right 2a = n

So a = n/2.
Or we can use n = 2a in one of the equations?

2a = n is the 5th equation

5a +x = 180
n + 3a + x = 180
2a + m = 180
m + n = 180
2a = n

well...x is not 90 degrees....

it's seriously complicated

|dw:1342759662640:dw|

if x were 90 then i assume the right triangle postulates and theorems could be applied

or maybe im just doing something wrong here...

Angle ABC = 180 - (3a + x).

a + 4a + x = 180
or 5a + x = 180

This is still not getting us anywhere ....

|dw:1342759792383:dw|

Is it possible to get x in terms of a ?

@dpaInc help here

|dw:1342760301927:dw|
If we take XY parallel to AB then AC is a transversal.

yep... just trying to figure it out....:)

|dw:1342761130552:dw|

i don't think the there is a unique solution....
are you looking for integer solutions?

I have to go now. Please please please help if possible .....

i think dplanc is right
there is no unique solution unless x=90