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Muskan Group Title

calculates the acceleration of a body starting from rest and has a speed of 20m / s after traveling 100m

  • 2 years ago
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  1. Hashir Group Title
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    |dw:1342777028474:dw|

    • 2 years ago
  2. Hashir Group Title
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    |dw:1342777061960:dw|

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  3. Hashir Group Title
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    |dw:1342777080539:dw|

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  4. lgbasallote Group Title
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    you are given the initial speed which is 0 (because it started from rest) you are given distance which is 100 m you are given final speed which is 20 m/s then you're looking for acceleration therefore you can use the formula \[V_2 ^2 = V_1 ^2 + 2ad\] where V2 is final speed V1 is initial speed a is acceleration d is distance so now just substitute \[20^2 = 0^2 + 2a(100)\] \[400 = 200a\] divide both sides by 200 \[\frac{400}{200} = a\] \[a = 200 m/s^2\]

    • 2 years ago
  5. lgbasallote Group Title
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    uhmm oops..should be \[a = 2 m/s^2\] sorry haha

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  6. lgbasallote Group Title
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    do you get it @Muskan ?

    • 2 years ago
  7. Muskan Group Title
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    yess

    • 2 years ago
  8. lgbasallote Group Title
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    glad to hear that :)

    • 2 years ago
  9. Muskan Group Title
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    :)) thnx

    • 2 years ago
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