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DHASHNI
 2 years ago
Best ResponseYou've already chosen the best response.0yeah ,,, which is equal to cos 30

DHASHNI
 2 years ago
Best ResponseYou've already chosen the best response.0but ,,,,, sin 0/tan 0 is not equal to cos 0 why so?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1342799811401:dw

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\(\sin \div \cos = \tan\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\(\sin \div \tan \ne \cos\)

Neemo
 2 years ago
Best ResponseYou've already chosen the best response.0@hba Ohh ! pleaase ! 0/0 =1 :) !!!!!!

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\( \color{Black}{\Rightarrow \tan 0 = \Large {\sin 0 \over \cos0} \normalsize = {0 \over1} = 0}\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1I believe that you are mistaken. sinx/tanx is not equal to cosx.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1The number '0' spoils it all.

Neemo
 2 years ago
Best ResponseYou've already chosen the best response.0this property is correct since tan(A)\[\tan(A) \neq 0\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1I see that all the exceptions come from the number \(0\). I like this number. You can do anything from it(prove 2 = 1) ;)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1I believe that we may just conclude that \(\Large {\sin x \over \tan x} \normalsize = \cos x , x \ne 0 \)

DHASHNI
 2 years ago
Best ResponseYou've already chosen the best response.0but this is a property right?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\( \color{Black}{\theta \ne 0 \Rightarrow {\Large {\sin \theta \over \tan \theta}} = \cos \theta}\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1That was mathematical language.

Neemo
 2 years ago
Best ResponseYou've already chosen the best response.0@ParthKohli Come on !( 2=1) and yes The property is correct ! for \[x \neq k \pi \] \[x \neq \pi/2\]

Neemo
 2 years ago
Best ResponseYou've already chosen the best response.0sorry \[x \neq \pi/2 +k \pi\] for the second one !
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