DHASHNI
sin A
 = cos A (known) ................(sin 30)/tan 30 ?
tan A



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sai1234
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cos 30=root(3)/2

DHASHNI
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yeah ,,, which is equal to cos 30

DHASHNI
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but ,,,,, sin 0/tan 0 is not equal to cos 0 why so?

hba
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what do we have to find

DHASHNI
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dw:1342799783750:dw

DHASHNI
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dw:1342799803525:dw

hba
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@DHASHNI it is equal

ParthKohli
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dw:1342799811401:dw

ParthKohli
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\(\sin \div \cos = \tan\)

ParthKohli
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\(\sin \div \tan \ne \cos\)

Neemo
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@hba Ohh ! pleaase ! 0/0 =1 :) !!!!!!

ParthKohli
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\( \color{Black}{\Rightarrow \tan 0 = \Large {\sin 0 \over \cos0} \normalsize = {0 \over1} = 0}\)

ParthKohli
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I believe that you are mistaken. sinx/tanx is not equal to cosx.

DHASHNI
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why its a property

ParthKohli
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The number '0' spoils it all.

Neemo
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this property is correct since tan(A)\[\tan(A) \neq 0\]

DHASHNI
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tan 0 is 0

Neemo
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yeaah !

ParthKohli
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I see that all the exceptions come from the number \(0\). I like this number. You can do anything from it(prove 2 = 1) ;)

DHASHNI
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yeah

ParthKohli
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I believe that we may just conclude that \(\Large {\sin x \over \tan x} \normalsize = \cos x , x \ne 0 \)

DHASHNI
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but this is a property right?

ParthKohli
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It is.

ParthKohli
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\( \color{Black}{\theta \ne 0 \Rightarrow {\Large {\sin \theta \over \tan \theta}} = \cos \theta}\)

ParthKohli
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That was mathematical language.

Neemo
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@ParthKohli Come on !( 2=1)
and yes The property is correct ! for \[x \neq k \pi \]
\[x \neq \pi/2\]

Neemo
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sorry \[x \neq \pi/2 +k \pi\]
for the second one !