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DHASHNI

  • 2 years ago

sin A ----- = cos A (known) ................(sin 30)/tan 30 ? tan A

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  1. sai1234
    • 2 years ago
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    cos 30=root(3)/2

  2. DHASHNI
    • 2 years ago
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    yeah ,,, which is equal to cos 30

  3. DHASHNI
    • 2 years ago
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    but ,,,,, sin 0/tan 0 is not equal to cos 0 why so?

  4. hba
    • 2 years ago
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    what do we have to find

  5. DHASHNI
    • 2 years ago
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    |dw:1342799783750:dw|

  6. DHASHNI
    • 2 years ago
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    |dw:1342799803525:dw|

  7. hba
    • 2 years ago
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    @DHASHNI it is equal

  8. ParthKohli
    • 2 years ago
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    |dw:1342799811401:dw|

  9. ParthKohli
    • 2 years ago
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    \(\sin \div \cos = \tan\)

  10. ParthKohli
    • 2 years ago
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    \(\sin \div \tan \ne \cos\)

  11. Neemo
    • 2 years ago
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    @hba Ohh ! pleaase ! 0/0 =1 :) !!!!!!

  12. ParthKohli
    • 2 years ago
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    \( \color{Black}{\Rightarrow \tan 0 = \Large {\sin 0 \over \cos0} \normalsize = {0 \over1} = 0}\)

  13. ParthKohli
    • 2 years ago
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    I believe that you are mistaken. sinx/tanx is not equal to cosx.

  14. DHASHNI
    • 2 years ago
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    why its a property

  15. ParthKohli
    • 2 years ago
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    The number '0' spoils it all.

  16. Neemo
    • 2 years ago
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    this property is correct since tan(A)\[\tan(A) \neq 0\]

  17. DHASHNI
    • 2 years ago
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    tan 0 is 0

  18. Neemo
    • 2 years ago
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    yeaah !

  19. ParthKohli
    • 2 years ago
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    I see that all the exceptions come from the number \(0\). I like this number. You can do anything from it(prove 2 = 1) ;)

  20. DHASHNI
    • 2 years ago
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    yeah

  21. ParthKohli
    • 2 years ago
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    I believe that we may just conclude that \(\Large {\sin x \over \tan x} \normalsize = \cos x , x \ne 0 \)

  22. DHASHNI
    • 2 years ago
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    but this is a property right?

  23. ParthKohli
    • 2 years ago
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    It is.

  24. ParthKohli
    • 2 years ago
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    \( \color{Black}{\theta \ne 0 \Rightarrow {\Large {\sin \theta \over \tan \theta}} = \cos \theta}\)

  25. ParthKohli
    • 2 years ago
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    That was mathematical language.

  26. Neemo
    • 2 years ago
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    @ParthKohli Come on !( 2=1) and yes The property is correct ! for \[x \neq k \pi \] \[x \neq \pi/2\]

  27. Neemo
    • 2 years ago
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    sorry \[x \neq \pi/2 +k \pi\] for the second one !

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