anonymous
  • anonymous
sin A ----- = cos A (known) ................(sin 30)/tan 30 ? tan A
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
cos 30=root(3)/2
anonymous
  • anonymous
yeah ,,, which is equal to cos 30
anonymous
  • anonymous
but ,,,,, sin 0/tan 0 is not equal to cos 0 why so?

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hba
  • hba
what do we have to find
anonymous
  • anonymous
|dw:1342799783750:dw|
anonymous
  • anonymous
|dw:1342799803525:dw|
hba
  • hba
@DHASHNI it is equal
ParthKohli
  • ParthKohli
|dw:1342799811401:dw|
ParthKohli
  • ParthKohli
\(\sin \div \cos = \tan\)
ParthKohli
  • ParthKohli
\(\sin \div \tan \ne \cos\)
anonymous
  • anonymous
@hba Ohh ! pleaase ! 0/0 =1 :) !!!!!!
ParthKohli
  • ParthKohli
\( \color{Black}{\Rightarrow \tan 0 = \Large {\sin 0 \over \cos0} \normalsize = {0 \over1} = 0}\)
ParthKohli
  • ParthKohli
I believe that you are mistaken. sinx/tanx is not equal to cosx.
anonymous
  • anonymous
why its a property
ParthKohli
  • ParthKohli
The number '0' spoils it all.
anonymous
  • anonymous
this property is correct since tan(A)\[\tan(A) \neq 0\]
anonymous
  • anonymous
tan 0 is 0
anonymous
  • anonymous
yeaah !
ParthKohli
  • ParthKohli
I see that all the exceptions come from the number \(0\). I like this number. You can do anything from it(prove 2 = 1) ;)
anonymous
  • anonymous
yeah
ParthKohli
  • ParthKohli
I believe that we may just conclude that \(\Large {\sin x \over \tan x} \normalsize = \cos x , x \ne 0 \)
anonymous
  • anonymous
but this is a property right?
ParthKohli
  • ParthKohli
It is.
ParthKohli
  • ParthKohli
\( \color{Black}{\theta \ne 0 \Rightarrow {\Large {\sin \theta \over \tan \theta}} = \cos \theta}\)
ParthKohli
  • ParthKohli
That was mathematical language.
anonymous
  • anonymous
@ParthKohli Come on !( 2=1) and yes The property is correct ! for \[x \neq k \pi \] \[x \neq \pi/2\]
anonymous
  • anonymous
sorry \[x \neq \pi/2 +k \pi\] for the second one !

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