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DHASHNI

sin A ----- = cos A (known) ................(sin 30)/tan 30 ? tan A

  • one year ago
  • one year ago

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  1. sai1234
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    cos 30=root(3)/2

    • one year ago
  2. DHASHNI
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    yeah ,,, which is equal to cos 30

    • one year ago
  3. DHASHNI
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    but ,,,,, sin 0/tan 0 is not equal to cos 0 why so?

    • one year ago
  4. hba
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    what do we have to find

    • one year ago
  5. DHASHNI
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    |dw:1342799783750:dw|

    • one year ago
  6. DHASHNI
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    |dw:1342799803525:dw|

    • one year ago
  7. hba
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    @DHASHNI it is equal

    • one year ago
  8. ParthKohli
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    |dw:1342799811401:dw|

    • one year ago
  9. ParthKohli
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    \(\sin \div \cos = \tan\)

    • one year ago
  10. ParthKohli
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    \(\sin \div \tan \ne \cos\)

    • one year ago
  11. Neemo
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    @hba Ohh ! pleaase ! 0/0 =1 :) !!!!!!

    • one year ago
  12. ParthKohli
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    \( \color{Black}{\Rightarrow \tan 0 = \Large {\sin 0 \over \cos0} \normalsize = {0 \over1} = 0}\)

    • one year ago
  13. ParthKohli
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    I believe that you are mistaken. sinx/tanx is not equal to cosx.

    • one year ago
  14. DHASHNI
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    why its a property

    • one year ago
  15. ParthKohli
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    The number '0' spoils it all.

    • one year ago
  16. Neemo
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    this property is correct since tan(A)\[\tan(A) \neq 0\]

    • one year ago
  17. DHASHNI
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    tan 0 is 0

    • one year ago
  18. Neemo
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    yeaah !

    • one year ago
  19. ParthKohli
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    I see that all the exceptions come from the number \(0\). I like this number. You can do anything from it(prove 2 = 1) ;)

    • one year ago
  20. DHASHNI
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    yeah

    • one year ago
  21. ParthKohli
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    I believe that we may just conclude that \(\Large {\sin x \over \tan x} \normalsize = \cos x , x \ne 0 \)

    • one year ago
  22. DHASHNI
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    but this is a property right?

    • one year ago
  23. ParthKohli
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    It is.

    • one year ago
  24. ParthKohli
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    \( \color{Black}{\theta \ne 0 \Rightarrow {\Large {\sin \theta \over \tan \theta}} = \cos \theta}\)

    • one year ago
  25. ParthKohli
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    That was mathematical language.

    • one year ago
  26. Neemo
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    @ParthKohli Come on !( 2=1) and yes The property is correct ! for \[x \neq k \pi \] \[x \neq \pi/2\]

    • one year ago
  27. Neemo
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    sorry \[x \neq \pi/2 +k \pi\] for the second one !

    • one year ago
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