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A cone with a radius of 8 feet and a slant height of 17 feet is shown below. What is the surface area of this cone? Use 22/7 for pi. 628.57 square feet 427.43 square feet 1,335.71 square feet 854.86 square feet

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are=pie.r^2+pie.r.s 22/7.8.8+22/7.8.17 =628.0
\(a^2+b^2=c^2\) where c = 17 ft and a = r |dw:1342800106700:dw|= 8 ft

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Other answers:

\[\text{Volume} = \frac{\pi r^2 h}{3}\] \[\text{Surface Area} = \pi r s + (\text{Area}_{\text{circle}}) = \pi r s + \pi r^2\] s = c = 17 ft
You should now be able to find either volume or surface area @NyKole ^_^ Make sense?
Maybe this will make it more interesting then... :-P
is the answer A?
\(\text{Surface Area} = \pi (8 \ ft)(17 \ ft) + \pi (8 \ ft)^2\) \(\text{Surface Area} = 136\pi \ ft^2 + 64\pi \ ft^2\) \(\text{Surface Area} = 200\pi \ ft^2 \approx 628 \ ft^2\) Correct! Good job (see how the units work btw? foot * foot = feet squared)
The precise answer would be "200\(\pi\) ft\(^2\)" :-) That's what my boss would want if I was engineering something like this. Any contractor making the item can use a little calculator on-site to figure out how accurate they want to get.

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