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rayford

sqrt64/sqrt3

  • one year ago
  • one year ago

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  1. Ganpat
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    \[\sqrt{64} / \sqrt{3} = \sqrt{(8 * 8)} / \sqrt{3} = 8/\sqrt{3}..\]

    • one year ago
  2. rayford
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    oh my god it's so easy now that you explained it!...may you answer one more?

    • one year ago
  3. Ganpat
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    ya sure..

    • one year ago
  4. Ganpat
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    its good, if u practice as well :D

    • one year ago
  5. rayford
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    sqrt10(4-sqrt5)+sqrt8(sqrt5+2)

    • one year ago
  6. .Sam.
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    \[ 8/\sqrt{3}~~ \text{is \not the simplified form yet}\]

    • one year ago
  7. DLS
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    8/root 3 = 8 root 3/3=> 13.856/3=>4.61

    • one year ago
  8. violy
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    yes, 8/ sqrt of 3 is not yet simplified, you need to raionalize it.

    • one year ago
  9. rayford
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    so is it 8sqrt3/3?

    • one year ago
  10. DLS
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    Its 4.61

    • one year ago
  11. Ganpat
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    \[\sqrt{10} * (4 - \sqrt{5}) + \sqrt{8} * (\sqrt{5} + 2) = \] \[4\sqrt{10} - \sqrt{(5 * 10)} + \sqrt{(5 * 8)} + 2\sqrt{8}\] Now can u solve further...

    • one year ago
  12. rayford
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    wait guys ..for the first one the answer choices are..8sqt3/3 8/3 8/sqrt3 sqrt3/3

    • one year ago
  13. DLS
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    8sqt3/3 !

    • one year ago
  14. Ganpat
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    for the second one... \[4\sqrt{10} - 5\sqrt{2} + 2\sqrt{10} + 4\sqrt{2} = 6\sqrt{2} - \sqrt{2}\] is the answer...

    • one year ago
  15. rayford
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    the second question choices are..4sqrt10-sqrt50+sqrt40+2sqrt8 6sqrt10-sqrt50+2sqrt8 2sqrt8-4 6sqrt10-sqrt2

    • one year ago
  16. Ganpat
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    sorry last one.. typo error..

    • one year ago
  17. rayford
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    thank you...now i can sleep..3;40 am and i can finally sleep...enjoy ur 2 medals.

    • one year ago
  18. Ganpat
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    lol !! have a good sleep :) good night !!

    • one year ago
  19. TheViper
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    \[\Huge{\color{red}{\sqrt{64}\over \sqrt{3}}}\]\[\LARGE{\color{blue}{{8\over \sqrt{3}}=\frac{8}{1.714}}}\]

    • one year ago
  20. muhammad9t5
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    8/sqrt3

    • one year ago
  21. TheViper
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    yes right @muhammad9t5 but it is equal to 8/1.714 :)

    • one year ago
  22. muhammad9t5
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    yes for further solving your asnwer is also right. but in math we need only whole numbers.

    • one year ago
  23. TheViper
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    ;)

    • one year ago
  24. muhammad9t5
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    friend also rate me please.

    • one year ago
  25. TheViper
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    k I m ur fan :)

    • one year ago
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