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azib

  • 2 years ago

see the attached image file

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  1. azib
    • 2 years ago
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  2. zzr0ck3r
    • 2 years ago
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    intx+6 - int x^2 on the bounds given

  3. nitz
    • 2 years ago
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    \[\int\limits_{0}^{2}((x+6)-(x ^{2}))dx\]

  4. dpflan
    • 2 years ago
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    Bounded integrals, I believe the general concept is you find the area beneath the top curve over the interval, the area beneath the bottom curve over the interval, and because you want the area below the top curve and above the bottom curve, you then subtract the first function from the second function, and find the integral over the interval...

  5. dpflan
    • 2 years ago
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    Like @nitz has done

  6. zzr0ck3r
    • 2 years ago
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    1/2*x^2 +6x - 1/3x^3 then do the bounds

  7. dpflan
    • 2 years ago
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    and @zzr0ck3r rockin' it

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