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anonymous
 4 years ago
see the attached image file
anonymous
 4 years ago
see the attached image file

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zzr0ck3r
 4 years ago
Best ResponseYou've already chosen the best response.1intx+6  int x^2 on the bounds given

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2}((x+6)(x ^{2}))dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Bounded integrals, I believe the general concept is you find the area beneath the top curve over the interval, the area beneath the bottom curve over the interval, and because you want the area below the top curve and above the bottom curve, you then subtract the first function from the second function, and find the integral over the interval...

zzr0ck3r
 4 years ago
Best ResponseYou've already chosen the best response.11/2*x^2 +6x  1/3x^3 then do the bounds

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and @zzr0ck3r rockin' it
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