anonymous
  • anonymous
in a 45 45 90 triangle i need to find what x is
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1342917395925:dw|
anonymous
  • anonymous
|dw:1342917641735:dw|
anonymous
  • anonymous
would it be 6 square root of 2

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anonymous
  • anonymous
Use Pythagoras theorem \[x^2+x^2=12^2\]
anonymous
  • anonymous
yes
Australopithecus
  • Australopithecus
you cant solve this with pythagoras theorem you have to use trig I'm pretty sure
anonymous
  • anonymous
\[2x^2=12^2\]\[2x^2=144\]\[x^2=\frac{144}{2}\]\[x^2=72\]\[x= \sqrt{72}\]\[x= \sqrt{36*2}\]\[x=6 \sqrt{2}\]
anonymous
  • anonymous
Yes you can you have two sides that are equal
anonymous
  • anonymous
Hey @sarver1995 Been a while :) 45-45-90 triangles: |dw:1342917784578:dw|
Australopithecus
  • Australopithecus
oh yeah just noticed :)
anonymous
  • anonymous
\[x\sqrt{2} = 12\]\[x = \frac{12}{\sqrt{2}}\]\[x = \frac{12}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}\]\[x = \frac{12\sqrt{2}}{2}\]\[x = 6\sqrt{2}\]There you go :)
Australopithecus
  • Australopithecus
SOH CAH TOA Sin = opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/adjacent cos(45) = x/12 cos(45)(12) = x
anonymous
  • anonymous
from this I noticed that you can simply get one of the sides by multiplying the hypotenuse by \[\frac{1}{\sqrt{2}}\]
anonymous
  • anonymous
Only if the triangle is a 45 45 90
anonymous
  • anonymous
|dw:1342917788335:dw|
anonymous
  • anonymous
Same thing...use the ratio above... |dw:1342918025299:dw|
anonymous
  • anonymous
same thing like I said \[\frac{1}{\sqrt{2}}*x=10\]
anonymous
  • anonymous
solve for x
anonymous
  • anonymous
to calcmathlete yeah i am now reviewing and oh course still confused i only have a few more lessons and i am finished with 11th grade. its been really rough
anonymous
  • anonymous
|dw:1342918127585:dw| would x be 10 square root of 2
anonymous
  • anonymous
Yes :) \[x = 10\sqrt{2}\]
anonymous
  • anonymous
Good job mate!
anonymous
  • anonymous
|dw:1342918257888:dw| okay not sure how to do this one
anonymous
  • anonymous
it cant be 1/2 square root of 2
anonymous
  • anonymous
Does it tell you if it's a right triangle?
anonymous
  • anonymous
45 45 90
anonymous
  • anonymous
It tells you that?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Ok. The ratio again. x, x, x√2 x = 1.2 x√2 = ?
anonymous
  • anonymous
i will try to draw it again maybe i ddin't do it right
anonymous
  • anonymous
By the way, if the x's get confusing because they are using x as a variable, I'll just use y.
anonymous
  • anonymous
|dw:1342918455394:dw|
anonymous
  • anonymous
Ok. Same situation. The legs are always congruent in a 45-45-90 triangle. The hypotenuse is always in this ratio: \[Leg \times \sqrt{2}\]Can you figure it out since you have the leg?
anonymous
  • anonymous
1.2 x square root of 2
anonymous
  • anonymous
not sure on this one
anonymous
  • anonymous
Yup. which can be rewritten as \(1.2\sqrt{2}\)
anonymous
  • anonymous
okay i have one more like these can i try it with us
anonymous
  • anonymous
Alright shoot away :)
anonymous
  • anonymous
|dw:1342918731847:dw|
anonymous
  • anonymous
\[x = \frac{\sqrt{24}}{\sqrt{2}} = \sqrt{\frac{24}{2}} = \sqrt{12} = ?\]
anonymous
  • anonymous
2 square root of 3
anonymous
  • anonymous
yup :)
anonymous
  • anonymous
okay i have a different one i just need u to help me understand the problem it will take a little while to draw
anonymous
  • anonymous
ok.
anonymous
  • anonymous
|dw:1342918993022:dw| Refer to the figure to complete the following item. Given: If m arc vu =80° and marc st =40°, then 1 =
anonymous
  • anonymous
Oh gosh...a proof?
anonymous
  • anonymous
yeah lol
anonymous
  • anonymous
Do you have to like fill in a blank or is it like write an entire proof?
anonymous
  • anonymous
its just asking what angle 1 would equal
anonymous
  • anonymous
just an answer
anonymous
  • anonymous
I think that it's 50...
anonymous
  • anonymous
can you tell me how you got that because i have three more problems like this one
anonymous
  • anonymous
\[m\angle1 = \frac 12(arcVT - arcST)\]
anonymous
  • anonymous
If arc vu m = 70° and m arc st = 30°, then 2 = would it be the same formula for this one
anonymous
  • anonymous
I kind of have to go...sorry :/ If it maintains the same shape, it should be the same sort of formula...
anonymous
  • anonymous
thanks for your help its really appreciated and God bless you

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