Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342917395925:dw
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
dw:1342917641735:dw
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
would it be 6 square root of 2
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
Use Pythagoras theorem \[x^2+x^2=12^2\]
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
you cant solve this with pythagoras theorem you have to use trig I'm pretty sure
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
\[2x^2=12^2\]\[2x^2=144\]\[x^2=\frac{144}{2}\]\[x^2=72\]\[x= \sqrt{72}\]\[x= \sqrt{36*2}\]\[x=6 \sqrt{2}\]
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
Yes you can you have two sides that are equal
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Hey @sarver1995 Been a while :) 454590 triangles: dw:1342917784578:dw
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
oh yeah just noticed :)
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
\[x\sqrt{2} = 12\]\[x = \frac{12}{\sqrt{2}}\]\[x = \frac{12}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}\]\[x = \frac{12\sqrt{2}}{2}\]\[x = 6\sqrt{2}\]There you go :)
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
SOH CAH TOA Sin = opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/adjacent cos(45) = x/12 cos(45)(12) = x
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
from this I noticed that you can simply get one of the sides by multiplying the hypotenuse by \[\frac{1}{\sqrt{2}}\]
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
Only if the triangle is a 45 45 90
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342917788335:dw
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Same thing...use the ratio above... dw:1342918025299:dw
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
same thing like I said \[\frac{1}{\sqrt{2}}*x=10\]
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
to calcmathlete yeah i am now reviewing and oh course still confused i only have a few more lessons and i am finished with 11th grade. its been really rough
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342918127585:dw would x be 10 square root of 2
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Yes :) \[x = 10\sqrt{2}\]
 2 years ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
Good job mate!
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342918257888:dw okay not sure how to do this one
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
it cant be 1/2 square root of 2
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Does it tell you if it's a right triangle?
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
45 45 90
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
It tells you that?
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Ok. The ratio again. x, x, x√2 x = 1.2 x√2 = ?
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
i will try to draw it again maybe i ddin't do it right
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
By the way, if the x's get confusing because they are using x as a variable, I'll just use y.
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342918455394:dw
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Ok. Same situation. The legs are always congruent in a 454590 triangle. The hypotenuse is always in this ratio: \[Leg \times \sqrt{2}\]Can you figure it out since you have the leg?
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
1.2 x square root of 2
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
not sure on this one
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Yup. which can be rewritten as \(1.2\sqrt{2}\)
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
okay i have one more like these can i try it with us
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Alright shoot away :)
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342918731847:dw
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
\[x = \frac{\sqrt{24}}{\sqrt{2}} = \sqrt{\frac{24}{2}} = \sqrt{12} = ?\]
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
2 square root of 3
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
yup :)
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
okay i have a different one i just need u to help me understand the problem it will take a little while to draw
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
dw:1342918993022:dw Refer to the figure to complete the following item. Given: If m arc vu =80° and marc st =40°, then 1 =
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Oh gosh...a proof?
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
yeah lol
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
Do you have to like fill in a blank or is it like write an entire proof?
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
its just asking what angle 1 would equal
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
just an answer
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
I think that it's 50...
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
can you tell me how you got that because i have three more problems like this one
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
\[m\angle1 = \frac 12(arcVT  arcST)\]
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
If arc vu m = 70° and m arc st = 30°, then 2 = would it be the same formula for this one
 2 years ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.1
I kind of have to go...sorry :/ If it maintains the same shape, it should be the same sort of formula...
 2 years ago

sarver1995 Group TitleBest ResponseYou've already chosen the best response.1
thanks for your help its really appreciated and God bless you
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.