## sarver1995 Group Title in a 45 45 90 triangle i need to find what x is 2 years ago 2 years ago

1. sarver1995 Group Title

|dw:1342917395925:dw|

2. Romero Group Title

|dw:1342917641735:dw|

3. sarver1995 Group Title

would it be 6 square root of 2

4. Romero Group Title

Use Pythagoras theorem $x^2+x^2=12^2$

5. Romero Group Title

yes

6. Australopithecus Group Title

you cant solve this with pythagoras theorem you have to use trig I'm pretty sure

7. Romero Group Title

$2x^2=12^2$$2x^2=144$$x^2=\frac{144}{2}$$x^2=72$$x= \sqrt{72}$$x= \sqrt{36*2}$$x=6 \sqrt{2}$

8. Romero Group Title

Yes you can you have two sides that are equal

9. Calcmathlete Group Title

Hey @sarver1995 Been a while :) 45-45-90 triangles: |dw:1342917784578:dw|

10. Australopithecus Group Title

oh yeah just noticed :)

11. Calcmathlete Group Title

$x\sqrt{2} = 12$$x = \frac{12}{\sqrt{2}}$$x = \frac{12}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$$x = \frac{12\sqrt{2}}{2}$$x = 6\sqrt{2}$There you go :)

12. Australopithecus Group Title

SOH CAH TOA Sin = opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/adjacent cos(45) = x/12 cos(45)(12) = x

13. Romero Group Title

from this I noticed that you can simply get one of the sides by multiplying the hypotenuse by $\frac{1}{\sqrt{2}}$

14. Romero Group Title

Only if the triangle is a 45 45 90

15. sarver1995 Group Title

|dw:1342917788335:dw|

16. Calcmathlete Group Title

Same thing...use the ratio above... |dw:1342918025299:dw|

17. Romero Group Title

same thing like I said $\frac{1}{\sqrt{2}}*x=10$

18. Romero Group Title

solve for x

19. sarver1995 Group Title

to calcmathlete yeah i am now reviewing and oh course still confused i only have a few more lessons and i am finished with 11th grade. its been really rough

20. sarver1995 Group Title

|dw:1342918127585:dw| would x be 10 square root of 2

21. Calcmathlete Group Title

Yes :) $x = 10\sqrt{2}$

22. Romero Group Title

Good job mate!

23. sarver1995 Group Title

|dw:1342918257888:dw| okay not sure how to do this one

24. sarver1995 Group Title

it cant be 1/2 square root of 2

25. Calcmathlete Group Title

Does it tell you if it's a right triangle?

26. sarver1995 Group Title

45 45 90

27. Calcmathlete Group Title

It tells you that?

28. sarver1995 Group Title

yes

29. Calcmathlete Group Title

Ok. The ratio again. x, x, x√2 x = 1.2 x√2 = ?

30. sarver1995 Group Title

i will try to draw it again maybe i ddin't do it right

31. Calcmathlete Group Title

By the way, if the x's get confusing because they are using x as a variable, I'll just use y.

32. sarver1995 Group Title

|dw:1342918455394:dw|

33. Calcmathlete Group Title

Ok. Same situation. The legs are always congruent in a 45-45-90 triangle. The hypotenuse is always in this ratio: $Leg \times \sqrt{2}$Can you figure it out since you have the leg?

34. sarver1995 Group Title

1.2 x square root of 2

35. sarver1995 Group Title

not sure on this one

36. Calcmathlete Group Title

Yup. which can be rewritten as $$1.2\sqrt{2}$$

37. sarver1995 Group Title

okay i have one more like these can i try it with us

38. Calcmathlete Group Title

Alright shoot away :)

39. sarver1995 Group Title

|dw:1342918731847:dw|

40. Calcmathlete Group Title

$x = \frac{\sqrt{24}}{\sqrt{2}} = \sqrt{\frac{24}{2}} = \sqrt{12} = ?$

41. sarver1995 Group Title

2 square root of 3

42. Calcmathlete Group Title

yup :)

43. sarver1995 Group Title

okay i have a different one i just need u to help me understand the problem it will take a little while to draw

44. Calcmathlete Group Title

ok.

45. sarver1995 Group Title

|dw:1342918993022:dw| Refer to the figure to complete the following item. Given: If m arc vu =80° and marc st =40°, then 1 =

46. Calcmathlete Group Title

Oh gosh...a proof?

47. sarver1995 Group Title

yeah lol

48. Calcmathlete Group Title

Do you have to like fill in a blank or is it like write an entire proof?

49. sarver1995 Group Title

its just asking what angle 1 would equal

50. sarver1995 Group Title

51. Calcmathlete Group Title

I think that it's 50...

52. sarver1995 Group Title

can you tell me how you got that because i have three more problems like this one

53. Calcmathlete Group Title

$m\angle1 = \frac 12(arcVT - arcST)$

54. sarver1995 Group Title

If arc vu m = 70° and m arc st = 30°, then 2 = would it be the same formula for this one

55. Calcmathlete Group Title

I kind of have to go...sorry :/ If it maintains the same shape, it should be the same sort of formula...

56. sarver1995 Group Title

thanks for your help its really appreciated and God bless you