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|dw:1342917395925:dw|

|dw:1342917641735:dw|

would it be 6 square root of 2

Use Pythagoras theorem
\[x^2+x^2=12^2\]

yes

you cant solve this with pythagoras theorem you have to use trig I'm pretty sure

Yes you can you have two sides that are equal

Hey @sarver1995 Been a while :)
45-45-90 triangles:
|dw:1342917784578:dw|

oh yeah just noticed :)

Only if the triangle is a 45 45 90

|dw:1342917788335:dw|

Same thing...use the ratio above...
|dw:1342918025299:dw|

same thing like I said
\[\frac{1}{\sqrt{2}}*x=10\]

solve for x

|dw:1342918127585:dw| would x be 10 square root of 2

Yes :)
\[x = 10\sqrt{2}\]

Good job mate!

|dw:1342918257888:dw| okay not sure how to do this one

it cant be 1/2 square root of 2

Does it tell you if it's a right triangle?

45 45 90

It tells you that?

yes

Ok.
The ratio again.
x, x, x√2
x = 1.2
x√2 = ?

i will try to draw it again maybe i ddin't do it right

By the way, if the x's get confusing because they are using x as a variable, I'll just use y.

|dw:1342918455394:dw|

1.2 x square root of 2

not sure on this one

Yup. which can be rewritten as \(1.2\sqrt{2}\)

okay i have one more like these can i try it with us

Alright shoot away :)

|dw:1342918731847:dw|

\[x = \frac{\sqrt{24}}{\sqrt{2}} = \sqrt{\frac{24}{2}} = \sqrt{12} = ?\]

2 square root of 3

yup :)

ok.

Oh gosh...a proof?

yeah lol

Do you have to like fill in a blank or is it like write an entire proof?

its just asking what angle 1 would equal

just an answer

I think that it's 50...

can you tell me how you got that because i have three more problems like this one

\[m\angle1 = \frac 12(arcVT - arcST)\]

If arc vu m = 70° and m arc st = 30°, then 2 = would it be the same formula for this one

thanks for your help its really appreciated and God bless you