A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
The hydroxide ion concentration in a 0.157 mol/L solution of sodium propanoate, NaC3H5O2 (aq) is found to be 1.1*10^5 mol/L. Calculate the base ionization constant for the propanoate ion.
 2 years ago
The hydroxide ion concentration in a 0.157 mol/L solution of sodium propanoate, NaC3H5O2 (aq) is found to be 1.1*10^5 mol/L. Calculate the base ionization constant for the propanoate ion.

This Question is Closed

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0I am using the Formula Ka*Kb=Kw. Rearranged then into Kb=Kw/Ka. Kw is a constant; 1.0*10^14. Originally attempted using formula Kw=[H30}{OH^}. Answer was 9.09*10^10. Actual answer is 7.7*10^10.

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0@saifoo.khan @Hero @ParthKohli

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0Finally, got some people.

Hero
 2 years ago
Best ResponseYou've already chosen the best response.0What world am I in? Chemistry? Really? Sorry I'm not the guy.

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.0that's the salt of a strong base and a weak acid.....

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.0base ionization constant means PoH?

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0I don't think so, but it's mentioned in this part of the textbook.

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.0so ther's some other formula to calculate that i suppose.......

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.0yes thats the PoH and 1st one is pH(Hydrogen Concentration)

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0So far, I attempted to use Kw=[H3O][OH], kakb=kw and kb=[HB][OH]/[B]

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.0please have a look on http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/Calculating_pHandpOH.htm

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.02ph=14+pka+logc @25 degree c

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.0use that.....u l get it....

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry, which formula did oyu use? (Best use the equation editor or draw it out to get the message across)

A.Avinash_Goutham
 2 years ago
Best ResponseYou've already chosen the best response.0help ur self......

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0Wait, is this question related any way to pH Also, that was a rather rude way to brush me off.

huneya
 2 years ago
Best ResponseYou've already chosen the best response.1http://herh.ccrsb.ca/staff/FarrellL/chem12/acids/acidbasereviewanswers.pdf

IsTim
 2 years ago
Best ResponseYou've already chosen the best response.0Ok. Thank you all. I was not suppose to do questions related with pH yet. Thank you for clearing that up.

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.0You are welcome friend!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.