IsTim
  • IsTim
The hydroxide ion concentration in a 0.157 mol/L solution of sodium propanoate, NaC3H5O2 (aq) is found to be 1.1*10^-5 mol/L. Calculate the base ionization constant for the propanoate ion.
Chemistry
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SOLVED
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katieb
  • katieb
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IsTim
  • IsTim
I am using the Formula Ka*Kb=Kw. Rearranged then into Kb=Kw/Ka. Kw is a constant; 1.0*10^-14. Originally attempted using formula Kw=[H30}{OH^-}. Answer was 9.09*10^-10. Actual answer is 7.7*10^-10.
IsTim
  • IsTim
@saifoo.khan @Hero @ParthKohli
IsTim
  • IsTim
Finally, got some people.

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More answers

Hero
  • Hero
What world am I in? Chemistry? Really? Sorry I'm not the guy.
IsTim
  • IsTim
@.Sam. @Callisto
anonymous
  • anonymous
that's the salt of a strong base and a weak acid.....
IsTim
  • IsTim
Sodium propanoate?
anonymous
  • anonymous
base ionization constant means PoH?
IsTim
  • IsTim
I don't think so, but it's mentioned in this part of the textbook.
anonymous
  • anonymous
so ther's some other formula to calculate that i suppose.......
anonymous
  • anonymous
yes thats the PoH and 1st one is pH(Hydrogen Concentration)
IsTim
  • IsTim
So far, I attempted to use Kw=[H3O][OH], kakb=kw and kb=[HB][OH]/[B]
anonymous
  • anonymous
please have a look on http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/Calculating_pHandpOH.htm
anonymous
  • anonymous
2ph=14+pka+logc @25 degree c
anonymous
  • anonymous
use that.....u l get it....
IsTim
  • IsTim
Sorry, which formula did oyu use? (Best use the equation editor or draw it out to get the message across)
anonymous
  • anonymous
help ur self......
IsTim
  • IsTim
Wait, is this question related any way to pH Also, that was a rather rude way to brush me off.
anonymous
  • anonymous
yes
anonymous
  • anonymous
http://herh.ccrsb.ca/staff/FarrellL/chem12/acids/acid-base-review-answers.pdf
IsTim
  • IsTim
Ok. Thank you all. I was not suppose to do questions related with pH yet. Thank you for clearing that up.
anonymous
  • anonymous
ur welcome
anonymous
  • anonymous
You are welcome friend!

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