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zaphod

Simplify

  • one year ago
  • one year ago

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  1. zaphod
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    \[\frac{\sqrt{6}}{\sqrt{2}} + \frac{3}{\sqrt{3}} + \frac{\sqrt{15}}{\sqrt{5}} +\frac{\sqrt{18}}{\sqrt{6}}\]

    • one year ago
  2. waterineyes
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    Remember one thing: \[\large \color{green}{\frac{\sqrt{x}}{\sqrt{y}} = \sqrt{\frac{x}{y}}}\]

    • one year ago
  3. waterineyes
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    So for first term apply this formula... and tell me what do you get..??

    • one year ago
  4. waterineyes
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    @mathslover will suggest you to take the rationalization process I guess..

    • one year ago
  5. mathslover
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    \[\large{\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{\frac{6}{2}}}\] \[\large{\sqrt{6}=\sqrt{3}}\] \[\large{\frac{3}{\sqrt{3}}}\]Now rationalizing the above expression

    • one year ago
  6. waterineyes
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    Every term will contain 3 after solving Strange WOW..

    • one year ago
  7. zaphod
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    yes i get it, but then how do i simplify later

    • one year ago
  8. mathslover
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    sorry i meant : \(\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{3}\)

    • one year ago
  9. zaphod
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    yes there are three terms like that and the other one 3/root 3

    • one year ago
  10. waterineyes
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    What do you get show us first..

    • one year ago
  11. mathslover
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    |dw:1342950785620:dw|

    • one year ago
  12. zaphod
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    root 3 + root 3 + root 3 + 3/ root 3

    • one year ago
  13. mathslover
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    Yes right

    • one year ago
  14. waterineyes
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    Oh sorry..

    • one year ago
  15. waterineyes
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    Take the LCD..

    • one year ago
  16. zaphod
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    then it becomes 3 root 3 + 3/root 3

    • one year ago
  17. waterineyes
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    LCD = root(3)

    • one year ago
  18. zaphod
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    i get it thanks :)

    • one year ago
  19. zaphod
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    we have to rationalize later :)

    • one year ago
  20. waterineyes
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    Take the LCM and then we will do rationalization..

    • one year ago
  21. waterineyes
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    Yes you are absolutely correct @zaphod

    • one year ago
  22. zaphod
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    thanks alot :) guys

    • one year ago
  23. mathslover
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    Now rationalizing \(\huge{\frac{3}{\sqrt{3}}}\) = \(\huge{\frac{3*\sqrt{3}}{\sqrt{3}*\sqrt{3}}}\) \[\huge{\frac{\sqrt{3}\cancel{3}^1}{\cancel{3}^1}}\] \[\huge{\sqrt{3}}\]

    • one year ago
  24. waterineyes
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    Or if you take rationalization process first then you need not to take LCD..

    • one year ago
  25. waterineyes
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    |dw:1342951138950:dw|

    • one year ago
  26. waterineyes
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    Did you understand how to do this?? @zaphod

    • one year ago
  27. zaphod
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    i got the answer

    • one year ago
  28. waterineyes
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    My question is not about the answer.. I said did you get how to do this??

    • one year ago
  29. zaphod
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    yes i got it

    • one year ago
  30. waterineyes
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    That is nice..

    • one year ago
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