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zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{6}}{\sqrt{2}} + \frac{3}{\sqrt{3}} + \frac{\sqrt{15}}{\sqrt{5}} +\frac{\sqrt{18}}{\sqrt{6}}\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Remember one thing: \[\large \color{green}{\frac{\sqrt{x}}{\sqrt{y}} = \sqrt{\frac{x}{y}}}\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1So for first term apply this formula... and tell me what do you get..??

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1@mathslover will suggest you to take the rationalization process I guess..

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large{\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{\frac{6}{2}}}\] \[\large{\sqrt{6}=\sqrt{3}}\] \[\large{\frac{3}{\sqrt{3}}}\]Now rationalizing the above expression

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Every term will contain 3 after solving Strange WOW..

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1yes i get it, but then how do i simplify later

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0sorry i meant : \(\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{3}\)

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1yes there are three terms like that and the other one 3/root 3

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1What do you get show us first..

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1342950785620:dw

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1root 3 + root 3 + root 3 + 3/ root 3

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1then it becomes 3 root 3 + 3/root 3

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.1we have to rationalize later :)

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Take the LCM and then we will do rationalization..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Yes you are absolutely correct @zaphod

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0Now rationalizing \(\huge{\frac{3}{\sqrt{3}}}\) = \(\huge{\frac{3*\sqrt{3}}{\sqrt{3}*\sqrt{3}}}\) \[\huge{\frac{\sqrt{3}\cancel{3}^1}{\cancel{3}^1}}\] \[\huge{\sqrt{3}}\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Or if you take rationalization process first then you need not to take LCD..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1342951138950:dw

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Did you understand how to do this?? @zaphod

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1My question is not about the answer.. I said did you get how to do this??
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