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zaphodBest ResponseYou've already chosen the best response.1
\[\frac{\sqrt{6}}{\sqrt{2}} + \frac{3}{\sqrt{3}} + \frac{\sqrt{15}}{\sqrt{5}} +\frac{\sqrt{18}}{\sqrt{6}}\]
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Remember one thing: \[\large \color{green}{\frac{\sqrt{x}}{\sqrt{y}} = \sqrt{\frac{x}{y}}}\]
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
So for first term apply this formula... and tell me what do you get..??
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
@mathslover will suggest you to take the rationalization process I guess..
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
\[\large{\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{\frac{6}{2}}}\] \[\large{\sqrt{6}=\sqrt{3}}\] \[\large{\frac{3}{\sqrt{3}}}\]Now rationalizing the above expression
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Every term will contain 3 after solving Strange WOW..
 one year ago

zaphodBest ResponseYou've already chosen the best response.1
yes i get it, but then how do i simplify later
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
sorry i meant : \(\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{3}\)
 one year ago

zaphodBest ResponseYou've already chosen the best response.1
yes there are three terms like that and the other one 3/root 3
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
What do you get show us first..
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
dw:1342950785620:dw
 one year ago

zaphodBest ResponseYou've already chosen the best response.1
root 3 + root 3 + root 3 + 3/ root 3
 one year ago

zaphodBest ResponseYou've already chosen the best response.1
then it becomes 3 root 3 + 3/root 3
 one year ago

zaphodBest ResponseYou've already chosen the best response.1
we have to rationalize later :)
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Take the LCM and then we will do rationalization..
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Yes you are absolutely correct @zaphod
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
Now rationalizing \(\huge{\frac{3}{\sqrt{3}}}\) = \(\huge{\frac{3*\sqrt{3}}{\sqrt{3}*\sqrt{3}}}\) \[\huge{\frac{\sqrt{3}\cancel{3}^1}{\cancel{3}^1}}\] \[\huge{\sqrt{3}}\]
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Or if you take rationalization process first then you need not to take LCD..
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
dw:1342951138950:dw
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Did you understand how to do this?? @zaphod
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
My question is not about the answer.. I said did you get how to do this??
 one year ago
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