## ParthKohli Group Title Hello! This is a general Math question. Based on my past experience, am I ready for Calculus? 2 years ago 2 years ago

1. Spacelimbus Group Title

@ParthKohli, without a doubt.

2. nitz Group Title

ya............mr.intelligent......

3. hoya Group Title

you are! haha-

4. ParthKohli Group Title

Hmm, thanks for flattering. I want more answers with a detail.

5. ParthKohli Group Title

And I doubt if you guys know my past experience :P

6. Compassionate Group Title

Parth, I will tutor you on Calculus for free if you want a good introduction and help.

7. Spacelimbus Group Title

8. ash2326 Group Title

@ParthKohli To learn calculus you should be well versed in Logarithms, Trigonometry, and Sets. Have you learned all these?

9. mathdumbo Group Title

I felt Calc I was like 75% Algebra and 20% Trig...pretty sure it will be easy for someone like you

10. ParthKohli Group Title

Thank you. Yes, @ash2326

11. agentx5 Group Title

Calculus is MOSTLY Algebra, just FYI. ;-)

12. agentx5 Group Title

Speaking from direct experience.

13. ash2326 Group Title

14. Compassionate Group Title

Parth, do you have knowledge in Trig, Algebra I-II, and working with functions?

15. ParthKohli Group Title

I went to a website and learned all these concepts very thoroughly. What is the starting in Calculus? Limits?

16. hoya Group Title

math is hard keke ayiyi

17. ParthKohli Group Title

@Compassionate I do.

18. mathdumbo Group Title

It depends on the school. At MIT, we started with Integrals first and defined limits based on that.

19. vikrantg4 Group Title

Calculus will come next year in my syllabus lol :P

20. ash2326 Group Title

Functions->Limits->Continuity->DIfferentiability->Differentiation->Integration

21. Compassionate Group Title

You're ready, Parth. If you wouldn't mind taking a few minutes out of your time today, and send me what you know and give me some examples. I can take that information and place you at a level. :) And like I said, "I can tutor you."

22. agentx5 Group Title

And when I say that it is mostly, I mean that you'll REALLY need to be good with it. Everything from factoring, to trig identities, to partial fractions, to series and sequences, to things like this: |dw:1342968425801:dw|

23. ParthKohli Group Title

Derivative is small change in $$y$$ - known as $$dy$$ - over the small change in $$x$$ - known as $$dx$$.

24. agentx5 Group Title

You see this stuff over and over in Calculus

25. ash2326 Group Title

@mathdumbo That's a nice way:D

26. ParthKohli Group Title

Integral is a number of which something is a derivative of(as far as I know).

27. vikrantg4 Group Title

not a number but function.. :P

28. ash2326 Group Title

@ParthKohli You'll get a good start here http://ocw.mit.edu/high-school/calculus/

29. agentx5 Group Title

Average slope: $m=\frac{\triangle y}{\triangle x}=\frac{y_2-y_1}{x_2-x_1}$ Turns into... $m=\frac{d y}{d x}=\text{instantaneous slope}$

30. ParthKohli Group Title

So, $\int \limits {2xdx } = x^2$?

31. ParthKohli Group Title

Yes, @agentx5. I saw a video on Khanacademy on the intuition of differentiation.

32. ParthKohli Group Title

And I believe that you are allowed to 'skip' some of the topics in Mathematics; that's how beautiful it is :)

33. Compassionate Group Title

Parth, how would you solve this: ${2 - 5x \sqrt23}{-3x \sqrt2}$

34. Compassionate Group Title

^ You need to have a background with working on radicals.

35. ParthKohli Group Title

I believe that we should stick to the question, and yes I do know that :)

36. Compassionate Group Title

There is a lot of really small division in calculus.

37. ParthKohli Group Title

I don't think we can simplify that.

38. Compassionate Group Title

And by small, I mean integrals.

39. Compassionate Group Title

It was just an example.

40. vikrantg4 Group Title

I have heard that we can calculate "nth" root of any number by differentiation. Am I correct ?

41. agentx5 Group Title

You can move the constant out front: $$\large\int \limits {2x \ \ dx } = 2\int x \ \ dx = 2[\frac{x^{1+1}}{1+1}] + C = \cancel{2} * \frac{x^2}{\cancel{2}} + C = x^2 + C$$

42. 91 Group Title

Parth, don't forget the C

43. ParthKohli Group Title

Yep, because the derivative of any constant is 0, and $$x + 0 = x$$.

44. agentx5 Group Title

The "C" means some constant. Why put it on indefinite integrals? Because $$\frac{d}{dx}$$ constant = 0

45. agentx5 Group Title

You got it lol :-D

46. ParthKohli Group Title

I am just starting it ;)

47. ParthKohli Group Title

Thank you, all! You are a great help!

48. ParthKohli Group Title

49. agentx5 Group Title

Limits.

50. ParthKohli Group Title

Any resource?

51. 91 Group Title

parth,I learn it on MIT , and Khanacedemy

52. agentx5 Group Title
53. agentx5 Group Title

That is a phenomenal reference.

54. 91 Group Title

also , this awesome book

55. ParthKohli Group Title

Hah! Paul's Notes! I find it a little difficult to start with the basics on that.

56. ParthKohli Group Title

P.S. I learned my logs and trig on there. :)

57. vikrantg4 Group Title

Try E-book "Calculus for dummies"

58. 91 Group Title
59. 91 Group Title

That book help me a lot

60. agentx5 Group Title

Parth try this one! ^_^ $\huge \lim_{x \rightarrow 0} \frac{1}{x-1}$ and $\huge \lim_{x \rightarrow 1} \frac{1}{x-1}$ and $\huge \lim_{x \rightarrow \infty} \frac{1}{x-1}$ Do it visually :-D (draw a graph with arrows & stuff)

61. agentx5 Group Title

Try it @ParthKohli :-D It's not a hard problem, it just makes you think and once you get the concepts down it just goes back to Algebra tricks for the most part. hint: What happens if the x = 1 to the denominator?

62. ParthKohli Group Title

I find these as the answers: 1) $$-1$$ 2) $$\infty$$ 3) $$\infty$$ You use L'Hopital's Rule.

63. ParthKohli Group Title

You may do it visually by taking the numbers closer to the number which it is approaching.

64. agentx5 Group Title

Aww come on draw it! ^_^ Make a sketch

65. ParthKohli Group Title

|dw:1342969380728:dw|

66. ParthKohli Group Title

Hmm. There's a thing that I am missing: CONIC SECTIONS.

67. ParthKohli Group Title

Would I be able to do Calculus without conic sections?

68. agentx5 Group Title

Incorrect @ParthKohli |dw:1342970148488:dw| Correct answers are: $$\huge \lim_{x \rightarrow 0} \frac{1}{x-1} = -1$$ $$\huge \lim_{x \rightarrow 1} \frac{1}{x-1} = \text{Does NOT exist.}$$ $$\huge \lim_{x \rightarrow \infty} \frac{1}{x-1} = 0$$ You cannot use the l'Hospital's rule unless after simplification you still have a $$\large \frac{\pm\ \infty}{\pm\ \infty}$$ or $$\large \frac{0}{0}$$ form when you go to substitute.

69. agentx5 Group Title

This is why sketching/graphing things visually is so helpful in Calculus :-D

70. ParthKohli Group Title

Hmm—you should have included that I am a beginner too :)

71. agentx5 Group Title

72. agentx5 Group Title

Hey no worries, we all have to learn to fly sometime right? ^_^

73. ParthKohli Group Title

Isn't 'Does NOT Exist' just infinity?

74. agentx5 Group Title

Actually, no, take a closer look. The limit is as if you're taking your right and left hand and tracing the function from both points towards whatever the limit is approaching. In the case of the first one, it's clearly approaching -1 from both the right and left. But in the second one, it goes on way up to infinity, and the other way down to negative infinity. It creates a kind of a paradox, it can't be both and yet it is. So the limit simply doesn't exist. Here's an example where the limit is infinity: $\huge \lim_{x \rightarrow \infty} x^2 = \infty$ |dw:1342970876711:dw|

75. ParthKohli Group Title

Oh!

76. agentx5 Group Title

$$\huge \lim_{x \rightarrow 1} | \frac{1}{x-1} | = \infty$$ |dw:1342971089127:dw|

77. agentx5 Group Title

^_^ Make more sense now?

78. ParthKohli Group Title

I, for once, believe in visual techniques :)

79. agentx5 Group Title

Amen brotha! ;-P

80. ParthKohli Group Title

Heh! That was so clear :')

81. agentx5 Group Title

And don't forget you can't just use l'Hostpital's rule whenever you feel like it, it's got to meet the prerequisites of the theorem that I mentioned above :-)