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Hello! This is a general Math question.
Based on my past experience, am I ready for Calculus?
 one year ago
 one year ago
Hello! This is a general Math question. Based on my past experience, am I ready for Calculus?
 one year ago
 one year ago

This Question is Closed

SpacelimbusBest ResponseYou've already chosen the best response.0
@ParthKohli, without a doubt.
 one year ago

nitzBest ResponseYou've already chosen the best response.0
ya............mr.intelligent......
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Hmm, thanks for flattering. I want more answers with a detail.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
And I doubt if you guys know my past experience :P
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
Parth, I will tutor you on Calculus for free if you want a good introduction and help.
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
calculus is only an expansion of algebra, guess that includes your answer already.
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
@ParthKohli To learn calculus you should be well versed in Logarithms, Trigonometry, and Sets. Have you learned all these?
 one year ago

mathdumboBest ResponseYou've already chosen the best response.0
I felt Calc I was like 75% Algebra and 20% Trig...pretty sure it will be easy for someone like you
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Thank you. Yes, @ash2326
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Calculus is MOSTLY Algebra, just FYI. ;)
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Speaking from direct experience.
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
Parth, do you have knowledge in Trig, Algebra III, and working with functions?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I went to a website and learned all these concepts very thoroughly. What is the starting in Calculus? Limits?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
@Compassionate I do.
 one year ago

mathdumboBest ResponseYou've already chosen the best response.0
It depends on the school. At MIT, we started with Integrals first and defined limits based on that.
 one year ago

vikrantg4Best ResponseYou've already chosen the best response.0
Calculus will come next year in my syllabus lol :P
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
Functions>Limits>Continuity>DIfferentiability>Differentiation>Integration
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
You're ready, Parth. If you wouldn't mind taking a few minutes out of your time today, and send me what you know and give me some examples. I can take that information and place you at a level. :) And like I said, "I can tutor you."
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
And when I say that it is mostly, I mean that you'll REALLY need to be good with it. Everything from factoring, to trig identities, to partial fractions, to series and sequences, to things like this: dw:1342968425801:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Derivative is small change in \(y\)  known as \(dy\)  over the small change in \(x\)  known as \(dx\).
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
You see this stuff over and over in Calculus
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
@mathdumbo That's a nice way:D
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Integral is a number of which something is a derivative of(as far as I know).
 one year ago

vikrantg4Best ResponseYou've already chosen the best response.0
not a number but function.. :P
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
@ParthKohli You'll get a good start here http://ocw.mit.edu/highschool/calculus/
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Average slope: \[m=\frac{\triangle y}{\triangle x}=\frac{y_2y_1}{x_2x_1}\] Turns into... \[m=\frac{d y}{d x}=\text{instantaneous slope}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
So, \[\int \limits {2xdx } = x^2\]?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Yes, @agentx5. I saw a video on Khanacademy on the intuition of differentiation.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
And I believe that you are allowed to 'skip' some of the topics in Mathematics; that's how beautiful it is :)
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
Parth, how would you solve this: \[{2  5x \sqrt23}{3x \sqrt2}\]
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
^ You need to have a background with working on radicals.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I believe that we should stick to the question, and yes I do know that :)
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
There is a lot of really small division in calculus.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I don't think we can simplify that.
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
And by small, I mean integrals.
 one year ago

CompassionateBest ResponseYou've already chosen the best response.0
It was just an example.
 one year ago

vikrantg4Best ResponseYou've already chosen the best response.0
I have heard that we can calculate "nth" root of any number by differentiation. Am I correct ?
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
You can move the constant out front: \(\large\int \limits {2x \ \ dx } = 2\int x \ \ dx = 2[\frac{x^{1+1}}{1+1}] + C = \cancel{2} * \frac{x^2}{\cancel{2}} + C = x^2 + C\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Yep, because the derivative of any constant is 0, and \(x + 0 = x\).
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
The "C" means some constant. Why put it on indefinite integrals? Because \(\frac{d}{dx}\) constant = 0
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I am just starting it ;)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Thank you, all! You are a great help!
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
What concept should I start with?
 one year ago

91Best ResponseYou've already chosen the best response.0
parth,I learn it on MIT , and Khanacedemy
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Yes: http://tutorial.math.lamar.edu/sitemap.aspx
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
That is a phenomenal reference.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Hah! Paul's Notes! I find it a little difficult to start with the basics on that.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
P.S. I learned my logs and trig on there. :)
 one year ago

vikrantg4Best ResponseYou've already chosen the best response.0
Try Ebook "Calculus for dummies"
 one year ago

91Best ResponseYou've already chosen the best response.0
http://ocw.mit.edu/ans7870/resources/Strang/Edited/Calculus/Calculus.pdf
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Parth try this one! ^_^ \[\huge \lim_{x \rightarrow 0} \frac{1}{x1}\] and \[\huge \lim_{x \rightarrow 1} \frac{1}{x1}\] and \[\huge \lim_{x \rightarrow \infty} \frac{1}{x1}\] Do it visually :D (draw a graph with arrows & stuff)
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Try it @ParthKohli :D It's not a hard problem, it just makes you think and once you get the concepts down it just goes back to Algebra tricks for the most part. hint: What happens if the x = 1 to the denominator?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I find these as the answers: 1) \(1\) 2) \(\infty \) 3) \(\infty\) You use L'Hopital's Rule.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
You may do it visually by taking the numbers closer to the number which it is approaching.
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Aww come on draw it! ^_^ Make a sketch
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
dw:1342969380728:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Hmm. There's a thing that I am missing: CONIC SECTIONS.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Would I be able to do Calculus without conic sections?
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Incorrect @ParthKohli dw:1342970148488:dw Correct answers are: \(\huge \lim_{x \rightarrow 0} \frac{1}{x1} = 1\) \(\huge \lim_{x \rightarrow 1} \frac{1}{x1} = \text{Does NOT exist.}\) \(\huge \lim_{x \rightarrow \infty} \frac{1}{x1} = 0\) You cannot use the l'Hospital's rule unless after simplification you still have a \(\large \frac{\pm\ \infty}{\pm\ \infty}\) or \(\large \frac{0}{0}\) form when you go to substitute.
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
This is why sketching/graphing things visually is so helpful in Calculus :D
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Hmm—you should have included that I am a beginner too :)
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
I had to get lunch, sry about the delay
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Hey no worries, we all have to learn to fly sometime right? ^_^
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Isn't 'Does NOT Exist' just infinity?
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
Actually, no, take a closer look. The limit is as if you're taking your right and left hand and tracing the function from both points towards whatever the limit is approaching. In the case of the first one, it's clearly approaching 1 from both the right and left. But in the second one, it goes on way up to infinity, and the other way down to negative infinity. It creates a kind of a paradox, it can't be both and yet it is. So the limit simply doesn't exist. Here's an example where the limit is infinity: \[\huge \lim_{x \rightarrow \infty} x^2 = \infty\] dw:1342970876711:dw
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
\(\huge \lim_{x \rightarrow 1}  \frac{1}{x1}  = \infty\) dw:1342971089127:dw
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
^_^ Make more sense now?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I, for once, believe in visual techniques :)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Heh! That was so clear :')
 one year ago

agentx5Best ResponseYou've already chosen the best response.1
And don't forget you can't just use l'Hostpital's rule whenever you feel like it, it's got to meet the prerequisites of the theorem that I mentioned above :)
 one year ago
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