A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Find the limit. lim x>3. sqrt(x+1)/x4
anonymous
 3 years ago
Find the limit. lim x>3. sqrt(x+1)/x4

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1342982402887:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got 2.. is that right @apoorvk

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is +2 or 2 depending on the what you take as sqrt ( 4)= [ 2 or 2]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got 2 as my answer..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well the square root of 4 is 2.... so

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But we have to divide by 1. SO i got 2 @quarkine

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer is 2 u r Quite right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but cant sqrt 4 be taken as 2 as well??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we consider \( y=\sqrt{x+1} \) as a function so for a given x u have a unique y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1342983149196:dw

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1yes @mukushla you're right!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm yeah... thought of that but here it wasnt said anything about a single valued function..

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1and @schmidtdancer you too with 2!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.