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IsTimBest ResponseYou've already chosen the best response.0
Are we suppose to find the derivative of its sight?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
maybe the integral of its periphery
 one year ago

AnkoretBest ResponseYou've already chosen the best response.0
Supposed to find "the vertical angle subtended by the billboard at her eye in terms of x" and also the distance the cow must be standing from the billboard to maximize the first thing.
 one year ago

mickifree12Best ResponseYou've already chosen the best response.0
is this an optimization problem?
 one year ago

mickifree12Best ResponseYou've already chosen the best response.0
also it would help if you gave us more information
 one year ago

AnkoretBest ResponseYou've already chosen the best response.0
yes, optimization. hang on, getting more info.
 one year ago

AnkoretBest ResponseYou've already chosen the best response.0
Rectangular billboard 5 ft in height is 12 ft above the ground. Nearsighted cow with eye level at 4 ft above ground stands x ft from the billboard. Express theta in terms of x, then find the distance the cow must stand from the billboard in order to maximize theta.
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
dw:1343007462718:dw
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
Behold! My drawing skills!
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
Anyway, since it is barely decipherable, I will add what I think is best to do. I have chosen f(x) to be the angle in which the cow sees the board, y_2 should be the entire angle since there should be substitutions involved. \[ y_2=f(x)+y_1 \rightarrow f(x)=y_2y_1 \] now for the angles \[ \tan(y_1)=\frac{8}{x} \rightarrow y_1 = \tan^{1}\left(\frac{8}{x}\right)\] and \[ \tan(y_2)=\frac{11}{x} \rightarrow y_2=\tan^{1} \left(\frac{11}{x}\right)\]
 one year ago

SpacelimbusBest ResponseYou've already chosen the best response.0
the rest is calculus,\[ f'(x)=0 \\ f''(x)<0 \longrightarrow \text{Max}\]
 one year ago
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