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Kathatesmath94
Group Title
Angelina has a lawn, ABCD. She has placed a watering hose, BD, as shown below.
Part A: Angelina plans to put a fence along the length AD of her lawn. What is the length of the fence required?
Part B: Using complete sentences, explain how you arrived at the answer for Part A.
 one year ago
 one year ago
Kathatesmath94 Group Title
Angelina has a lawn, ABCD. She has placed a watering hose, BD, as shown below. Part A: Angelina plans to put a fence along the length AD of her lawn. What is the length of the fence required? Part B: Using complete sentences, explain how you arrived at the answer for Part A.
 one year ago
 one year ago

This Question is Closed

Hero Group TitleBest ResponseYou've already chosen the best response.0
Hi Katlovesmath94
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
hahah hey :)
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I'll let outkast explain since he is so eager
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
can you help me with this? I am not sure where to start and I am suppose to explain it
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
For the triangle BCD you are given two of the sides and you can use Pythagorean's theorem to find the third side, the length of side BD. Once you have that, side BD and the 60degree angle given can be used in a trig function (sine, cosine, or tangent  which one?) to find out the length of side AD.
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
soooo I am still confused what am I doing?
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Step one: look at the triangle BCD. You are given two sides, correct? Let's find the third side, BD. How do we find the third side of a right triangle? Using Pythagorean's theorem. Are you familiar with Pythagorean's theorem? a^2 + b^2 = c^2 ?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
yes
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
what am I putting in the pathagoreum therum formula
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
dw:1343004042674:dw
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Looks like a good explanation going on here so far.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
There are 3 sides in a triangle. You are given two of them: 35 ft and 12 ft. Pythagorean's theorem \[a ^{2}+b ^{2}=c ^{2}\] means you can take those two sides you already know and plug them into "a" and "b" then solve for "c." Try it out. What do you get?
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
"c" here is just a generic variable, like x. In your picture, "c" represents the side BD of the triangle. So if you solve for c, you've solved for the length of side BD.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Do you got it? Or are you still confused on how to use the theorem to get the length of side BD?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
no I am still lost not gonna lie I have been working on this for twenty minutes and I am not sure what I am doing
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
like I tried the pathegorium thing and I got some rediculas numbers in the thousands
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
I am just frustrated with this problem
 one year ago

J.L. Group TitleBest ResponseYou've already chosen the best response.0
When you got the large numbers had you already taken the square root of the number?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
no i just did the pathagorium thing squared them and then what i have two huge number equal to c^2
 one year ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
what are you plugging in for Pythagoras theorem?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
the 35 and 12
 one year ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
alright that's good. You are doing the right thing. \[12^2+35^2=c^2\]\[144+1225=c^2\]\[1369=c^2\]
 one year ago

Romero Group TitleBest ResponseYou've already chosen the best response.1
now square root both sides....what do you get then?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
37?
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Good job! So c = 37 means the length of side BD in your picture is 37 feet.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
We are done with triangle BCD. Now look at the next triangle, ABD.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
You are given one angle and one side. We can use a trig function to solve for side AD, which is what you need.
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
tan60
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Perfect. Do you know the trick to remember the trig functions, SOH CAH TOA? SOH: sin(angle)=opposite/hypotenuse CAH: cos(angle)=adjacent/hypotenuse TOA: tan(angle)=opposite/adjacent.
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
yes
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
So tan(60)=opposite/adjacent. What is the side that is opposite of the 60degree angle? It's the side BD, which you just found out is 37 feet. And what is the side adjacent (or next to) the 60degree angle? That's the one you're solving for, side AD. So tan(60)=opposite/adjacent=60/AD tan(60)=60/AD Solve for AD. Do you know how to do that?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
opposite is 35 but what is the adjacent? 37?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
oh you multiply AD to both sides
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
The 35 is not the opposite side; that's the OTHER triangle; we aren't looking at that triangle at all anymore. We are looking for the opposite side of this small triangle ABD. The opposite of the 60degree angle in that small triangle is the length BD. BD = 37 feet according to your calculation.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
OH my bad, I mean tan(60)=37/AD
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
you still multiply AD to both sides right
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
tan(60) = opposite/adjacent = 37 / AD
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
So multiplying both sides by AD gives you (AD) tan(60) = 37. Then divide each side by tan(6), so you get AD = 37 / tan(60)
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
You should get something in the 20s for your answer for AD if you calculate the tan(60).
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Does it make sense?
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
21.361
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Perfect. Good job :)
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
If you practice problems like this over and over they get easier.
 one year ago

mbradar2 Group TitleBest ResponseYou've already chosen the best response.1
Sorry about a couple of my typos there.
 one year ago

Kathatesmath94 Group TitleBest ResponseYou've already chosen the best response.0
thank goodness that is over lol sorry I was just frustrated I didnt understand how the big number in the pathagorium therum was working
 one year ago
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