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Kathatesmath94
Angelina has a lawn, ABCD. She has placed a watering hose, BD, as shown below. Part A: Angelina plans to put a fence along the length AD of her lawn. What is the length of the fence required? Part B: Using complete sentences, explain how you arrived at the answer for Part A.
I'll let outkast explain since he is so eager
can you help me with this? I am not sure where to start and I am suppose to explain it
For the triangle BCD you are given two of the sides and you can use Pythagorean's theorem to find the third side, the length of side BD. Once you have that, side BD and the 60-degree angle given can be used in a trig function (sine, cosine, or tangent -- which one?) to find out the length of side AD.
soooo I am still confused what am I doing?
Step one: look at the triangle BCD. You are given two sides, correct? Let's find the third side, BD. How do we find the third side of a right triangle? Using Pythagorean's theorem. Are you familiar with Pythagorean's theorem? a^2 + b^2 = c^2 ?
what am I putting in the pathagoreum therum formula
Looks like a good explanation going on here so far.
There are 3 sides in a triangle. You are given two of them: 35 ft and 12 ft. Pythagorean's theorem \[a ^{2}+b ^{2}=c ^{2}\] means you can take those two sides you already know and plug them into "a" and "b" then solve for "c." Try it out. What do you get?
"c" here is just a generic variable, like x. In your picture, "c" represents the side BD of the triangle. So if you solve for c, you've solved for the length of side BD.
Do you got it? Or are you still confused on how to use the theorem to get the length of side BD?
no I am still lost not gonna lie I have been working on this for twenty minutes and I am not sure what I am doing
like I tried the pathegorium thing and I got some rediculas numbers in the thousands
I am just frustrated with this problem
When you got the large numbers had you already taken the square root of the number?
no i just did the pathagorium thing squared them and then what i have two huge number equal to c^2
what are you plugging in for Pythagoras theorem?
alright that's good. You are doing the right thing. \[12^2+35^2=c^2\]\[144+1225=c^2\]\[1369=c^2\]
now square root both sides....what do you get then?
Good job! So c = 37 means the length of side BD in your picture is 37 feet.
We are done with triangle BCD. Now look at the next triangle, ABD.
You are given one angle and one side. We can use a trig function to solve for side AD, which is what you need.
Perfect. Do you know the trick to remember the trig functions, SOH CAH TOA? SOH: sin(angle)=opposite/hypotenuse CAH: cos(angle)=adjacent/hypotenuse TOA: tan(angle)=opposite/adjacent.
So tan(60)=opposite/adjacent. What is the side that is opposite of the 60-degree angle? It's the side BD, which you just found out is 37 feet. And what is the side adjacent (or next to) the 60-degree angle? That's the one you're solving for, side AD. So tan(60)=opposite/adjacent=60/AD tan(60)=60/AD Solve for AD. Do you know how to do that?
opposite is 35 but what is the adjacent? 37?
oh you multiply AD to both sides
The 35 is not the opposite side; that's the OTHER triangle; we aren't looking at that triangle at all anymore. We are looking for the opposite side of this small triangle ABD. The opposite of the 60-degree angle in that small triangle is the length BD. BD = 37 feet according to your calculation.
OH my bad, I mean tan(60)=37/AD
you still multiply AD to both sides right
tan(60) = opposite/adjacent = 37 / AD
So multiplying both sides by AD gives you (AD) tan(60) = 37. Then divide each side by tan(6), so you get AD = 37 / tan(60)
You should get something in the 20s for your answer for AD if you calculate the tan(60).
If you practice problems like this over and over they get easier.
Sorry about a couple of my typos there.
thank goodness that is over lol sorry I was just frustrated I didnt understand how the big number in the pathagorium therum was working