Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Select the system of equations that corresponds to the given graph. 4x + y = 6 6x + 3y = 6 −3x + y = 2 4x + 2y = 4 2x + y = 4 6x + 3y = 12 4x + 2y = 6 6x + 3y = 12 I can't get a picture but the graph is crossing at (1.5, 3) and (2, 4) Thanks :D

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
how can it cross two points?
If it cross more than one point then I assume that there an infinite number of solutions. are the two lines on top of each other?
It is parallel

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I got a screenshot
Any ideas?
they never cross
My bad sorry.
What you can do is find the slope of each of the two lines given in each solution and compare. We know that two parallel lines have the same slope so find the ones that have the same slope
If you have no idea how to find the slope set them into y-intercept form \[y=mx+b\]
where m is the slope.

Not the answer you are looking for?

Search for more explanations.

Ask your own question