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anonymous
 4 years ago
#9 Please
anonymous
 4 years ago
#9 Please

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto @Calcmathlete @sritama

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SAS, ASA both of them.

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Please give reason to your choice.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait me.. ok.. I said its ASA becausedw:1343019548584:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0RT is perpendicular to QS..so, ,<RTQ=<RTS=90 degree.. <Q=<S, RT is the common side..it is for asa

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0understand little bit :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but,if it is not said that whether RT is perpendicular to QS, better to go for sas

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1343019738889:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1343019841179:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i didn't get your question @Trexy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait.. which one is the best SAS or ASA?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SAS S = common side A = given angle S = issoceles triangle theorem (sides opposite to congruent angles are congruet)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you thats explain better

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and also this is AAA or AAS.. im debating?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AAA my bad, coz if 2 angles are equal the third should be equal

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Please start a new post for a new question. Thanks.
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