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f(x)=(-3x^2)+13x-11

Mathematics
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What are you supposed to do with this? Graph it?
no
What then? You haven't posted the directions.

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Other answers:

Find roots?
how to complete a square
yep
Hint: Since y = f(x), rewrite it like this: \(y = -3x^2 + 3x - 11\) Next add 11 to both sides, then divide divide both sides by -3 to get: \(\frac{y + 11}{-3} = x^2 - x\) Now add \(\frac{1}{16}\) to both sides to get: \(\frac{y + 11}{-3} + \frac{1}{16} = x^2 - x + \frac{1}{16}\) Once you have finished reducing, you should have a new expression for y
is that the answer
?
The final result I get comes out to \(y = -\large\frac{48(x-\frac{1}{4}^2) - 3}{16} - 11\)
But that hasn't been simplified
How is that better than what he wrote originally?
Because it said to complete the square
Once you complete the square, you have to put it back in the form y =
But let me fix one minor mistake
\(y = -\large\frac{48(x-\frac{1}{4})^2 - 3}{16} - 11\)
ok
Ideally, I think you would want to express that as just one fraction.
yes
Well, I did most of the work for you. You can finish the rest.
Also, you might want to change y back to f(x)
ok sure
yes
\(f(x) = -\large3(x-\frac{1}{4})^2 - \frac{179}{16}\)
THANKS
hero
I must have made a calculation mistake because here's wolfram alpha's result: http://www.wolframalpha.com/input/?i=complete%20square%20(%5B%2F%2Fquantity%3A-3%2F%2F%5D)x%5E2%2B(%5B%2F%2Fquantity%3A13%2F%2F%5D)x%2B(%5B%2F%2Fquantity%3A-11%2F%2F%5D)
Yeah, I see where I went wrong. I added 1/16 to both sides instead of adding 1/4 to both sides
ok

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