anonymous
  • anonymous
f(x)=(-3x^2)+13x-11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Hero
  • Hero
What are you supposed to do with this? Graph it?
anonymous
  • anonymous
no
Hero
  • Hero
What then? You haven't posted the directions.

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More answers

zepp
  • zepp
Find roots?
anonymous
  • anonymous
how to complete a square
anonymous
  • anonymous
yep
Hero
  • Hero
Hint: Since y = f(x), rewrite it like this: \(y = -3x^2 + 3x - 11\) Next add 11 to both sides, then divide divide both sides by -3 to get: \(\frac{y + 11}{-3} = x^2 - x\) Now add \(\frac{1}{16}\) to both sides to get: \(\frac{y + 11}{-3} + \frac{1}{16} = x^2 - x + \frac{1}{16}\) Once you have finished reducing, you should have a new expression for y
anonymous
  • anonymous
is that the answer
anonymous
  • anonymous
?
Hero
  • Hero
The final result I get comes out to \(y = -\large\frac{48(x-\frac{1}{4}^2) - 3}{16} - 11\)
Hero
  • Hero
But that hasn't been simplified
anonymous
  • anonymous
How is that better than what he wrote originally?
Hero
  • Hero
Because it said to complete the square
Hero
  • Hero
Once you complete the square, you have to put it back in the form y =
Hero
  • Hero
But let me fix one minor mistake
Hero
  • Hero
\(y = -\large\frac{48(x-\frac{1}{4})^2 - 3}{16} - 11\)
anonymous
  • anonymous
ok
Hero
  • Hero
Ideally, I think you would want to express that as just one fraction.
anonymous
  • anonymous
yes
Hero
  • Hero
Well, I did most of the work for you. You can finish the rest.
Hero
  • Hero
Also, you might want to change y back to f(x)
anonymous
  • anonymous
ok sure
goformit100
  • goformit100
yes
Hero
  • Hero
\(f(x) = -\large3(x-\frac{1}{4})^2 - \frac{179}{16}\)
anonymous
  • anonymous
THANKS
anonymous
  • anonymous
hero
Hero
  • Hero
I must have made a calculation mistake because here's wolfram alpha's result: http://www.wolframalpha.com/input/?i=complete%20square%20(%5B%2F%2Fquantity%3A-3%2F%2F%5D)x%5E2%2B(%5B%2F%2Fquantity%3A13%2F%2F%5D)x%2B(%5B%2F%2Fquantity%3A-11%2F%2F%5D)
Hero
  • Hero
Yeah, I see where I went wrong. I added 1/16 to both sides instead of adding 1/4 to both sides
anonymous
  • anonymous
ok

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