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rebeccaskell94
Group Title
Given the triangle below, what is cot∡B?
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_03/image0084e2ec0b0.gif
√33/ 4
7•√33/ 33
√33 /7
4•√33/33
I think the Answer is C?
 2 years ago
 2 years ago
rebeccaskell94 Group Title
Given the triangle below, what is cot∡B? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_03/image0084e2ec0b0.gif √33/ 4 7•√33/ 33 √33 /7 4•√33/33 I think the Answer is C?
 2 years ago
 2 years ago

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goformit100 Group TitleBest ResponseYou've already chosen the best response.0
Use Pythagoras theorem
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
I think that is a) \(\sqrt{33}/4\)
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
urg I couldn't figure out if it was a or c because I wasn't sure if 4 or 7 should be the denominator
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
cot B = \(\frac{1}{tanB}\) right ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
@rebeccaskell94 First step is to find AB we know that using Pythagoras \[BC^2=AB^2+AC^2\] Find AB from here \[\cot =\frac{adjacent}{perpendicular}=\frac1 {\tan}\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
tan B = opposite/adjacent opposite = 4 adjacent = ??? We will find adj. by pythagoras theorem
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
\[base^2+perpendicular^2=hypotenuse^2\] Adjacent = \(\sqrt{33}\) hence we have tan B = \(\frac{\sqrt{33}}{4}\)
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
did it help @rebeccaskell94 ?
 2 years ago

rebeccaskell94 Group TitleBest ResponseYou've already chosen the best response.0
Yes! Very much so. I'm writing it down now so I remember the basic idea :) Thank you so much!
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Nice to hear that @rebeccaskell94 :)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
See http://www.khanacademy.org/math/trigonometry/v/basictrigonometry for a video on sin,cos, tan defs using SOHCAHTOA a the co functions are harder to remember!
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
SOH CAH TOA much better sine = opposite / hypotenuse cosine = adj. / hypotenuse tan = opposite / adj. right ?
 2 years ago
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