Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Given the triangle below, what is cot∡B? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_03/image0084e2ec0b0.gif √33/ 4 7•√33/ 33 √33 /7 4•√33/33 I think the Answer is C?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Use Pythagoras theorem
I think that is a) \(\sqrt{33}/4\)
urg I couldn't figure out if it was a or c because I wasn't sure if 4 or 7 should be the denominator

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

cot B = \(\frac{1}{tanB}\) right ?
@rebeccaskell94 First step is to find AB we know that using Pythagoras \[BC^2=AB^2+AC^2\] Find AB from here \[\cot =\frac{adjacent}{perpendicular}=\frac1 {\tan}\]
tan B = opposite/adjacent opposite = 4 adjacent = ??? We will find adj. by pythagoras theorem
\[base^2+perpendicular^2=hypotenuse^2\] Adjacent = \(\sqrt{33}\) hence we have tan B = \(\frac{\sqrt{33}}{4}\)
did it help @rebeccaskell94 ?
Yes! Very much so. I'm writing it down now so I remember the basic idea :) Thank you so much!
Nice to hear that @rebeccaskell94 :)
  • phi
See http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry for a video on sin,cos, tan defs using SOHCAHTOA a the co functions are harder to remember!
SOH CAH TOA much better sine = opposite / hypotenuse cosine = adj. / hypotenuse tan = opposite / adj. right ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question