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Calcmathlete
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Not quite. If you look at choice C:
\[\sec = \frac{hyp.}{adj.} = \frac{7}{6}\]

myko
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cot right triangle C =1 / 2

Calcmathlete
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\[\cot = \frac{adj.}{opp.}\]\[sec = \frac{hyp.}{adj.}\]

rebeccaskell94
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grr sorry @calcmathlete I had the formula thingies written down wrong

Calcmathlete
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lol. np. myko is correct in that regard Do you see how he got that though?

rebeccaskell94
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yeah with sec that would be 3/6 or 1/2..I think ...

Calcmathlete
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yup :)

myko
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dw:1343068971763:dw

rebeccaskell94
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Thank you guys!

Calcmathlete
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Glad to help :)

rebeccaskell94
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Calc can you medal myko for me lol I can't give one to both of you D:

myko
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yw

Calcmathlete
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I already did :)

myko
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ty, :)

mukushla
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o.O

Calcmathlete
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What @mukushla ? lol

mukushla
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nothing ; my first reply : i was 'quite wrong' . lol

Calcmathlete
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lol. I saw it for a split second before you deleted XD

rebeccaskell94
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lol

mukushla
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haha :D