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rebeccaskell94

  • 3 years ago

Given the triangle below, which of the following is a correct statement? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_02/image0114e2eb87b.gif sec right triangle C=3/7 cot right triangle B=3/2 sec right triangle B= 7/3 cot right triangle C =1 / 2 *I think the answer is C?*

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  1. Calcmathlete
    • 3 years ago
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    Not quite. If you look at choice C: \[\sec = \frac{hyp.}{adj.} = \frac{7}{6}\]

  2. myko
    • 3 years ago
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    cot right triangle C =1 / 2

  3. Calcmathlete
    • 3 years ago
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    \[\cot = \frac{adj.}{opp.}\]\[sec = \frac{hyp.}{adj.}\]

  4. rebeccaskell94
    • 3 years ago
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    grr sorry @calcmathlete I had the formula thingies written down wrong

  5. Calcmathlete
    • 3 years ago
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    lol. np. myko is correct in that regard Do you see how he got that though?

  6. rebeccaskell94
    • 3 years ago
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    yeah with sec that would be 3/6 or 1/2..I think ...

  7. Calcmathlete
    • 3 years ago
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    yup :)

  8. myko
    • 3 years ago
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    |dw:1343068971763:dw|

  9. rebeccaskell94
    • 3 years ago
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    Thank you guys!

  10. Calcmathlete
    • 3 years ago
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    Glad to help :)

  11. rebeccaskell94
    • 3 years ago
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    Calc can you medal myko for me lol I can't give one to both of you D:

  12. myko
    • 3 years ago
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    yw

  13. Calcmathlete
    • 3 years ago
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    I already did :)

  14. myko
    • 3 years ago
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    ty, :)

  15. mukushla
    • 3 years ago
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    o.O

  16. Calcmathlete
    • 3 years ago
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    What @mukushla ? lol

  17. mukushla
    • 3 years ago
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    nothing ; my first reply : i was 'quite wrong' . lol

  18. Calcmathlete
    • 3 years ago
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    lol. I saw it for a split second before you deleted XD

  19. rebeccaskell94
    • 3 years ago
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    lol

  20. mukushla
    • 3 years ago
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    haha :D

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