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Given the triangle below, which of the following is a correct statement? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_02/image0114e2eb87b.gif sec right triangle C=3/7 cot right triangle B=3/2 sec right triangle B= 7/3 cot right triangle C =1 / 2 *I think the answer is C?*

Mathematics
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Not quite. If you look at choice C: \[\sec = \frac{hyp.}{adj.} = \frac{7}{6}\]
cot right triangle C =1 / 2
\[\cot = \frac{adj.}{opp.}\]\[sec = \frac{hyp.}{adj.}\]

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Other answers:

grr sorry @calcmathlete I had the formula thingies written down wrong
lol. np. myko is correct in that regard Do you see how he got that though?
yeah with sec that would be 3/6 or 1/2..I think ...
yup :)
|dw:1343068971763:dw|
Thank you guys!
Glad to help :)
Calc can you medal myko for me lol I can't give one to both of you D:
yw
I already did :)
ty, :)
o.O
What @mukushla ? lol
nothing ; my first reply : i was 'quite wrong' . lol
lol. I saw it for a split second before you deleted XD
lol
haha :D

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