anonymous
  • anonymous
Given the triangle below, which of the following is a correct statement? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0403_02/image0114e2eb87b.gif sec right triangle C=3/7 cot right triangle B=3/2 sec right triangle B= 7/3 cot right triangle C =1 / 2 *I think the answer is C?*
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Not quite. If you look at choice C: \[\sec = \frac{hyp.}{adj.} = \frac{7}{6}\]
anonymous
  • anonymous
cot right triangle C =1 / 2
anonymous
  • anonymous
\[\cot = \frac{adj.}{opp.}\]\[sec = \frac{hyp.}{adj.}\]

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anonymous
  • anonymous
grr sorry @calcmathlete I had the formula thingies written down wrong
anonymous
  • anonymous
lol. np. myko is correct in that regard Do you see how he got that though?
anonymous
  • anonymous
yeah with sec that would be 3/6 or 1/2..I think ...
anonymous
  • anonymous
yup :)
anonymous
  • anonymous
|dw:1343068971763:dw|
anonymous
  • anonymous
Thank you guys!
anonymous
  • anonymous
Glad to help :)
anonymous
  • anonymous
Calc can you medal myko for me lol I can't give one to both of you D:
anonymous
  • anonymous
yw
anonymous
  • anonymous
I already did :)
anonymous
  • anonymous
ty, :)
anonymous
  • anonymous
o.O
anonymous
  • anonymous
What @mukushla ? lol
anonymous
  • anonymous
nothing ; my first reply : i was 'quite wrong' . lol
anonymous
  • anonymous
lol. I saw it for a split second before you deleted XD
anonymous
  • anonymous
lol
anonymous
  • anonymous
haha :D

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