Type the equation of the given line in standard form. The line with a slope (-1/3) of and b of 6. Would I just substitute that into y=mx+b? giving me y=(-1/3)x+6. And then to get to standard form I would put the constants on one side giving me (-1/3)+y=6. Would that be right? Thanks ! :D

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Type the equation of the given line in standard form. The line with a slope (-1/3) of and b of 6. Would I just substitute that into y=mx+b? giving me y=(-1/3)x+6. And then to get to standard form I would put the constants on one side giving me (-1/3)+y=6. Would that be right? Thanks ! :D

Mathematics
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  • hba
did u try to solve it
I don't have to solve it, just put it in standard form.
Does that make sense?

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Yep! standard form: \(ax^2+bx+c=0\) Can be found from simply re-arranging: y=mx+b y=(-1/3)x+6 Correct! Now when y = 0?
You don't have any x^2 term, it's just something x and a constant :-)
Oh okay, thanks :)
np! ^_^

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