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rebeccaskell94

  • 3 years ago

Lol I might jsut be stupid but idk how to do this xD Find the value of the cot 10° using your calculator. IDK HOW D; It's my last question I don't have a cot button on my calc either if I'm supposed to and and

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  1. Calcmathlete
    • 3 years ago
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    do tan 10 then put 1 ÷ Ans

  2. waterineyes
    • 3 years ago
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    Firstly find tan10..

  3. myko
    • 3 years ago
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    cot=1/tg

  4. Calcmathlete
    • 3 years ago
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    Or you could do 1 ÷ (tan 10)

  5. rebeccaskell94
    • 3 years ago
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    oh. I am stupid. My bad. Thanks guys :D

  6. waterineyes
    • 3 years ago
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    Welcome dear..

  7. agentx5
    • 3 years ago
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    \[\cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta}\]

  8. Calcmathlete
    • 3 years ago
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    np :)

  9. agentx5
    • 3 years ago
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    ^_^

  10. waterineyes
    • 3 years ago
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    going hard @agentx5

  11. rebeccaskell94
    • 3 years ago
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    :O AGENT D: -___-

  12. waterineyes
    • 3 years ago
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    I can make it more hard: \[\cot \theta = \frac{1}{\tan \theta} = \frac{\sin(2 \theta)}{2\sin^2 \theta}\]

  13. rebeccaskell94
    • 3 years ago
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    oh wait xD Is that tan^-1 or tan (10)

  14. rebeccaskell94
    • 3 years ago
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    lol "more hard"

  15. waterineyes
    • 3 years ago
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    tan10..

  16. Calcmathlete
    • 3 years ago
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    YES @waterineyes

  17. Calcmathlete
    • 3 years ago
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    Double angles rule!

  18. rebeccaskell94
    • 3 years ago
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    0.176?

  19. waterineyes
    • 3 years ago
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    @rebeccaskell94 i think now you are getting more confused..

  20. agentx5
    • 3 years ago
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    no no no not the same thing dear Rebecca! :-D \[\tan^{-1} (\frac{opp}{adj}) = \arctan (\frac{opp}{adj}) = \theta\]

  21. rebeccaskell94
    • 3 years ago
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    lol Agent your genius talents are commendable

  22. waterineyes
    • 3 years ago
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    Now use: 1/0.176

  23. agentx5
    • 3 years ago
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    Inverse tangent is cotangent, anti-tangent is arctangent. The latter returns and angle value in degrees or radians :-)

  24. Calcmathlete
    • 3 years ago
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    @rebeccaskell94 You forgot to do the rciprocal. Now. 1/0.176326981...

  25. rebeccaskell94
    • 3 years ago
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    5.671? o.o

  26. Calcmathlete
    • 3 years ago
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    THat's what I get :)

  27. rebeccaskell94
    • 3 years ago
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    oh dang.

  28. waterineyes
    • 3 years ago
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    May be.. Ha ha ha..

  29. Calcmathlete
    • 3 years ago
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    3:)

  30. waterineyes
    • 3 years ago
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    Can anyone find this without calculator??

  31. Calcmathlete
    • 3 years ago
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    o_O No idea...

  32. Calcmathlete
    • 3 years ago
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    Is Wolfram considered a calculator? XD

  33. waterineyes
    • 3 years ago
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    Can anybody think about finding the above value without using calculator?? Question changed to this one now..

  34. agentx5
    • 3 years ago
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    I can... I think... |dw:1343070912188:dw|

  35. waterineyes
    • 3 years ago
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    That is why I always say you Unique @ Kazem..

  36. agentx5
    • 3 years ago
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    Is that right @waterineyes ?

  37. waterineyes
    • 3 years ago
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    How do you find dimensions I never know that..

  38. agentx5
    • 3 years ago
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    Ah wait... |dw:1343071090394:dw|

  39. agentx5
    • 3 years ago
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    Whoops... And find dimensions with... anti-functions, arctan in this case.

  40. waterineyes
    • 3 years ago
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    According to you 1/6 is the value.. @agentx5

  41. agentx5
    • 3 years ago
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    or \(\tan^{-1}(6) \approx 80^o\)

  42. waterineyes
    • 3 years ago
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    But then answer changes...

  43. agentx5
    • 3 years ago
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    Erm, you switched the question here :-) "Question changed to this one now.."

  44. waterineyes
    • 3 years ago
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    I said you all to think how we can find tan10 without calculator.. And you know what??

  45. mukushla
    • 3 years ago
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    \( \tan 3x=\frac{\sqrt{3}}{3} \) is better i think

  46. waterineyes
    • 3 years ago
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    You all are not thinking.. Instead you are finding.. Ha ha ha ha..

  47. waterineyes
    • 3 years ago
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    How?? I did not get that one..

  48. mukushla
    • 3 years ago
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    tan 30 =sqrt(3)/3

  49. waterineyes
    • 3 years ago
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    Oh.. How can we proceed further??

  50. mukushla
    • 3 years ago
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    after simplifying we have a degree 3 polynomial in terms of tan x but leave it ... not in the mood of simplifying that right now..haha o.O lol

  51. waterineyes
    • 3 years ago
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    I am getting faint.. Leave it from my side too..

  52. mukushla
    • 3 years ago
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    i love this sign o.O o.O o.O O.o o.O o.O hahaha....

  53. waterineyes
    • 3 years ago
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    It is looking nice Kazem..

  54. rebeccaskell94
    • 3 years ago
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    O.o o.O so many notifs xD

  55. waterineyes
    • 3 years ago
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    After all it is Great @rebeccaskell94 post.. Ha ha ha..

  56. rebeccaskell94
    • 3 years ago
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    lol I see this xD

  57. waterineyes
    • 3 years ago
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    Discussion over here... If you want to close it then you can...

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