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cutie.patootie

More help? Type the equation of the given line in standard form. The line with m = 4 and intersecting 2x -4y = 8 at x = 6. Thanks!

  • one year ago
  • one year ago

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  1. agentx5
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    Step #1: convert "2x -4y = 8" to y=mx+b Step #2...

    • one year ago
  2. cutie.patootie
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    So that would make it -4y=2x+8?

    • one year ago
  3. cutie.patootie
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    Or do I have to put the m in there to and make it -4y=8x+8?

    • one year ago
  4. jazy
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    you want y not -4y so you should simplify

    • one year ago
  5. agentx5
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    Move the 2x over to the other side (with subtraction), divide both sides by -4. Can you write this second step @cutie.patootie ? :-) You'll end up getting a y=mx+b form line that allows to to draw this: |dw:1343071328047:dw|

    • one year ago
  6. cutie.patootie
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    -4y=2x+8 turns into.. -4y-2x=8 divide by -4 gives you.. y+(1/2)x=2 Right?

    • one year ago
  7. agentx5
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    No... unless you wrote it incorrect at the start. -4y + 2x = 8? Move the x's over -4y = -2x + 8 Divide by -4 y = 0.5 x - 2 (see graph above)

    • one year ago
  8. cutie.patootie
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    Oh well I had it right, but then I moved the x to the wrong side. But I see where I made my mistake now.

    • one year ago
  9. agentx5
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    then it tells you there is some other line with: y = 4x + b , because it says "m = 4" An "intersection of two lines" means when they are equal to each other. If you've solved both for the dependent varible (y) that means you can set the y's equal to each other: \(y_1 = y_2\) we know: \(y_1 = \frac{1}{2}x - 2\) \(y_2 = 4x + b_2\) So... \(y_1 = y_2\) \(\frac{1}{2}x - 2 = 4x + b_2\) Make sense? The final steps are substitute in "x=6", solve for \(b_2\), and rewrite \(y_2\)

    • one year ago
  10. cutie.patootie
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    Okay, so you get... (1/2)(6) - 2 = 4(6) +b2 3-2=24+b2 1=24+b2 b2= -23?

    • one year ago
  11. agentx5
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    You're correct! |dw:1343072679957:dw|

    • one year ago
  12. agentx5
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    When x = 6, they are both equal.

    • one year ago
  13. agentx5
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    Now don't forget to rewrite \(y_2=4x-23\) in standard form :-) All good?

    • one year ago
  14. agentx5
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    Visual methods FTW!

    • one year ago
  15. cutie.patootie
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    Okay, I think I follow. So I write it y + 4x = -23?

    • one year ago
  16. cutie.patootie
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    And yes! Hahaha.

    • one year ago
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