how is the differentiation of x=ky^2 equal to \[1=2ky\frac{dy}{dx}\]

how is the differentiation of x=ky^2 equal to \[1=2ky\frac{dy}{dx}\]

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implicite differentiation, in this case y(x), such that y is a function of x.

But that's only one guess in this case, the mechanical way I remember for implicit differentiation is derivate as if you were deriving something in terms of x and then just multiply it by dy/dx, chain rule.

I"m working on the separable equations section of my differential equations chapter.

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