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sorry,, how do you do -2^-2?

Mathematics
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|dw:1343110409163:dw|
thankyouu... how about -2^-1? isit 1/2? or is it -1/2..
-1/2

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Other answers:

howabout -2^0?? sorry... this is the lastone.,.
Wait hashir..
|dw:1343110648327:dw|
ummm sorry @waterineyes
two answers?????waaa?
is it \(-2^2\) or \((-2)^{-2}\) ??/ @punk0129
now imtalkin about -2^0 .
If this one you got -1 then how previous one is 1/4 @Hashir
|dw:1343110758868:dw|
he should make the question more clear !!
Tell me @punk0129 What is the exact question??
|dw:1343110790229:dw|
huh????! my first question was-2^-2, but now i'm askin whatis -2^0
In question brackets are not given you yourself assume the brackets I guess... @Hashir
I am asking the same @punk0129
|dw:1343110877789:dw|
no 4 da brackets i did it for exponents
sorry if that was confusnign
If your question is: \(-2^{-2}\) the you got: \[\large \implies -2^{-2} = -\frac{1}{2^2} \implies \frac{-1}{4}\]
so is it not 1/4=what Hashir said??!
And if your question is : \((-2)^{-2}\) then you will get: \[\large (-2)^{-2} = \frac{1}{2^2} \implies \frac{1}{4}\]
firstly clarify the question..
OHHH i get it!! its witout the ' ( )'s thank you:P
Welcome..
Remember anything raised to the power 0 is 1.. except the base must not be 0.. So: \[\large -2^0 \implies -(1) \implies -1\] And: \[\large (-2)^0 \implies 1\]
ya a thankyouu!!

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