## punk0129 3 years ago sorry,, how do you do -2^-2?

1. Hashir

|dw:1343110409163:dw|

2. punk0129

thankyouu... how about -2^-1? isit 1/2? or is it -1/2..

3. Hashir

-1/2

4. punk0129

howabout -2^0?? sorry... this is the lastone.,.

5. waterineyes

Wait hashir..

6. Hashir

|dw:1343110648327:dw|

7. Hashir

ummm sorry @waterineyes

8. punk0129

9. waterineyes

is it $$-2^2$$ or $$(-2)^{-2}$$ ??/ @punk0129

10. punk0129

11. waterineyes

If this one you got -1 then how previous one is 1/4 @Hashir

12. Hashir

|dw:1343110758868:dw|

13. Hashir

he should make the question more clear !!

14. waterineyes

Tell me @punk0129 What is the exact question??

15. Hashir

|dw:1343110790229:dw|

16. punk0129

huh????! my first question was-2^-2, but now i'm askin whatis -2^0

17. waterineyes

In question brackets are not given you yourself assume the brackets I guess... @Hashir

18. waterineyes

I am asking the same @punk0129

19. Hashir

|dw:1343110877789:dw|

20. punk0129

no 4 da brackets i did it for exponents

21. punk0129

sorry if that was confusnign

22. waterineyes

If your question is: $$-2^{-2}$$ the you got: $\large \implies -2^{-2} = -\frac{1}{2^2} \implies \frac{-1}{4}$

23. punk0129

so is it not 1/4=what Hashir said??!

24. waterineyes

And if your question is : $$(-2)^{-2}$$ then you will get: $\large (-2)^{-2} = \frac{1}{2^2} \implies \frac{1}{4}$

25. waterineyes

firstly clarify the question..

26. punk0129

OHHH i get it!! its witout the ' ( )'s thank you:P

27. waterineyes

Welcome..

28. waterineyes

Remember anything raised to the power 0 is 1.. except the base must not be 0.. So: $\large -2^0 \implies -(1) \implies -1$ And: $\large (-2)^0 \implies 1$

29. punk0129

ya a thankyouu!!