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moongazer
Group Title
1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3.
2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6
 2 years ago
 2 years ago
moongazer Group Title
1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6
 2 years ago
 2 years ago

This Question is Closed

moongazer Group TitleBest ResponseYou've already chosen the best response.1
My answer for no. 1 is \[3x^3 ( 3x^2/2)  3x + (3/2)\] but my teacher said there should be no fractions
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then multiply all the terms by 2(the denominator) to get rid of the fraction
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
but the leading coefficient will not be 3???
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
@saifoo.khan
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
could you help me?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
dw:1343106002554:dw
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
What does it mean by leading coefficient?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
http://4.bp.blogspot.com/_lvMAEEKgEx8/TM6ebuxxeYI/AAAAAAAAAhA/PMyxtcHq5hI/s320/a.gif
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
isn't that your answer does not have a leading coefficient of 3 ?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
you did a mistake in multiplying.
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
(x1)(x+1)(x1/2) = 0 try again.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I'll do it again :)
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I did (x1)(x+1)(2x1) = 0 is it the same as (x1)(x+1)(x1/2) = 0 ??
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got\[x^3+( x^2/2) (x/2)+(1/2)\] I checked it twice :)
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
@saifoo.khan is this correct?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Now this is correct!! :D
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
NOw get rid of 2 in the denominators, multiply the whole expression by 2.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
\[2x^3 + x^2  x + 1\]
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
How will I make it into 3?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Are decimals allowed?
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
he said there is no fractions
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
SInce your teacher said NO FRACTIONS.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
that's why I am confused :) or maybe I misheard him :)
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Possibly..
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
We can multiply the equation by 1.5 to make the leading coef as 3. :D
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
maybe he is referring to (2x1) and (x1/2)
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
2x1 and x1/2 is same.
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
are* same.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
so my answer I think is \[3x^3 + (3x^2/2)  (3x/2) + (3/2)\] that's the only expression I can have to make the leading coefficient equal to 3
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
is that correct?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
3x^3 + 1.5x^2  1.5x + 1.5 NO FRACTIONS!!! :D
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
lol, I'll just include that to my answer :)
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
how about for the second one ?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
HAHA. http://funnypicturesblog.com/wpcontent/uploads/funnypictures/Likeaboss.jpg
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
That question looks like a challenge!!
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
it should be P(x) = x^2  10kx + 6
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
it had a typo :)
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6 (3)^2  10k(3) + 6 = 0 9 + 30 k + 6 = 0
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
I got k = 1/2 but why did you made x into 3?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Because since it's a product of it, the remainder is 0.
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
So we insert the factor and set the equation = 0.
 2 years ago

moongazer Group TitleBest ResponseYou've already chosen the best response.1
Thanks, I understand it :)
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Great. Welcome.
 2 years ago
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