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 2 years ago
1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3.
2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6
 2 years ago
1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6

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moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1My answer for no. 1 is \[3x^3 ( 3x^2/2)  3x + (3/2)\] but my teacher said there should be no fractions

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0then multiply all the terms by 2(the denominator) to get rid of the fraction

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1but the leading coefficient will not be 3???

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1343106002554:dw

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1What does it mean by leading coefficient?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1http://4.bp.blogspot.com/_lvMAEEKgEx8/TM6ebuxxeYI/AAAAAAAAAhA/PMyxtcHq5hI/s320/a.gif

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1isn't that your answer does not have a leading coefficient of 3 ?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1you did a mistake in multiplying.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1(x1)(x+1)(x1/2) = 0 try again.

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1I did (x1)(x+1)(2x1) = 0 is it the same as (x1)(x+1)(x1/2) = 0 ??

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1I got\[x^3+( x^2/2) (x/2)+(1/2)\] I checked it twice :)

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1@saifoo.khan is this correct?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Now this is correct!! :D

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1NOw get rid of 2 in the denominators, multiply the whole expression by 2.

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1\[2x^3 + x^2  x + 1\]

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1How will I make it into 3?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Are decimals allowed?

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1he said there is no fractions

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1SInce your teacher said NO FRACTIONS.

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1that's why I am confused :) or maybe I misheard him :)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1We can multiply the equation by 1.5 to make the leading coef as 3. :D

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1maybe he is referring to (2x1) and (x1/2)

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.12x1 and x1/2 is same.

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1so my answer I think is \[3x^3 + (3x^2/2)  (3x/2) + (3/2)\] that's the only expression I can have to make the leading coefficient equal to 3

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.13x^3 + 1.5x^2  1.5x + 1.5 NO FRACTIONS!!! :D

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1lol, I'll just include that to my answer :)

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1how about for the second one ?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1HAHA. http://funnypicturesblog.com/wpcontent/uploads/funnypictures/Likeaboss.jpg

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1That question looks like a challenge!!

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1it should be P(x) = x^2  10kx + 6

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6 (3)^2  10k(3) + 6 = 0 9 + 30 k + 6 = 0

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1I got k = 1/2 but why did you made x into 3?

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1Because since it's a product of it, the remainder is 0.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1So we insert the factor and set the equation = 0.

moongazer
 2 years ago
Best ResponseYou've already chosen the best response.1Thanks, I understand it :)
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