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then multiply all the terms by 2(the denominator) to get rid of the fraction

but the leading coefficient will not be 3???

could you help me?

|dw:1343106002554:dw|

What does it mean by leading coefficient?

http://4.bp.blogspot.com/_lvMAEEKgEx8/TM6ebuxxeYI/AAAAAAAAAhA/PMyxtcHq5hI/s320/a.gif

isn't that your answer does not have a leading coefficient of 3 ?

you did a mistake in multiplying.

(x-1)(x+1)(x-1/2) = 0
try again.

I'll do it again :)

Sure.

I did (x-1)(x+1)(2x-1) = 0
is it the same as (x-1)(x+1)(x-1/2) = 0 ??

yup.

I got\[x^3+( x^2/2) -(x/2)+(1/2)\]
I checked it twice :)

Now this is correct!! :D

NOw get rid of 2 in the denominators, multiply the whole expression by 2.

\[2x^3 + x^2 - x + 1\]

How will I make it into 3?

Are decimals allowed?

he said there is no fractions

SInce your teacher said NO FRACTIONS.

:D

that's why I am confused :)
or maybe I misheard him :)

Possibly..

We can multiply the equation by 1.5 to make the leading coef as 3. :D

maybe he is referring to (2x-1) and (x-1/2)

2x-1 and x-1/2 is same.

are* same.

is that correct?

3x^3 + 1.5x^2 - 1.5x + 1.5
NO FRACTIONS!!! :D

lol, I'll just include that to my answer :)

how about for the second one ?

HAHA.
http://funny-pictures-blog.com/wp-content/uploads/funny-pictures/Like-a-boss.jpg

That question looks like a challenge!!

it should be P(x) = x^2 - 10kx + 6

it had a typo :)

I got k = 1/2
but why did you made x into -3?

Because since it's a product of it, the remainder is 0.

So we insert the factor and set the equation = 0.

Thanks, I understand it :)

Great. Welcome.