moongazer
  • moongazer
1.) Find a polynomial of degree that has zeros 1, -1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2 - 10kx + 6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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moongazer
  • moongazer
My answer for no. 1 is \[3x^3 -( 3x^2/2) - 3x + (3/2)\] but my teacher said there should be no fractions
lgbasallote
  • lgbasallote
then multiply all the terms by 2(the denominator) to get rid of the fraction
moongazer
  • moongazer
but the leading coefficient will not be 3???

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More answers

moongazer
  • moongazer
@saifoo.khan
moongazer
  • moongazer
could you help me?
saifoo.khan
  • saifoo.khan
|dw:1343106002554:dw|
moongazer
  • moongazer
What does it mean by leading coefficient?
saifoo.khan
  • saifoo.khan
http://4.bp.blogspot.com/_lvMAEEKgEx8/TM6ebuxxeYI/AAAAAAAAAhA/PMyxtcHq5hI/s320/a.gif
moongazer
  • moongazer
isn't that your answer does not have a leading coefficient of 3 ?
saifoo.khan
  • saifoo.khan
you did a mistake in multiplying.
saifoo.khan
  • saifoo.khan
(x-1)(x+1)(x-1/2) = 0 try again.
moongazer
  • moongazer
I'll do it again :)
saifoo.khan
  • saifoo.khan
Sure.
moongazer
  • moongazer
I did (x-1)(x+1)(2x-1) = 0 is it the same as (x-1)(x+1)(x-1/2) = 0 ??
saifoo.khan
  • saifoo.khan
yup.
moongazer
  • moongazer
I got\[x^3+( x^2/2) -(x/2)+(1/2)\] I checked it twice :)
moongazer
  • moongazer
@saifoo.khan is this correct?
saifoo.khan
  • saifoo.khan
Now this is correct!! :D
saifoo.khan
  • saifoo.khan
NOw get rid of 2 in the denominators, multiply the whole expression by 2.
moongazer
  • moongazer
\[2x^3 + x^2 - x + 1\]
moongazer
  • moongazer
How will I make it into 3?
saifoo.khan
  • saifoo.khan
Are decimals allowed?
moongazer
  • moongazer
he said there is no fractions
saifoo.khan
  • saifoo.khan
SInce your teacher said NO FRACTIONS.
saifoo.khan
  • saifoo.khan
:D
moongazer
  • moongazer
that's why I am confused :) or maybe I misheard him :)
saifoo.khan
  • saifoo.khan
Possibly..
saifoo.khan
  • saifoo.khan
We can multiply the equation by 1.5 to make the leading coef as 3. :D
moongazer
  • moongazer
maybe he is referring to (2x-1) and (x-1/2)
saifoo.khan
  • saifoo.khan
2x-1 and x-1/2 is same.
saifoo.khan
  • saifoo.khan
are* same.
moongazer
  • moongazer
so my answer I think is \[3x^3 + (3x^2/2) - (3x/2) + (3/2)\] that's the only expression I can have to make the leading coefficient equal to 3
moongazer
  • moongazer
is that correct?
saifoo.khan
  • saifoo.khan
3x^3 + 1.5x^2 - 1.5x + 1.5 NO FRACTIONS!!! :D
moongazer
  • moongazer
lol, I'll just include that to my answer :)
moongazer
  • moongazer
how about for the second one ?
saifoo.khan
  • saifoo.khan
HAHA. http://funny-pictures-blog.com/wp-content/uploads/funny-pictures/Like-a-boss.jpg
saifoo.khan
  • saifoo.khan
That question looks like a challenge!!
moongazer
  • moongazer
it should be P(x) = x^2 - 10kx + 6
moongazer
  • moongazer
it had a typo :)
saifoo.khan
  • saifoo.khan
Find the value of k such that x+3 is a product of P(x) = x^2 - 10kx + 6 (-3)^2 - 10k(-3) + 6 = 0 9 + 30 k + 6 = 0
moongazer
  • moongazer
I got k = 1/2 but why did you made x into -3?
saifoo.khan
  • saifoo.khan
Because since it's a product of it, the remainder is 0.
saifoo.khan
  • saifoo.khan
So we insert the factor and set the equation = 0.
moongazer
  • moongazer
Thanks, I understand it :)
saifoo.khan
  • saifoo.khan
Great. Welcome.

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