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Omniscience

  • 2 years ago

Consider the gaseous equilibrium \[2HI(g) \rightleftharpoons H_2(g) +I_2(g)\] the addition of more hydrogen will shift the equilibrium to the left right? If yes I don't get why; because there are two volumes in the products?

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  1. apoorvk
    • 2 years ago
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    The addition of more hydrogen would shift the reaction towards the reactant side, since you;re adding more 'product'.

  2. apoorvk
    • 2 years ago
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    Oh you mentioned 'left' - I only noticed the 'right' beside it. My bad lol.

  3. UnkleRhaukus
    • 2 years ago
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    the gas is at lower energy when there are less moles of gas {ie less pressure the gas pressures are stable when there are as many moles of reactant/products

  4. Omniscience
    • 2 years ago
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    then it shift to the left or right?

  5. UnkleRhaukus
    • 2 years ago
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    if you add to the right, some will move to the left

  6. Omniscience
    • 2 years ago
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    the hydrogen would move to the left( reactants)?

  7. apoorvk
    • 2 years ago
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    The basic funda is that, since more hydrogen has been added, the collision frequency between hydrogen and iodine molecules would increase, and hence, the reformation of HI would be get a 'push', and hence the equilibrium 'shifts towards left' a bit!

  8. Omniscience
    • 2 years ago
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    i got it; thanks

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