anonymous
  • anonymous
Consider the gaseous equilibrium \[2HI(g) \rightleftharpoons H_2(g) +I_2(g)\] the addition of more hydrogen will shift the equilibrium to the left right? If yes I don't get why; because there are two volumes in the products?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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apoorvk
  • apoorvk
The addition of more hydrogen would shift the reaction towards the reactant side, since you;re adding more 'product'.
apoorvk
  • apoorvk
Oh you mentioned 'left' - I only noticed the 'right' beside it. My bad lol.
UnkleRhaukus
  • UnkleRhaukus
the gas is at lower energy when there are less moles of gas {ie less pressure the gas pressures are stable when there are as many moles of reactant/products

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anonymous
  • anonymous
then it shift to the left or right?
UnkleRhaukus
  • UnkleRhaukus
if you add to the right, some will move to the left
anonymous
  • anonymous
the hydrogen would move to the left( reactants)?
apoorvk
  • apoorvk
The basic funda is that, since more hydrogen has been added, the collision frequency between hydrogen and iodine molecules would increase, and hence, the reformation of HI would be get a 'push', and hence the equilibrium 'shifts towards left' a bit!
anonymous
  • anonymous
i got it; thanks

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