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Ah, this is a nice series.
\[[5,8,17,44]\]

find the difference .. note the difference in the difference is a multiple of 3

Yes the first order difference is in Gp

I suggest that you show us the values you have for the difference between the numbers in the series

Once, you have those differences, see if there is a pattern or relationship among them

Looks like 3 to some power :D

tn+1 = tn + 3^(n-1)

don't know closed form at the moment!!

Ar^n + b1n^k-1 + b2n^k-2............bk

Hmm, can you explain the terms please?

it is the general formula lol1

i guess we should use summation rule
|dw:1343147827410:dw|

|dw:1343147906405:dw|

|dw:1343147929358:dw|

not sure that works!

|dw:1343147968035:dw|
something like that!! just try to manipulate and fit in it ...

|dw:1343147962155:dw|

|dw:1343148038487:dw|

|dw:1343148023475:dw|

factor out a 3
3( 2 + 3 + 6 + 15 + ...)
all ways to se it differently

|dw:1343148174027:dw|

i hope it works for other terms too .. let's see for sum

@experimentX i didnt understand!!

|dw:1343148311125:dw|

that's just some manipulation .. typing in latex really takes lot of time

|dw:1343149457407:dw|

@experimentX I guess you missed 1/2 .

thanks @mahmit2012 for correction ... you are sharp!!ii

@mahmit2012 @experimentX i learnt this by using this Ar^n + b1n^k-1 + b2n^k-2............bk

formula!1

You're welcome , and good tutoring you have had. @experimentX

Ar^n + b1n^k-1 + b2n^k-2............bk

can u ssolve this by using Ar^n + b1n^k-1 + b2n^k-2............bk

you are a good tutor!! most of me is autodidact!!