anonymous
  • anonymous
In △PQR, what is the length of line segment QR? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0404_02/image0064e2eda71.gif 28 28radical 2 56radical 3 56radical 2 *I think the answer is A?*
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
phi
  • phi
this is a "special right triangle" 45-45-90 The idea is to remember that the hypotenuse (longest side, opposite the 90 deg angle) is sqrt(2) times bigger than either leg (which are equal) h = a*sqrt(2) or (divide by sqrt(2) ) a= h/sqrt(2)
phi
  • phi
or (because people do not sqrt(2) in the denominator) a= sqrt(2)*h/(sqrt(2)*sqrt(2)) (multiply top and bottom by sqrt(2)) you do this to get rid of the sqrt(2) in the bottom a= sqrt(2)*h/2
anonymous
  • anonymous
Whoa. That was a lot.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
too much to get the answer?
anonymous
  • anonymous
I'm not sure. I'm looking at it like @ . @
phi
  • phi
the side is h/sqrt(2)= 56/sqrt(2) but none of your answers are in that form. so we have to "rationalize" to get an answer that matches.
anonymous
  • anonymous
@Parthkohli this one :D If you are given a leg of a 45-45-90 triangle, you just put 2√ in front of it to get the hypotenuse ^_^ • If the leg is 8, then the hypotenuse is 82√ • If the leg is 1281283283283249483483, then the hypotenuse is 12812832832832494834832√
ParthKohli
  • ParthKohli
The short-cut that I gave you doesn't work here too much, FYI. I just told you in simple words to remove/put sqrt2. What that short-cut actually says is that you have to multiply sqrt2 to get the hypotenuse and divide sqrt2 from the hypotenuse to get the leg.
kaiz122
  • kaiz122
can we just use trigo. here? \[\cos \theta =\frac{adjacent}{hyp}\]
ParthKohli
  • ParthKohli
So, you divide \(\sqrt2\) from the hypotenuse to get the leg.
kaiz122
  • kaiz122
adjacent=(cos 45)*56
ParthKohli
  • ParthKohli
Or, the Pythagorean. \( \color{Black}{\Rightarrow a^2 + a^2 = 56^2 }\) \( \color{Black}{\Rightarrow 2a^2 = 3136}\)
ParthKohli
  • ParthKohli
If you ever get confused with that short-cut, just come back to Pythagorean ;)
anonymous
  • anonymous
Ah! okay um wait...that just goes back to 28?
ParthKohli
  • ParthKohli
\( \color{Black}{\Rightarrow a^2 = 1568}\) You find \(\sqrt{1568}\).
ParthKohli
  • ParthKohli
(In radical form).
anonymous
  • anonymous
Okay √1568 = 39.5 and 28√2 = 39.5 as well :D
ParthKohli
  • ParthKohli
Yep :)
anonymous
  • anonymous
Yay :D Thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.