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Whoa. That was a lot.

too much to get the answer?

I'm not sure. I'm looking at it like @ . @

can we just use trigo. here?
\[\cos \theta =\frac{adjacent}{hyp}\]

So, you divide \(\sqrt2\) from the hypotenuse to get the leg.

adjacent=(cos 45)*56

If you ever get confused with that short-cut, just come back to Pythagorean ;)

Ah! okay um wait...that just goes back to 28?

\( \color{Black}{\Rightarrow a^2 = 1568}\)
You find \(\sqrt{1568}\).

(In radical form).

Okay √1568 = 39.5 and 28√2 = 39.5 as well :D

Yep :)

Yay :D Thanks