Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
In △PQR, what is the length of line segment QR?
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0404_02/image0064e2eda71.gif
28
28radical 2
56radical 3
56radical 2
*I think the answer is A?*
 one year ago
 one year ago
In △PQR, what is the length of line segment QR? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0404_02/image0064e2eda71.gif 28 28radical 2 56radical 3 56radical 2 *I think the answer is A?*
 one year ago
 one year ago

This Question is Closed

phiBest ResponseYou've already chosen the best response.2
this is a "special right triangle" 454590 The idea is to remember that the hypotenuse (longest side, opposite the 90 deg angle) is sqrt(2) times bigger than either leg (which are equal) h = a*sqrt(2) or (divide by sqrt(2) ) a= h/sqrt(2)
 one year ago

phiBest ResponseYou've already chosen the best response.2
or (because people do not sqrt(2) in the denominator) a= sqrt(2)*h/(sqrt(2)*sqrt(2)) (multiply top and bottom by sqrt(2)) you do this to get rid of the sqrt(2) in the bottom a= sqrt(2)*h/2
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.1
Whoa. That was a lot.
 one year ago

phiBest ResponseYou've already chosen the best response.2
too much to get the answer?
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.1
I'm not sure. I'm looking at it like @ . @
 one year ago

phiBest ResponseYou've already chosen the best response.2
the side is h/sqrt(2)= 56/sqrt(2) but none of your answers are in that form. so we have to "rationalize" to get an answer that matches.
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.1
@Parthkohli this one :D If you are given a leg of a 454590 triangle, you just put 2√ in front of it to get the hypotenuse ^_^ • If the leg is 8, then the hypotenuse is 82√ • If the leg is 1281283283283249483483, then the hypotenuse is 12812832832832494834832√
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The shortcut that I gave you doesn't work here too much, FYI. I just told you in simple words to remove/put sqrt2. What that shortcut actually says is that you have to multiply sqrt2 to get the hypotenuse and divide sqrt2 from the hypotenuse to get the leg.
 one year ago

kaiz122Best ResponseYou've already chosen the best response.0
can we just use trigo. here? \[\cos \theta =\frac{adjacent}{hyp}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
So, you divide \(\sqrt2\) from the hypotenuse to get the leg.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Or, the Pythagorean. \( \color{Black}{\Rightarrow a^2 + a^2 = 56^2 }\) \( \color{Black}{\Rightarrow 2a^2 = 3136}\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
If you ever get confused with that shortcut, just come back to Pythagorean ;)
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.1
Ah! okay um wait...that just goes back to 28?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
\( \color{Black}{\Rightarrow a^2 = 1568}\) You find \(\sqrt{1568}\).
 one year ago

rebeccaskell94Best ResponseYou've already chosen the best response.1
Okay √1568 = 39.5 and 28√2 = 39.5 as well :D
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.