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OK, I assume v is a constant?

Yup, it is.

OK then, the derivative of 'x' is a constant

like you so elegantly show. Now are you familiar with the power rule for derivatives?

Yeah. Derivative of \[x^n\] is \[nx^{n-1}\ But in this case, how can I express that as d(something)?

\[n*x^{n-1}\] Yeah, well, \[dx\] I think can just be looked at as a term for 'change in x'

Now, for the more complex \[y = v * x^{n}\]

now, the change in y with respect to change in x is now time for the derivative

\[dy = v * (n)*(x^{n-1}) * dx\] Use the power rule here

Thanks, that was well-explained.