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use sin/cos

to find BA , then subtract that from 120

to find AG

use trig again to find GE

@ . @

@rebeccaskell94 did you understand?

I triangle CBA, what's tan 45? @rebeccaskell94

Doesn't tan(45) = 1?

yeah, you;re right but it's also perpendicular/ adjacent, isn't it?

Idk what to do with it now D:

Remember how the legs of a 45-45-90 triangle are the same length? Can you find AG knowing that?

Are you studying trig? these are 45-45-90 triangle and 30-60-90 triangle

ok, I am out

I'll let others help here :P
I'll observe silently :)

But ashy!! D: I wanted you to help me xD

|dw:1343150968050:dw|
If x = 58, can you figure the rest out?

I just used the ratio for a 45-45-90 triangle and 30-60-90 triangle.

@rebeccaskell94 @Calcmathlete is a great helper, I'm sure you'll understand .

Okay I has this XD|dw:1343151162714:dw|

If you didn't notice, all it asked for was GE which you have as 62âˆš3 which you have :)

Oh wait, so are my âˆ†s right?

Which one?

|dw:1343151807943:dw|

ohhhh okay

Yeah. I think you read it as 20 - x when it's 120 - x.

Good job though. 45-45-90 and 30-60-90 triangles can be very simple once you remember the ratios! :D

Thank you :D

np :)

good job , "becca"

lol why the quotation marks around my name D: