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to find BA , then subtract that from 120
to find AG
use trig again to find GE
@ . @
1......find AB using tan 45 in triangle ABC 2......find AG using AG=120-AB 3......find GE using tan 60 in triangle AGE o.O
Idunnow is mukushala and 91's ways good? how do you do sin/cos anyway D: urg I'm so confused. My brain is not a math brain :(
Doesn't tan(45) = 1?
yeah, you;re right but it's also perpendicular/ adjacent, isn't it?
Idk what to do with it now D:
Remember how the legs of a 45-45-90 triangle are the same length? Can you find AG knowing that?
Are you studying trig? these are 45-45-90 triangle and 30-60-90 triangle
ummm can we have like, 1 person helping me xD too many is making it worse. It takes a while to help me bc my brain...it doesn't get along well with math
ok, I am out
http://www.khanacademy.org/math/geometry/triangles/v/45-45-90-triangles and http://www.khanacademy.org/math/geometry/triangles/v/intro-to-30-60-90-triangles
I'll let others help here :P I'll observe silently :)
But ashy!! D: I wanted you to help me xD
|dw:1343150968050:dw| If x = 58, can you figure the rest out?
I just used the ratio for a 45-45-90 triangle and 30-60-90 triangle.
Okay I has this XD|dw:1343151162714:dw|
Oh. You misread that part for AG....it said 120 - x. When I said to figure out the rest, I meant did you understand how to get the answer now using the ratios, but it's good practice XD Good job by the way :)
If you didn't notice, all it asked for was GE which you have as 62√3 which you have :)
Oh wait, so are my ∆s right?
Yup :) Good work! That one part on the bottom of the 30-60-90 triangle is wrong because you misread it, but as long as you understand the concept, it's fine :)
Yeah. I think you read it as 20 - x when it's 120 - x.
Good job though. 45-45-90 and 30-60-90 triangles can be very simple once you remember the ratios! :D
Thank you :D
good job , "becca"
lol why the quotation marks around my name D: