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TransendentialPI Group Title

Folks, I'm trying to evaluate (1/2)sin(2arcsec(-8)) where arcsec is the inverse secant. The answer is supposed to be 3sqrt(7)/128. I'll post a sketch of what I've done so far.

  • one year ago
  • one year ago

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  1. TransendentialPI Group Title
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    |dw:1343155955658:dw|. I'm not sure how deal with the 2arcsec(-8)

    • one year ago
  2. Uniquebum Group Title
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    \[arcsec(-8) = \frac{\pi}{2}+\arcsin(1/8)\] If that sounds weird, draw a sketch and you might notice why.

    • one year ago
  3. TransendentialPI Group Title
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    It might be an equivalence, but how does that become 3sqrt(7)/128?

    • one year ago
  4. TransendentialPI Group Title
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    Is there an identity I'm missing?

    • one year ago
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spraguer (Moderator)
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