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Grazes

  • 3 years ago

Complete the square. 2x^(2)+6x+y^(2)+10y+100=0

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  1. Calcmathlete
    • 3 years ago
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    \[\implies2x^2 + 6x + y^2 + 10y + 100 \]\[\implies (2x^2 + 6x) + (y^2 + 10y) = -100\]\[\implies 2(x^2 + 3x) + (y^2 + 10y) = -100 \]\[\implies 2(x^2 + 3x + 2.25) + (y^2 + 10y + 25) = -100 + 4.5 + 25\]\[\implies 2(x + 1.5)^2 + (y + 5)^2 = -70.5\]\[\implies -\frac{2(x + 1.5)^2}{70.5} - \frac{(y + 5)^2}{70.5} = 1\] @mukushla Is it just me or is this a degenerate conic?

  2. Grazes
    • 3 years ago
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    Thanks.

  3. mukushla
    • 3 years ago
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    yes it is...

  4. Calcmathlete
    • 3 years ago
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    Alright. Thanks. Just wanted to make sure :)

  5. mukushla
    • 3 years ago
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    yw :)

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