Grazes
Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following:
1. (1/r1)+(1/r2)
2. ((1/r1)+(1/r2)^2



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allank
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Kindly rewrite the equation in a more readable form.

Grazes
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dw:1343164493957:dw

allank
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Thanks @Grazes but I was talking about the original.
9x^2_7x06=0

allank
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Is it 9x^27x6=0 ?

Grazes
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ohhhh. my bad. dw:1343164807154:dw

allank
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No problem. Most of the work here involves factoring the quadratic equation. Can you do that?

ganeshie8
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hint 
find sum of roots & product of roots

cwrw238
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sum of roots = b/a
product of roots = c/a
a,b and c refer to the equation
ax^2 + bx + c = 0

cwrw238
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so r1 + r2 =  7/9
and r1r2 = 6/9

Grazes
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oh. Thanks!

cwrw238
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now
1/r1 + 1/r2 = r1 + r2 / r1r2
plug in the values 7/9 and 6/9 into the above and you have answer to 1.

cwrw238
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no 2 is the square of this result

cwrw238
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yw