anonymous
  • anonymous
Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following: 1. (1/r1)+(1/r2) 2. ((1/r1)+(1/r2)^2
Mathematics
jamiebookeater
  • jamiebookeater
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allank
  • allank
Kindly rewrite the equation in a more readable form.
anonymous
  • anonymous
|dw:1343164493957:dw|
allank
  • allank
Thanks @Grazes but I was talking about the original. 9x^2_7x06=0

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allank
  • allank
Is it 9x^2-7x-6=0 ?
anonymous
  • anonymous
ohhhh. my bad. |dw:1343164807154:dw|
allank
  • allank
No problem. Most of the work here involves factoring the quadratic equation. Can you do that?
ganeshie8
  • ganeshie8
hint - find sum of roots & product of roots
cwrw238
  • cwrw238
sum of roots = -b/a product of roots = c/a a,b and c refer to the equation ax^2 + bx + c = 0
cwrw238
  • cwrw238
so r1 + r2 = - 7/9 and r1r2 = -6/9
anonymous
  • anonymous
oh. Thanks!
cwrw238
  • cwrw238
now 1/r1 + 1/r2 = r1 + r2 / r1r2 plug in the values -7/9 and -6/9 into the above and you have answer to 1.
cwrw238
  • cwrw238
no 2 is the square of this result
cwrw238
  • cwrw238
yw

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