Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following: 1. (1/r1)+(1/r2) 2. ((1/r1)+(1/r2)^2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Kindly rewrite the equation in a more readable form.
|dw:1343164493957:dw|
Thanks @Grazes but I was talking about the original. 9x^2_7x06=0

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Is it 9x^2-7x-6=0 ?
ohhhh. my bad. |dw:1343164807154:dw|
No problem. Most of the work here involves factoring the quadratic equation. Can you do that?
hint - find sum of roots & product of roots
sum of roots = -b/a product of roots = c/a a,b and c refer to the equation ax^2 + bx + c = 0
so r1 + r2 = - 7/9 and r1r2 = -6/9
oh. Thanks!
now 1/r1 + 1/r2 = r1 + r2 / r1r2 plug in the values -7/9 and -6/9 into the above and you have answer to 1.
no 2 is the square of this result
yw

Not the answer you are looking for?

Search for more explanations.

Ask your own question