A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following:
1. (1/r1)+(1/r2)
2. ((1/r1)+(1/r2)^2
anonymous
 4 years ago
Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following: 1. (1/r1)+(1/r2) 2. ((1/r1)+(1/r2)^2

This Question is Closed

allank
 4 years ago
Best ResponseYou've already chosen the best response.0Kindly rewrite the equation in a more readable form.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1343164493957:dw

allank
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks @Grazes but I was talking about the original. 9x^2_7x06=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh. my bad. dw:1343164807154:dw

allank
 4 years ago
Best ResponseYou've already chosen the best response.0No problem. Most of the work here involves factoring the quadratic equation. Can you do that?

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.0hint  find sum of roots & product of roots

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1sum of roots = b/a product of roots = c/a a,b and c refer to the equation ax^2 + bx + c = 0

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1so r1 + r2 =  7/9 and r1r2 = 6/9

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1now 1/r1 + 1/r2 = r1 + r2 / r1r2 plug in the values 7/9 and 6/9 into the above and you have answer to 1.

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1no 2 is the square of this result
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.