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Grazes

  • 2 years ago

Let the 2 roots of the quadratic equation 9x^2_7x06=0 be r1 and r2. Evaluate the following: 1. (1/r1)+(1/r2) 2. ((1/r1)+(1/r2)^2

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  1. allank
    • 2 years ago
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    Kindly rewrite the equation in a more readable form.

  2. Grazes
    • 2 years ago
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    |dw:1343164493957:dw|

  3. allank
    • 2 years ago
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    Thanks @Grazes but I was talking about the original. 9x^2_7x06=0

  4. allank
    • 2 years ago
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    Is it 9x^2-7x-6=0 ?

  5. Grazes
    • 2 years ago
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    ohhhh. my bad. |dw:1343164807154:dw|

  6. allank
    • 2 years ago
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    No problem. Most of the work here involves factoring the quadratic equation. Can you do that?

  7. ganeshie8
    • 2 years ago
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    hint - find sum of roots & product of roots

  8. cwrw238
    • 2 years ago
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    sum of roots = -b/a product of roots = c/a a,b and c refer to the equation ax^2 + bx + c = 0

  9. cwrw238
    • 2 years ago
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    so r1 + r2 = - 7/9 and r1r2 = -6/9

  10. Grazes
    • 2 years ago
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    oh. Thanks!

  11. cwrw238
    • 2 years ago
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    now 1/r1 + 1/r2 = r1 + r2 / r1r2 plug in the values -7/9 and -6/9 into the above and you have answer to 1.

  12. cwrw238
    • 2 years ago
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    no 2 is the square of this result

  13. cwrw238
    • 2 years ago
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    yw

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