A community for students.
Here's the question you clicked on:
 0 viewing
MathSofiya
 3 years ago
I guess F is not a conservative vector field.
\[F(x,y)=e^xsiny\hat{i}+e^xcosy\hat{j}\]
\[\frac{\partial{P}}{\partial{y}}=\frac{\partial}{\partial{y}}e^xsiny=cosy\]
\[\frac{\partial{Q}}{\partial{x}}=\frac{\partial}{\partial{x}}e^xcosy=e^x\]
\[cosy\neq e^x\]
MathSofiya
 3 years ago
I guess F is not a conservative vector field. \[F(x,y)=e^xsiny\hat{i}+e^xcosy\hat{j}\] \[\frac{\partial{P}}{\partial{y}}=\frac{\partial}{\partial{y}}e^xsiny=cosy\] \[\frac{\partial{Q}}{\partial{x}}=\frac{\partial}{\partial{x}}e^xcosy=e^x\] \[cosy\neq e^x\]

This Question is Closed

Spacelimbus
 3 years ago
Best ResponseYou've already chosen the best response.1The second one, I am not sure what you defined as which, but just to make sure. You are taking the partial derivative of e^x cosy ? with respect to x?

91
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{\partial{P}}{\partial{y}}=\frac{\partial}{\partial{y}}e^xsiny=e^x cosy\]

Spacelimbus
 3 years ago
Best ResponseYou've already chosen the best response.1treat the respective values as constants for partial derivatives.

91
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{\partial{Q}}{\partial{x}}=\frac{\partial}{\partial{x}}e^xcosy=e^x cos y\] so there are conservative

Spacelimbus
 3 years ago
Best ResponseYou've already chosen the best response.1it is a conservative vector field.

91
 3 years ago
Best ResponseYou've already chosen the best response.2constant multplied to variable don't go away

MathSofiya
 3 years ago
Best ResponseYou've already chosen the best response.0Oh ok. Thanks in the previous example that I did I got \[\frac{\partial}{\partial{y}}2x3y=3\] Which lead me to believe that the constant went away

91
 3 years ago
Best ResponseYou've already chosen the best response.2only if they are by themselve

MathSofiya
 3 years ago
Best ResponseYou've already chosen the best response.0Makes sense. Thank you both!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.