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rebeccaskell94
 3 years ago
n the figure below, the length of line segment CB is 58 units and the length of line segment BG is 120 units. What is the length of line segment GE?
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0404_07/image0084e2ee688.gif
62√3
116
58√2
124
*I think the answer is C?*
rebeccaskell94
 3 years ago
n the figure below, the length of line segment CB is 58 units and the length of line segment BG is 120 units. What is the length of line segment GE? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0404_07/image0084e2ee688.gif 62√3 116 58√2 124 *I think the answer is C?*

This Question is Closed

Pac1f1cIslander
 3 years ago
Best ResponseYou've already chosen the best response.0I would think B...

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3look at the first triangle ABC  notice it is a rightangled triangle and one of the angles is 45, so what would the other angle be?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3correct  so that implies it is also isoceles

Pac1f1cIslander
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, they're both special triangles...one is 454590, the other is 306090

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3now use the fact that:\[\cos(60)=0.5\]to work out AE

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3sorry  use the fact that:\[\tan(60)=\sqrt(3)\]to work out GE

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0Well, I'm not really sure how to do that. Sorry, I'm dumb when it comes to math. :/

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3are you familiar with trigonometry (sin/cos/tan)?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3if not, then this might help you: http://www.mathsisfun.com/algebra/trigfourquadrants.html

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0Vaguely, yes. I took geometry 3 years ago and got a B+ and A but I don't remember most of it :/ I'm trying desperately to help a friend but some of this stuff I just don't remember. I know that tan = opposite ÷ adjacent cos= adjacent ÷ hypotenuse sin= opposite ÷ hypotenuse If I remember those correctly. I'm personally, currently in AlgII :/

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3good, so look at triangle AEG and note that:\[\tan(60)=\frac{GE}{AG}=\frac{GE}{62}\]

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3which implies:\[GE=62\times\tan(60)\]

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0Ah! Yes. I think so. I had to figure out where the 62 came from again xD

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3good, now some angles have /well known/ values for sin/cos/tan

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.360 is one such angle where: \(\tan(60)=\sqrt{3}\)

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3can you work it out now?

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0Let me try, and then I'll post it :D

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0107.26 is 62*1.73

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.3roughly yes  you should leave it in terms of the radical, so the answer is \(62\sqrt{3}\)
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