Solve. x^2 + x = 20

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Solve. x^2 + x = 20

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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okay so first you move 20 over the = sign
\[x^2+x=20\] \[x^2+x-20=0\] \[x=\frac{-b\pm\sqrt{b^2-4ax}}{2a}\]
so it becomes this: |dw:1343183162557:dw|

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and then like the guy did above you use the QUADRATIC FORMULAAA .. it's quite hectic i tell you... do you need help with that... i can walk you through it
i tried that way already but my hw is asking me to find two x's
that is it
oh..then i must of did something wrong
so you don't know how to do it because the quadratic formula DOES give u 2 answers
\[a=1,\qquad b=1,\qquad c=-20\]
still want me to walk you though it?
* through
or unkleR can help u that is...
|dw:1343183363230:dw|when i did the quadraric formula i got
GOODDDD
okay so now just do it one by one... your looking at 2 equations!
|dw:1343183439776:dw|
or you could leave it like that... idk what ur teacher likes best
oh okay. i understand now. thx for ur help
UR WELCOME
You can use sum of roots and product of roots, x^2-(SOR)+(POR)=0 SOR=a+b=-1 POR=ab=-20 Simultaneous equations, a=-5, b=4 Roots are x=-5, x=4

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