anonymous
  • anonymous
Solve. x^2 + x = 20
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
okay so first you move 20 over the = sign
UnkleRhaukus
  • UnkleRhaukus
\[x^2+x=20\] \[x^2+x-20=0\] \[x=\frac{-b\pm\sqrt{b^2-4ax}}{2a}\]
anonymous
  • anonymous
so it becomes this: |dw:1343183162557:dw|

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More answers

anonymous
  • anonymous
and then like the guy did above you use the QUADRATIC FORMULAAA .. it's quite hectic i tell you... do you need help with that... i can walk you through it
anonymous
  • anonymous
i tried that way already but my hw is asking me to find two x's
anonymous
  • anonymous
that is it
anonymous
  • anonymous
oh..then i must of did something wrong
anonymous
  • anonymous
so you don't know how to do it because the quadratic formula DOES give u 2 answers
UnkleRhaukus
  • UnkleRhaukus
\[a=1,\qquad b=1,\qquad c=-20\]
anonymous
  • anonymous
still want me to walk you though it?
anonymous
  • anonymous
* through
anonymous
  • anonymous
or unkleR can help u that is...
anonymous
  • anonymous
|dw:1343183363230:dw|when i did the quadraric formula i got
anonymous
  • anonymous
GOODDDD
anonymous
  • anonymous
okay so now just do it one by one... your looking at 2 equations!
anonymous
  • anonymous
|dw:1343183439776:dw|
anonymous
  • anonymous
or you could leave it like that... idk what ur teacher likes best
anonymous
  • anonymous
oh okay. i understand now. thx for ur help
anonymous
  • anonymous
UR WELCOME
.Sam.
  • .Sam.
You can use sum of roots and product of roots, x^2-(SOR)+(POR)=0 SOR=a+b=-1 POR=ab=-20 Simultaneous equations, a=-5, b=4 Roots are x=-5, x=4

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