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ashleyb

  • 3 years ago

Solve. x^2 + x = 20

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  1. Izzy25
    • 3 years ago
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    okay so first you move 20 over the = sign

  2. UnkleRhaukus
    • 3 years ago
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    \[x^2+x=20\] \[x^2+x-20=0\] \[x=\frac{-b\pm\sqrt{b^2-4ax}}{2a}\]

  3. Izzy25
    • 3 years ago
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    so it becomes this: |dw:1343183162557:dw|

  4. Izzy25
    • 3 years ago
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    and then like the guy did above you use the QUADRATIC FORMULAAA .. it's quite hectic i tell you... do you need help with that... i can walk you through it

  5. ashleyb
    • 3 years ago
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    i tried that way already but my hw is asking me to find two x's

  6. Izzy25
    • 3 years ago
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    that is it

  7. ashleyb
    • 3 years ago
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    oh..then i must of did something wrong

  8. Izzy25
    • 3 years ago
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    so you don't know how to do it because the quadratic formula DOES give u 2 answers

  9. UnkleRhaukus
    • 3 years ago
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    \[a=1,\qquad b=1,\qquad c=-20\]

  10. Izzy25
    • 3 years ago
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    still want me to walk you though it?

  11. Izzy25
    • 3 years ago
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    * through

  12. Izzy25
    • 3 years ago
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    or unkleR can help u that is...

  13. ashleyb
    • 3 years ago
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    |dw:1343183363230:dw|when i did the quadraric formula i got

  14. Izzy25
    • 3 years ago
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    GOODDDD

  15. Izzy25
    • 3 years ago
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    okay so now just do it one by one... your looking at 2 equations!

  16. Izzy25
    • 3 years ago
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    |dw:1343183439776:dw|

  17. Izzy25
    • 3 years ago
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    or you could leave it like that... idk what ur teacher likes best

  18. ashleyb
    • 3 years ago
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    oh okay. i understand now. thx for ur help

  19. Izzy25
    • 3 years ago
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    UR WELCOME

  20. .Sam.
    • 3 years ago
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    You can use sum of roots and product of roots, x^2-(SOR)+(POR)=0 SOR=a+b=-1 POR=ab=-20 Simultaneous equations, a=-5, b=4 Roots are x=-5, x=4

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