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ashleyb

Solve. x^2 + x = 20

  • one year ago
  • one year ago

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  1. Izzy25
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    okay so first you move 20 over the = sign

    • one year ago
  2. UnkleRhaukus
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    \[x^2+x=20\] \[x^2+x-20=0\] \[x=\frac{-b\pm\sqrt{b^2-4ax}}{2a}\]

    • one year ago
  3. Izzy25
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    so it becomes this: |dw:1343183162557:dw|

    • one year ago
  4. Izzy25
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    and then like the guy did above you use the QUADRATIC FORMULAAA .. it's quite hectic i tell you... do you need help with that... i can walk you through it

    • one year ago
  5. ashleyb
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    i tried that way already but my hw is asking me to find two x's

    • one year ago
  6. Izzy25
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    that is it

    • one year ago
  7. ashleyb
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    oh..then i must of did something wrong

    • one year ago
  8. Izzy25
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    so you don't know how to do it because the quadratic formula DOES give u 2 answers

    • one year ago
  9. UnkleRhaukus
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    \[a=1,\qquad b=1,\qquad c=-20\]

    • one year ago
  10. Izzy25
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    still want me to walk you though it?

    • one year ago
  11. Izzy25
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    * through

    • one year ago
  12. Izzy25
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    or unkleR can help u that is...

    • one year ago
  13. ashleyb
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    |dw:1343183363230:dw|when i did the quadraric formula i got

    • one year ago
  14. Izzy25
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    GOODDDD

    • one year ago
  15. Izzy25
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    okay so now just do it one by one... your looking at 2 equations!

    • one year ago
  16. Izzy25
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    |dw:1343183439776:dw|

    • one year ago
  17. Izzy25
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    or you could leave it like that... idk what ur teacher likes best

    • one year ago
  18. ashleyb
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    oh okay. i understand now. thx for ur help

    • one year ago
  19. Izzy25
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    UR WELCOME

    • one year ago
  20. .Sam.
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    You can use sum of roots and product of roots, x^2-(SOR)+(POR)=0 SOR=a+b=-1 POR=ab=-20 Simultaneous equations, a=-5, b=4 Roots are x=-5, x=4

    • one year ago
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