Peter's chickens got the bird flu and he is rying to stop the epidemic. He knows that the function f(t) = 300 / ( 15 - 20e^(-0.07t) ) describes the number of his chickens who are sick t weeks after the initial outbreak. (a) How many chickens became sick when the flu epidemic has began? I got -60 for my answer, which doesn't seem right (b) In how many weeks will 100 chickens be sick? i got roughly 7.3 weeks (c) What is the maximum number of chickens that will become ill?

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Peter's chickens got the bird flu and he is rying to stop the epidemic. He knows that the function f(t) = 300 / ( 15 - 20e^(-0.07t) ) describes the number of his chickens who are sick t weeks after the initial outbreak. (a) How many chickens became sick when the flu epidemic has began? I got -60 for my answer, which doesn't seem right (b) In how many weeks will 100 chickens be sick? i got roughly 7.3 weeks (c) What is the maximum number of chickens that will become ill?

Mathematics
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try asking just 1 question at a time
okay, well How many chickens became sick when the flu epidemic has began?
would t be 0 or 1? I dunno

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well when i put in 0 i got -60 for my answer. which did not make sense
and when i put 1, i got -82
eh. when did the epidemic begin?
the question never states it
how'd you figure out a???
haha, i can't figure it out. that's the point. i just assumed t would be 0, and when i plugged that in, i got a negative number
uhm dont worry about it. our prof just told us we don't have to do part a. could you maybe help me with part c?
eh...this doesn't look parabolic...is it? i ahvent done the math myself.
but if it is, then it is at the midpoint
well the prof said to not do part a
oh, talking about c there. I think a is 0...
..unless the 'parabola' has shifted...
it's okay, we don't need to wrry about it
for part c, i find the derivative and set it to 0 right?
lol i forgot all about derivatives... yes.
wait..is it the first or second derivative?
that u should use?
hey..you're doing calculus! you know of purplemath.com, calculushelp.com and khanacademy.org right?

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