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anonymous
 3 years ago
A T shirt launcher launches shirts at 15 m/s. If it takes 0.30 s to accelerate a 250 g shirt to launch speed, determine the force exerted on the shirt. You can assume no friction.
I just need the final answer Please ! btw this is a physics question
anonymous
 3 years ago
A T shirt launcher launches shirts at 15 m/s. If it takes 0.30 s to accelerate a 250 g shirt to launch speed, determine the force exerted on the shirt. You can assume no friction. I just need the final answer Please ! btw this is a physics question

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NotTim
 3 years ago
Best ResponseYou've already chosen the best response.1so, let's draw a diagram first and then make a variables list. then, find whic hformula we need.

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.1are we doing the entire motion, or just when it initally leaves the cannon?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343190086331:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im actually not sure :S

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2\[F=ma=m\frac{\Delta v}{\Delta t}\]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2that's all you need, just be careful about the units

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.1sigh....turingtest beat me to the punch...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2I like how you were thinking out the different factors in the question though. Props on that ;)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so final answer would be 12.5 ?

maheshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.012.5 newtons?????????????? I mean wt unit did u take?

maheshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.0yeah u r right then:D @sparkles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0F=(0.25)(50) = 12.5 N
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