anonymous
  • anonymous
A firecracker shoots up from a hill 150 feet high with an initial speed of 95 feet per second. Using the formula H(t) = −16t2 + vt + s, determine how long it will take the firecracker to hit the ground.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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NotTim
  • NotTim
1. Let's draw a diagram. 2. LEt's make a variables list 3 Find der formulas tu need!
NotTim
  • NotTim
4. Solve it! remember which formulas need to be 'combined'!
anonymous
  • anonymous
Do you just want the answer?

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More answers

NotTim
  • NotTim
blue bird! go back to your other question! THIS MA TOWN!
NotTim
  • NotTim
oooh wait. this aint physics...
anonymous
  • anonymous
How would i make a variables list?
NotTim
  • NotTim
you just need to find the end points!
anonymous
  • anonymous
I'm confused :o
anonymous
  • anonymous
I thought you only plug in the numbers to the equation but i'm unsure if that's correct or how to do it even if it is correct
NotTim
  • NotTim
v=95 ft/s H(t)=150
NotTim
  • NotTim
solve for s!
NotTim
  • NotTim
wait...what's s? solve for t, silly me
anonymous
  • anonymous
ok but there is also a s!?
anonymous
  • anonymous
I tried to solve but i'm soooo confused
lgbasallote
  • lgbasallote
let H(t) = 0 then solve for t
NotTim
  • NotTim
really? shoot. I suck at even trinomials now huh
NotTim
  • NotTim
maybe s is given elsewhere in your textbook
anonymous
  • anonymous
no it isn't :o
anonymous
  • anonymous
@Romero yes please can i have the answer
NotTim
  • NotTim
@lgbasallote wat is s?
lgbasallote
  • lgbasallote
i'd like to say it's the distance traveled
anonymous
  • anonymous
Is the answer 7.2 seconds?
NotTim
  • NotTim
dunno. doesnt your txtbook ahve the answer?
anonymous
  • anonymous
no @lgbasallote is the answe 7.2s ?!
anonymous
  • anonymous
i'm doing an online course not from a textbook!
lgbasallote
  • lgbasallote
lol shouldnt @NotTim be answering this o.O wait..ill check
NotTim
  • NotTim
i dont wanna do math...
lgbasallote
  • lgbasallote
it;s what my calculator said
anonymous
  • anonymous
ok thank you all :)

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