• lgbasallote
which one will liquefy most easily when compressed of a constant temperature? A) \(F_2\) B) \(H_2\) C) \(HF\) D) \(Si H_4\) E) \(Ar\)
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
  • NotTim
you should look at the bonds i guess
  • apoorvk
Okay - the more the inter-molecular forces between the molecules, the easier to compress them, and hence liquefy them. -.- So, in here, I guess you need to check the polarity of the bonds - More the electronegativity difference between participating atoms, more the dipole charge, and hence... more the inter-molecular attractions!
  • apoorvk
F-F ---> Same atom, same electronegativity, so just an instantaneous dipole. Not so great. H\(_2\) -----> Same as above -_- Ar -----> Noble gas BAH! very very veryyyyyyy little interactions with 'neighboring' molecules (selfish atoms -.- ) SiH\(_4\) ---> Interesting? Okay yes, a lot more interactions, and we have a dipole as well. However, while interacting with the surrounding molecules, the Si atoms are always enclosed within the 'tetrahedral-sphere' of their molecules, and it's just H-atoms which (being on the periphery) interact with the outside world. And now, since all the H-atoms have the same type of charge, it leads to a net repulsive-atmosphere between the atoms, rather causing inter-molecular interactions! So, liquefaction in comparatively tougher for this one. Which leaves us with H-F - (ofcourse this is the answer - what were you thinking eh? no surprises and no points for guessing -.-) Why - because they form a linear molecule, with a good dipole (OMG H and F). So:|dw:1343201393276:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.