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Omniscience
 3 years ago
Equilibrium Constants:
When decreasing the temperature of an endothermic reaction; the constant (K) value decreases or increases?
In my book the answer states "increase the value of the constant as the reaction is endothermic.
But my notes states that "when temperature increases, the K value increases for endothermic reactions."
So, doesn't the K value decrease when the temperature decreases?
Omniscience
 3 years ago
Equilibrium Constants: When decreasing the temperature of an endothermic reaction; the constant (K) value decreases or increases? In my book the answer states "increase the value of the constant as the reaction is endothermic. But my notes states that "when temperature increases, the K value increases for endothermic reactions." So, doesn't the K value decrease when the temperature decreases?

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NotTim
 3 years ago
Best ResponseYou've already chosen the best response.2We should revisit Le Chatelier's principle.

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.2http://en.wikipedia.org/wiki/Le_Chatelier's_principle#Effect_of_change_in_temperature

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.2wai.t TELL ME THE K WIKIPEDIA. Darnit

Omniscience
 3 years ago
Best ResponseYou've already chosen the best response.1when temperate decreases in an endothermic reaction the equilibrium shifts to the left i think

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.2My notes say: "Increase temp, K decreases in exothermic rx, K increases in endothermic rx.

Omniscience
 3 years ago
Best ResponseYou've already chosen the best response.1yeah.. but this is decreases; so does it go the opposite?

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.2"Decreases temp, K down in exothermic, K up in endothermic rx"

Omniscience
 3 years ago
Best ResponseYou've already chosen the best response.1why does the constant increases when the temperature decreases? and when the temperature increases the constant still increases..?
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