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moongazer Group Title

1.) Find a polynomial of degree that has zeros 1, -1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2 - 10kx + 6

  • 2 years ago
  • 2 years ago

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  1. sauravshakya Group Title
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    AT FIRST. do u know what a degree of polynomial means.

    • 2 years ago
  2. moongazer Group Title
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    \[3x^3+(3x^2/2)−(3x/2)+(3/2)\] is this correct?

    • 2 years ago
  3. moongazer Group Title
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    for 1.?

    • 2 years ago
  4. sauravshakya Group Title
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    simplify that.

    • 2 years ago
  5. moongazer Group Title
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    Is my answer correct?

    • 2 years ago
  6. sauravshakya Group Title
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    |dw:1343207441484:dw|

    • 2 years ago
  7. moongazer Group Title
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    how about for no. 2 could you help me?

    • 2 years ago
  8. sauravshakya Group Title
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    can u simplify this plz

    • 2 years ago
  9. sauravshakya Group Title
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    I DONT THINK YOUR ANSWER IS CORRECT.

    • 2 years ago
  10. moongazer Group Title
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    ok

    • 2 years ago
  11. sauravshakya Group Title
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    FOR NUMBER 2) do u know factor theorem

    • 2 years ago
  12. moongazer Group Title
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    could I make \[(x-1/2) -------> (2x-1)\] ????????

    • 2 years ago
  13. sauravshakya Group Title
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    |dw:1343207772794:dw|

    • 2 years ago
  14. sauravshakya Group Title
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    NOW do u know factor theorem? and did u get answer for 1)

    • 2 years ago
  15. moongazer Group Title
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    \[3x^3-(3x^2/2)−3x−(3/2)\]

    • 2 years ago
  16. moongazer Group Title
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    am I correct now?

    • 2 years ago
  17. sauravshakya Group Title
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    NOPE.

    • 2 years ago
  18. sauravshakya Group Title
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    BUT U R VERY CLOSE

    • 2 years ago
  19. moongazer Group Title
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    I'll do it again :)

    • 2 years ago
  20. sauravshakya Group Title
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    u just made the sign mistake

    • 2 years ago
  21. moongazer Group Title
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    could I make (x-1/2) into (2x-1) because my teacher said there should be no fractions?

    • 2 years ago
  22. moongazer Group Title
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    @sauravshakya

    • 2 years ago
  23. sauravshakya Group Title
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    |dw:1343208282102:dw|

    • 2 years ago
  24. sauravshakya Group Title
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    is the correct answer

    • 2 years ago
  25. moongazer Group Title
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    could I make (x-1/2) into (2x-1) ??????

    • 2 years ago
  26. sauravshakya Group Title
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    NOPE because|dw:1343208355724:dw|

    • 2 years ago
  27. sauravshakya Group Title
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    but if |dw:1343208386811:dw|

    • 2 years ago
  28. moongazer Group Title
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    that's what I mean for the second part

    • 2 years ago
  29. sauravshakya Group Title
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    because|dw:1343208443188:dw|

    • 2 years ago
  30. moongazer Group Title
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    isn't that it is zero so that it is possible?

    • 2 years ago
  31. moongazer Group Title
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    |dw:1343205903760:dw|

    • 2 years ago
  32. sauravshakya Group Title
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    IF it is equal to zero then yes u can because |dw:1343208534245:dw|

    • 2 years ago
  33. moongazer Group Title
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    |dw:1343205945423:dw|

    • 2 years ago
  34. sauravshakya Group Title
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    so what?

    • 2 years ago
  35. moongazer Group Title
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    I got the correct answer :)

    • 2 years ago
  36. sauravshakya Group Title
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    and what is that

    • 2 years ago
  37. moongazer Group Title
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    it mean that there zeroes are both 1/2

    • 2 years ago
  38. moongazer Group Title
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    so you can use either of the two?

    • 2 years ago
  39. sauravshakya Group Title
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    yeah. BUT only in that case. U cannot use this in simplification.

    • 2 years ago
  40. sauravshakya Group Title
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    AND NOW SHALL WE BEGIN NO. 2

    • 2 years ago
  41. moongazer Group Title
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    yup :)

    • 2 years ago
  42. sauravshakya Group Title
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    do u know factor theorem.

    • 2 years ago
  43. moongazer Group Title
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    wait I am trying to solve 1 with (2x-1) :)

    • 2 years ago
  44. moongazer Group Title
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    I got the same answer :)

    • 2 years ago
  45. moongazer Group Title
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    I know factor theorem. If the remainder when dividing P(x) by D(x) is zero, then D(x) is a factor of P(x). P(x) is any polynomial D(x) is the divisor being a factor means it is included in multiplying.

    • 2 years ago
  46. moongazer Group Title
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    is that correct? could you improve my definition of factor ?

    • 2 years ago
  47. sauravshakya Group Title
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    No u r defination is correct. And can u use this to solve this problem

    • 2 years ago
  48. moongazer Group Title
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    how I am confused with the question?

    • 2 years ago
  49. moongazer Group Title
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    I am thinking of distributing -3 to x

    • 2 years ago
  50. moongazer Group Title
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    but I can't explain why it is correct :)

    • 2 years ago
  51. sauravshakya Group Title
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    your 2 number question simply means that if u divide P(x) by (x+3) then remainder is zero. |dw:1343209619170:dw|

    • 2 years ago
  52. moongazer Group Title
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    ohh, I think it also has remainder theorem? :)

    • 2 years ago
  53. sauravshakya Group Title
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    YEAH.

    • 2 years ago
  54. sauravshakya Group Title
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    now can u

    • 2 years ago
  55. moongazer Group Title
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    |dw:1343207190855:dw|

    • 2 years ago
  56. moongazer Group Title
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    I added =0 so that the remainder will be equal to zero making (x+3) a product ?

    • 2 years ago
  57. sauravshakya Group Title
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    solve for k

    • 2 years ago
  58. moongazer Group Title
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    am I correct with my reason?

    • 2 years ago
  59. sauravshakya Group Title
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    yeah

    • 2 years ago
  60. moongazer Group Title
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    k=1/2

    • 2 years ago
  61. moongazer Group Title
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    @sauravshakya thank you very much for your help :)

    • 2 years ago
  62. sauravshakya Group Title
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    U r WELCOME. AND best of luck

    • 2 years ago
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