moongazer
  • moongazer
1.) Find a polynomial of degree that has zeros 1, -1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2 - 10kx + 6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
AT FIRST. do u know what a degree of polynomial means.
moongazer
  • moongazer
\[3x^3+(3x^2/2)−(3x/2)+(3/2)\] is this correct?
moongazer
  • moongazer
for 1.?

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More answers

anonymous
  • anonymous
simplify that.
moongazer
  • moongazer
Is my answer correct?
anonymous
  • anonymous
|dw:1343207441484:dw|
moongazer
  • moongazer
how about for no. 2 could you help me?
anonymous
  • anonymous
can u simplify this plz
anonymous
  • anonymous
I DONT THINK YOUR ANSWER IS CORRECT.
moongazer
  • moongazer
ok
anonymous
  • anonymous
FOR NUMBER 2) do u know factor theorem
moongazer
  • moongazer
could I make \[(x-1/2) -------> (2x-1)\] ????????
anonymous
  • anonymous
|dw:1343207772794:dw|
anonymous
  • anonymous
NOW do u know factor theorem? and did u get answer for 1)
moongazer
  • moongazer
\[3x^3-(3x^2/2)−3x−(3/2)\]
moongazer
  • moongazer
am I correct now?
anonymous
  • anonymous
NOPE.
anonymous
  • anonymous
BUT U R VERY CLOSE
moongazer
  • moongazer
I'll do it again :)
anonymous
  • anonymous
u just made the sign mistake
moongazer
  • moongazer
could I make (x-1/2) into (2x-1) because my teacher said there should be no fractions?
moongazer
  • moongazer
@sauravshakya
anonymous
  • anonymous
|dw:1343208282102:dw|
anonymous
  • anonymous
is the correct answer
moongazer
  • moongazer
could I make (x-1/2) into (2x-1) ??????
anonymous
  • anonymous
NOPE because|dw:1343208355724:dw|
anonymous
  • anonymous
but if |dw:1343208386811:dw|
moongazer
  • moongazer
that's what I mean for the second part
anonymous
  • anonymous
because|dw:1343208443188:dw|
moongazer
  • moongazer
isn't that it is zero so that it is possible?
moongazer
  • moongazer
|dw:1343205903760:dw|
anonymous
  • anonymous
IF it is equal to zero then yes u can because |dw:1343208534245:dw|
moongazer
  • moongazer
|dw:1343205945423:dw|
anonymous
  • anonymous
so what?
moongazer
  • moongazer
I got the correct answer :)
anonymous
  • anonymous
and what is that
moongazer
  • moongazer
it mean that there zeroes are both 1/2
moongazer
  • moongazer
so you can use either of the two?
anonymous
  • anonymous
yeah. BUT only in that case. U cannot use this in simplification.
anonymous
  • anonymous
AND NOW SHALL WE BEGIN NO. 2
moongazer
  • moongazer
yup :)
anonymous
  • anonymous
do u know factor theorem.
moongazer
  • moongazer
wait I am trying to solve 1 with (2x-1) :)
moongazer
  • moongazer
I got the same answer :)
moongazer
  • moongazer
I know factor theorem. If the remainder when dividing P(x) by D(x) is zero, then D(x) is a factor of P(x). P(x) is any polynomial D(x) is the divisor being a factor means it is included in multiplying.
moongazer
  • moongazer
is that correct? could you improve my definition of factor ?
anonymous
  • anonymous
No u r defination is correct. And can u use this to solve this problem
moongazer
  • moongazer
how I am confused with the question?
moongazer
  • moongazer
I am thinking of distributing -3 to x
moongazer
  • moongazer
but I can't explain why it is correct :)
anonymous
  • anonymous
your 2 number question simply means that if u divide P(x) by (x+3) then remainder is zero. |dw:1343209619170:dw|
moongazer
  • moongazer
ohh, I think it also has remainder theorem? :)
anonymous
  • anonymous
YEAH.
anonymous
  • anonymous
now can u
moongazer
  • moongazer
|dw:1343207190855:dw|
moongazer
  • moongazer
I added =0 so that the remainder will be equal to zero making (x+3) a product ?
anonymous
  • anonymous
solve for k
moongazer
  • moongazer
am I correct with my reason?
anonymous
  • anonymous
yeah
moongazer
  • moongazer
k=1/2
moongazer
  • moongazer
@sauravshakya thank you very much for your help :)
anonymous
  • anonymous
U r WELCOME. AND best of luck

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