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1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3.
2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6
 one year ago
 one year ago
1.) Find a polynomial of degree that has zeros 1, 1 and 1/2 and whose leading coefficient is 3. 2.) Find the value of k such that x+3 is a product of P(x) = x^2  10kx + 6
 one year ago
 one year ago

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sauravshakyaBest ResponseYou've already chosen the best response.1
AT FIRST. do u know what a degree of polynomial means.
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
\[3x^3+(3x^2/2)−(3x/2)+(3/2)\] is this correct?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
Is my answer correct?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
dw:1343207441484:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
how about for no. 2 could you help me?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
can u simplify this plz
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
I DONT THINK YOUR ANSWER IS CORRECT.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
FOR NUMBER 2) do u know factor theorem
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
could I make \[(x1/2) > (2x1)\] ????????
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
dw:1343207772794:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
NOW do u know factor theorem? and did u get answer for 1)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
\[3x^3(3x^2/2)−3x−(3/2)\]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
BUT U R VERY CLOSE
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
u just made the sign mistake
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
could I make (x1/2) into (2x1) because my teacher said there should be no fractions?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
dw:1343208282102:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
is the correct answer
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
could I make (x1/2) into (2x1) ??????
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
NOPE becausedw:1343208355724:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
but if dw:1343208386811:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
that's what I mean for the second part
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
becausedw:1343208443188:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
isn't that it is zero so that it is possible?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
dw:1343205903760:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
IF it is equal to zero then yes u can because dw:1343208534245:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
dw:1343205945423:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I got the correct answer :)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
it mean that there zeroes are both 1/2
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
so you can use either of the two?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
yeah. BUT only in that case. U cannot use this in simplification.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
AND NOW SHALL WE BEGIN NO. 2
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
do u know factor theorem.
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
wait I am trying to solve 1 with (2x1) :)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I got the same answer :)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I know factor theorem. If the remainder when dividing P(x) by D(x) is zero, then D(x) is a factor of P(x). P(x) is any polynomial D(x) is the divisor being a factor means it is included in multiplying.
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
is that correct? could you improve my definition of factor ?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
No u r defination is correct. And can u use this to solve this problem
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
how I am confused with the question?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I am thinking of distributing 3 to x
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
but I can't explain why it is correct :)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
your 2 number question simply means that if u divide P(x) by (x+3) then remainder is zero. dw:1343209619170:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
ohh, I think it also has remainder theorem? :)
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
dw:1343207190855:dw
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
I added =0 so that the remainder will be equal to zero making (x+3) a product ?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
am I correct with my reason?
 one year ago

moongazerBest ResponseYou've already chosen the best response.1
@sauravshakya thank you very much for your help :)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
U r WELCOME. AND best of luck
 one year ago
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