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do you have an answer?

no, i'm still very confused on how to even start

\[\LARGE \sqrt{63x^5} \implies \sqrt{9 \times 7 \times x^4 \times x}\]
does that help?

a little, the exponents are the things that trip me up the most though.

\[\LARGE \sqrt{x^a} \implies x^{a/2}\]

the one before that was too big for the screen lol but let me see if i can keep working this out :)

okay :D

I got |dw:1343225546659:dw|

you can also pull x^4 out of the square root to get
\[ 24 x^2 \sqrt{7x} \]

by definition:
sqrt(2*2) = sqrt(2)*sqrt(2) = 2
or, in general
sqrt(x)*sqrt(x)= x

okay! so all we did when we pulled out 4 from x^5 is divide it by two?

I got it now! :D thank you!