anonymous
  • anonymous
simplify 8√63x^5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
lgbasallote
  • lgbasallote
do you have an answer?
anonymous
  • anonymous
no, i'm still very confused on how to even start
lgbasallote
  • lgbasallote
\[\LARGE \sqrt{63x^5} \implies \sqrt{9 \times 7 \times x^4 \times x}\] does that help?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
a little, the exponents are the things that trip me up the most though.
lgbasallote
  • lgbasallote
\[\LARGE \sqrt{9 \times 7 \times x^4 \times x} \implies \sqrt 9 \times \sqrt{x^4} \times \sqrt 7 \times \sqrt x\]
lgbasallote
  • lgbasallote
\[\LARGE \sqrt{x^a} \implies x^{a/2}\]
anonymous
  • anonymous
the one before that was too big for the screen lol but let me see if i can keep working this out :)
lgbasallote
  • lgbasallote
okay :D
anonymous
  • anonymous
I got |dw:1343225546659:dw|
phi
  • phi
you can also pull x^4 out of the square root to get \[ 24 x^2 \sqrt{7x} \]
anonymous
  • anonymous
how would it be x^2 outside of the radical and inside it only be x? I need a bit of clarification, I'm not very good at math :/
phi
  • phi
by definition: sqrt(2*2) = sqrt(2)*sqrt(2) = 2 or, in general sqrt(x)*sqrt(x)= x
phi
  • phi
x^5 is short hand for x*x*x*x*x (people don't like typing it out, so they use the short hand) sqrt(x*x*x*x*x) = sqrt(x)*sqrt(x)*sqrt(x)*sqrt(x)*sqrt(x) each pair simplfies to x: x*x*sqrt(x) or, using the short hand x^2 * sqrt(x)
phi
  • phi
Of course, if you do this problem a bunch of times, you start saying things like: if the exponent is even (example: x^4) I can "pull out" x^4 , and divide the power by 2. in other words sqrt(x^4) = x^2
anonymous
  • anonymous
okay! so all we did when we pulled out 4 from x^5 is divide it by two?
phi
  • phi
the exponent 4 is divided by 2 when you pull x^4 out of a square root. if you have x^5 you write it as x^4 times x. then pull out the x^4 and leave the x inside
anonymous
  • anonymous
I got it now! :D thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.